A 35.3 g of element M is reacted with nitrogen to produce 43.5 g of compound M3N2 What is (i) the molar mass of the element and (ii) name of the element?

This problem is providing us with the mass of an unknown element which produces 43.5 g of M3N2. Thus, its name and molar mass are required and found to be 4.02 g/mol and calcium nitride after the following:

In chemistry, stoichiometry is a tool used for the calculation of masses or moles involved in chemical reactions, by the utilization of molar masses and mole ratios based on proportional factors.

In such a way, for the given reaction, one can use the formulas to write the following balanced chemical equation:

Where there is a 3:1 mole ratio of the metal to the product, which means we can use the following stoichiometric setup:

Now, by using the numbers only, one will be able to calculate x as the atomic mass of the element M in g/mol:

Which matches with the molar mass of calcium. Moreover, we find its name as calcium nitride.

Learn more about stoichiometry:

Answer:

Step-by-step explanation:

The input force is 50 N. But it will not create not any change. No mechanical advantage is observed.

Answer:

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm