03.12.2022

What is the Molarity of a solution prepared by dissolving 74.5 g of NaOH in water to make 1.50 L of solution? A. 1.24M
B. 40.0M
C. 49.6M
D. 1.86M

. 1

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09.07.2023, solved by verified expert
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74.5 g of NaOH is dissolved in water to 1.50L of Solution .

We have been asked to find the molarity of solution

Formula to calculate Molarity

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

First Let's find the Molar Mass of NaOH

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

Put the given value we get

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

Now calculating the molarity of given solution

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

What is the Molarity of a solution prepared by, №18010740, 03.12.2022 07:08

So, the molarity of the solution is 1.24M

Option (A) is your correct answer.

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Chemistry
Step-by-step answer
P Answered by Specialist

74.5 g of NaOH is dissolved in water to 1.50L of Solution .

We have been asked to find the molarity of solution

Formula to calculate Molarity

\\  \bullet{\boxed{\blue{\bf {molarity=   \frac{moles \: of \: solute }{volume \: of \: solution}  }}}}

First Let's find the Molar Mass of NaOH

\implies \sf \:molar \: mass \: of \: NaOH = 23 + 16 + 1 \\  \\  \implies\sf \:molar \: mass \: of \: NaOH =40g {mol}^{ - 1}

\bf \: moles \: of \: solute \:  =  \dfrac{mass}{molar \: mass}

Put the given value we get

\sf \implies \: moles \: of \: solute \:  =  \dfrac{74.5}{40}  \\  \\ \sf \implies \: moles \: of \: solute \: = 1.8625 \: mole

Now calculating the molarity of given solution

\\  \bullet{\boxed{\blue{\bf {molarity=   \frac{moles \: of \: solute }{volume \: of \: solution}  }}}}

\sf \implies \: molarity \:  =  \dfrac{1.8625}{1.50}  \\  \\  \sf \implies \: molarity \:  =1.24 \: M

So, the molarity of the solution is 1.24M

Option (A) is your correct answer.

Chemistry
Step-by-step answer
P Answered by Master
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarity * L
mol = 0.15 * 0.03 = 0.0045 mol
Answer: 0.0045 mol
Explanation: Convert 30 ml to l: 30 mL = 0.03 L
Molarity = mol/l
mol = molarit
Chemistry
Step-by-step answer
P Answered by PhD
Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.
Chemistry
Step-by-step answer
P Answered by Master

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the
Chemistry
Step-by-step answer
P Answered by PhD

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry
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P Answered by PhD

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N ×328 K

Solving:

Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry
Step-by-step answer
P Answered by PhD
15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.
Chemistry
Step-by-step answer
P Answered by PhD
Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g
Chemistry
Step-by-step answer
P Answered by PhD
Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g

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