4. How many times will the print statement be executed within the following nested for loops? Briefly explain how or show the math to calculate that number of iterations. for (int h = 1; h <= 12; h++) {
for (int m = 0; m <= 59; m++) {
for (int s = 0; s <= 59; s++) {
System.out.printf(“%d:%02d:%02d%n”, h, m, s);
}
}
}

Print statements are used to display outputs

The number of times the nested loop will be executed is 43200

Nested for loops are loops that are placed within another loop or loops

From the statement, we have the following loop conditions:

h = 1; h <= 12, m = 0; m <= 59 and s = 0; s <= 59

The above means that:

So, the number of times the nested loop will be executed is:

Hence, the number of times the nested loop will be executed is 43200

Read more about loops at:

The solution that would help the client pool their data together is a data integration solution. This type of solution allows for the collection and consolidation of data from various sources into a single, unified database. This can be achieved through a variety of methods, including Extract, Transform, Load (ETL) processes, data warehousing, and master data management. By implementing a data integration solution, the client will be able to access and analyze their data more efficiently, leading to better insights and informed decision-making.

The correct answer to the following question will be "Auto-encoder".

Explanation:

It is indeed a form of artificial neural net that utilizes in an unmonitored way to practice successful information coding.

A code in C++ follows:

Explanation:

#include<iostream>

using namespace std;

int calculate_area(int width, int length)

{

int area;

area=width*length;

return area;

}

int main()

{

int a,b,ar,c,d,ar1,n;

cout<<"\nEnter length of room:";

cin>>a;

cout<<"\nEnter width of room:";

cin>>b;

ar=calculate_area(a,b);

cout<<"\nArea of room:"<<ar<<" units";

cout<<"\nEnter length of mat:";

cin>>c;

cout<<"\nEnter width of mat:";

cin>>d;

ar1=calculate_area(c,d);

n=ar/ar1;

cout<<"\nNumber of mats required are:"<<n;

return 0;

}

boolean rsvp;

int selection;

String option1;

String option2;

(a) if(rsvp){

System.out.println("Attending");

} else {

System.out.println("Not attending");

}

(b) if (selection == 1){

System.out.println("Beef");

} else if (selection == 2){

System.out.println("Chicken");

} else if (selection == 3) {

System.out.println("Pasta");

} else {

System.out.println("Fish");

}

(c) switch(selection){

case 1:

if(rsvp){

option1 = "Thanks for attending. You will be served beef.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 2:

if(rsvp){

option1 = "Thanks for attending. You will be served chicken.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 3:

if(rsvp){

option1 = "Thanks for attending. You will be served pasta.";

} else{

option1 = "Sorry you can't make it";

}

break;

default:

if(rsvp){

option1 = "Thanks for attending. You will be served fish.";

} else{

option1 = "Sorry you can't make it";

}

break;

}

(d) if (option1 == option2){

System.out.println("True");

} else {

System.out.println("False");

}

Explanation:

This code snippet is written in Java.

a) Uses if statement to print "attending" if rsvp is true and "not attending" if rsvp is false.

b) Uses if-else statement to print the variety of food based on user selection. If selection is 1, it print beef. If selection is 2, it print chicken. If selection is 3, it prints pasta else it print fish for any other value of selection.

c) Uses switch statement to determine the value of selection and then uses inner if statement to assign "Thanks for attending. You will be served beef." if rsvp is true to option1. The value of beef changes depending on the value of selection. If rsvp is false, then "Sorry you can't make it." is assigned to option1.

d) Uses if statement to print true if option1 and option2 are equal else it print false.

def get_word(sentence, n):

# Only proceed if n is positive

   if n > 0:

       words = sentence.split()

# Only proceed if n is not more than the number of words

       if n <= len(words):

           return words[n-1]

   return (" ")

print(get_word("This is a lesson about lists", 4)) # Should print: lesson

print(get_word("This is a lesson about lists", -4)) # Nothing

print(get_word("Now we are cooking!", 1)) # Should print: Now

print(get_word("Now we are cooking!", 5)) # Nothing

Explanation:

Added parts are highlighted.

If n is greater than 0, split the given sentence using split method and set it to the words.

If n is not more than the number of words, return the (n-1)th index of the words. Since the index starts at 0, (n-1)th index corresponds to the nth word

I think that 3 would be the correct answer