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17.02.2022 the following question

# What are practical considerations you might encounter when you increase the moment of inertia (I) while keeping the cross-sectional area fixed?

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17.02.2022, solved by verified expert
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The answer is below

Explanation:

The practical considerations you might encounter when you increase the moment of inertia (I) while keeping the cross-sectional area fixed are:

1. Shapes of moment of inertia: Engineers should consider or know the different shapes of moment of inertia for different shape

2. Understanding the orientation of the beam: this will allow engineers to either increase or decrease the moment of inertia of a beam without increasing its cross sectional area.

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### Faq

Engineering
P Answered by Master

True, a retractable service pit cover can help other shop employees from falling into the pit while another technician is in the pit servicing a car.

Retractable service pit cover is a special cover made to cover service pit which aid inspection and repair of vehicle in an auto workshop.

Retractable service pit ensure safety of workshop technicians around service pits.Retractable service pits aid proper inspection of the beneath of the vehicleRetractable service pits enable the technician to have a close view of the vehicle in repair.The pit also serves as guide to short-eyed people or people to are not aware of the structure.In essence, the pit prevent against injury or death of workers and occupier.

In conclusion, the retractable service pit cover help other shop employees from falling into the pit even if they are aware of the structure.

Engineering
P Answered by Specialist
Measure the length of both weights, then alternately to each weight to weigh and again measure its length. The meaning of the extension is to put in the formula and find the relationship.
Engineering
P Answered by PhD

Code:

#include <iostream>

using namespace std;

int main()

{

int Car_Year;

cout<<"Please Enter the Car Model."<<endl;

cin>>Car_Year;

if (Car_Year<1967)

{

cout<<"Few safety features."<<endl;

}

else if (Car_Year>1971 && Car_Year<=1991)

{

cout<<"Probably has head rests."<<endl;

}

else if (Car_Year>1991 && Car_Year<=2000)

{

cout<<"Probably has antilock brakes."<<endl;

}

else if (Car_Year>2000)

{

cout<<"Probably has airbags."<<endl;

}

else

{

cout<<"Invalid Selection."<<endl;

}

return 0;

}

Output:

Please Enter the Car Model.

1975

Probably has head rests.

Please Enter the Car Model.

1999

Probably has antilock brakes.

Please Enter the Car Model.

2005

Probably has airbags.

Please Enter the Car Model.

1955

Few safety features.

Explanation:

We were required to implement multiple If else conditions to assign car model year with the corresponding features of the car.

The code is tested with a wide range of inputs and it returned the same results as it was asked in the question.

Engineering
P Answered by Master

"Test Phase " is the correct choice.

Explanation:

DevSecOps seems to be a community as well as experience of corporate data science which encompasses software design, regulation, including operational activities. This same main feature of DevSecOps has always been to strengthen customer achievement as well as expedition importance by computerizing, supervising as well as implementing data protection at all stages of the development including its development tools.The testing method throughout the test phase would then help make sure that the controller is designed mostly under the responsibilities forecasted. The test focuses on either the reaction times, dependability, use of resources but instead interoperability of applications.
Engineering
P Answered by Master

NTQ

Explanation:

The given sequence is

BHE : FLI : JPM

If is clear that, alphabets on first places are B, F, J. Difference between their place vales is 4.

B+4=F,F+4=J ; so alphabet on first place of next term of sequence is J+4=N.

Similarly, alphabets on second places are H, L, P. Difference between their place vales is 4.

H+4=L,L+4=P ; so alphabet on second place of next term of sequence is P+4=T.

Alphabets on third places are E, I, M. Difference between their place vales is 4.

E+4=I,I+4=M ; so alphabet on third place of next term of sequence is M+4=Q.

Therefore, the next term is NTQ.

Engineering
P Answered by PhD

The following code or the program will be used

Explanation:

dict = {}

with open(filename, 'r') as infile:

for index in range(0, len(lines) - 1, 2):

if lines[index].strip()=='':continue

count = int(lines[index].strip())

name = lines[index + 1].strip()

if count in dict.keys():

name_list = dict.get(count)

name_list.append(name)

name_list.sort()

else:

dict[count] = [name]

print(count,name)

return dict

def output_keys(dict, filename):

with open(filename,'w+') as outfile:

for key in sorted(dict.keys()):

outfile.write('{}: {}\n'.format(key,';'.join(dict.get(key

print('{}: {}\n'.format(key,';'.join(dict.get(key

def output_titles(dict, filename):

titles = []

for title in dict.values():

titles.extend(title)

with open(filename,'w+') as outfile:

for title in sorted(titles):

outfile.write('{}\n'.format(title))

print(title)

def main():

filename = input('Enter input file name: ')

if dict is None:

print('Error: Invalid file name provided: {}'.format(filename))

return

print(dict)

output_filename_1 ='output_keys.txt'

output_filename_2 ='output_titles.txt'

output_keys(dict,output_filename_1)

output_titles(dict,output_filename_2)

main()

Engineering
P Answered by PhD

Energy equation from this week’s notes, your answer from #5, and Plank’s constant (6.63E-34) to find the approximate energy of this photon

Explanation:

1.The amount of energy in those photons is calculated by this equation, E = hf, where E is the energy of the photon in Joules; h is Planck's constant, which is always 6.63 * 10^-34 Joule seconds; and f is the frequency of the light in hertz

2.The first is Planck's equation, which was proposed by Max Planck to describe how energy is transferred in quanta or packets. Planck's equation makes it possible to understand blackbody radiation and the photoelectric effect. The equation is:

E = hν

where

E = energy

h = Planck's constant = 6.626 x 10-34 J·s

ν = frequency

Engineering
P Answered by PhD

x=float(input("Enter a number: "))

sub=(x-int(x))

print(sub)

Explanation:

Got it Right

Engineering
P Answered by Specialist

B ). When cleaning a vessel, use regular  household detergents and cleaners.

Explanation:

Boat cleaning or vessel cleaning is a tedious job. It takes a lot of hard work to clean a vessel. We have to be careful while maintaining the vessel.

The products that we use to clean and maintain the vessels needs to chosen carefully. Many boat cleaning products have adverse effects on the marine life and aquatic animals. it also tends to pollute the water bodies.

These products may be corrosive in nature, toxic or poisonous.

So we must use the regular household detergents and cleaners to clean our vessels. The regular detergents do not cause any harm to the nature and the water bodies.

We can use phosphate free no detergent soaps which may include citrus based soap or vegetable based soaps.

Therefore, while cleaning or maintaining vessels , use the regular household detergents and cleaners.

Thus option (B) is correct.

Engineering