06.09.2021


Answer the following questions shown in the picture

. 1

Faq

Mathematics
Step-by-step answer
P Answered by PhD

The problem which is best modeled by a division expression is,

A. only Julia's.

Step-by-step explanation:

The problem which is best modeled by a division expression is,

A. only Julia's.

Answer to Julia's problem:-

The number of \frac {1}{4} quart servings which the cooler does hold is given by,

\frac {8}{\frac {1}{4}}

= 32

Answer to Tanveer's problem:-\

The number of quarts of juice needed to give 8 people each \frac {1}{4} quart serving of juice is given by,

(8 \times \frac {1}{4})

= 2

Mathematics
Step-by-step answer
P Answered by PhD

The problem which is best modeled by a division expression is,

A. only Julia's.

Step-by-step explanation:

The problem which is best modeled by a division expression is,

A. only Julia's.

Answer to Julia's problem:-

The number of \frac {1}{4} quart servings which the cooler does hold is given by,

\frac {8}{\frac {1}{4}}

= 32

Answer to Tanveer's problem:-\

The number of quarts of juice needed to give 8 people each \frac {1}{4} quart serving of juice is given by,

(8 \times \frac {1}{4})

= 2

Mathematics
Step-by-step answer
P Answered by Master

For a function to be continuous at an x-value of -3 you need to make sure two things line up:

First, we need to show that the limit from the left equals the limit from the right.

     \lim_{x \to -3^{-}} f(x) =  \lim_{x \to -3^{+}} f(x)

Second, we need to show that this limit equals the functions value.

    \lim_{x \to -3} f(x) = f(-3)

The left hand limit involves the first piece, f(x) = x^2 - 9:

    \begin{aligned} \lim_{x \to -3^{-}} f(x) &=  \lim_{x \to -3^{-}} (x^2-9)\\[0.5em]&=   (-3)^2-9\\[0.5em]&=   0\endaligned}

The right hand limit invovles the second piece, f(x) = 0:

    \begin{aligned} \lim_{x \to -3^{+}} f(x) &=  \lim_{x \to -3^{+}} (0)\\[0.5em]&=   0\endaligned}

Since the two one-sided limits do match, we can just say:

    \lim_{x \to -3} f(x)  = 0  

(no one-sided pieces needed now)

So that was step #1, to make sure the limit exists.  Next we need to make sure the limit is headed to the same place where the functions.  Since we're using x=-3, we'll use the top piece of the function because x=-3 fits with that piece ( x ≤ -3 ).

    f(-3) = (-3)^2-9 = 0

From this, we know that \lim_{x \to -3} f(x)  = f(-3), so the function is continuous at -3.  (We also know parabolas and lines are continuous in general, so we only needed to check where the two pieces came together at x = -3.)

Mathematics
Step-by-step answer
P Answered by PhD

Step-by-step explanation:

A Pair of skew lines → GH and FE

A Pair of perpendicular lines → AG and GH

A Pair of parallel lines →AG and BH

A Pair of intersecting planes → AGH and EGH

Planes AGH and EGH are intersecting each other at line GH.

Mathematics
Step-by-step answer
P Answered by PhD

1. 42.95

2. 8.8 meters; -14 meters

3. -53; 780

Step-by-step explanation:

1. subtract 1985 from 2013, you get 28

plug in 28 to the equation and you get 42.95

2. plug in the values of t

-4.9 (2^2) + 1.7 (2) + 25 = 8.8

-4.9 (3^2) + 1.7 (3) + 25 = -14

3. plug in your values again

5^3 - 6 (5^2) - 8 (5) + 12 = -53

12^3 - 6 (12^2) - 8 (12) + 12 = 780

Mathematics
Step-by-step answer
P Answered by Specialist

1. Is adding and subtracting 8

2. Is going up by 1/3

3. Is going up by 2/10

Step-by-step explanation:

I don't understand the other ones. But I hope what I gave you helps

Mathematics
Step-by-step answer
P Answered by PhD
Problem 27)

The domain is {-4,-2,0,2,4}

Plug in each of those values, one at a time, for x

Plug in x = -4
y = (-1/2)*x + 1
y = (-1/2)*(-4) + 1
y = 2 + 1
y = 3
So y = 3 is part of the range
------------------
Plug in x = -2
y = (-1/2)*x + 1
y = (-1/2)*(-2) + 1
y = 1 + 1
y = 2
So y = 2 is part of the range
------------------
Plug in x = 0
y = (-1/2)*x + 1
y = (-1/2)*(0) + 1
y = -0 + 1
y = 1
So y = 1 is part of the range
------------------
Plug in x = 2
y = (-1/2)*x + 1
y = (-1/2)*(2) + 1
y = -1 + 1
y = 0
So y = 0 is part of the range
------------------
Plug in x = 4
y = (-1/2)*x + 1
y = (-1/2)*(4) + 1
y = -2 + 1
y = -1
So y = -1 is part of the range
------------------

The range is the set {3, 2, 1, 0, -1}

======================================================================
Problem 28)

Since the equation y = (-1/2)*x + 1 is in the form y = m*x+b, this means we have a linear equation. 

So we only need two points to plot this line

If x = 0, then y = 1 as shown in problem 27. So the point (0,1) is on the line. This is the y intercept.
If x = 2, then y = 0 as shown in problem 27. So the point (2,0) is on the line. This is the x intercept

See the attached image to see the graph of the equation.

======================================================================
Problem 29)

To find the x intercept, plug in y = 0. Then solve for x
7x - 3y = 21
7x - 3(0) = 21
7x - 0 = 21
7x = 21
7x/7 = 21/7
x = 3

The x intercept is 3 meaning that the point (3,0) is on the line. 
This is where the graph crosses the x axis.

--------------------------------------

To find the y intercept, plug in x = 0. Then solve for y
7x - 3y = 21
7(0) - 3y = 21
0 - 3y = 21
-3y = 21
-3y/(-3) = 21/(-3)
y = -7

The y intercept is -7 meaning the point (0,-7) is on the line. This is where the graph crosses the y axis.

======================================================================
Problem 30)

The equation y = -3x+5 is in the form y = mx+b
m = -3 is the slope
b = 5 is the y intercept

You can write the y intercept as an ordered pair (0,5)
This is where the graph crosses the y axis

The slope of -3 means we go down 3 each time we move over to the right 1
slope = rise/run = -3/1
rise = -3
run = 1

Solve all questions shown with work. no tricks or anything i need this for my final .
Mathematics
Step-by-step answer
P Answered by Master

27. x=7/20; 28. m= 3.7; 29. a= 5.8

30. x= 6; 31.x= 46

Step-by-step explanation:

27.

x +  \frac{2}{3}  =  \frac{9}{ 10}

you are going to carry the 2/3 over the equal sign. This will make the 2/3 negative so...

x =  \frac{9}{10}  -  \frac{2}{3}

now calculate it by finding the LCM of 10 and 3 ....this will be 30....you can just multiply the 10 and 3

now

30 into 10 goes 3 times....you will multiply this 3 with the 9 to get 27

30 into 3 goes 10 times...you will multiply this 10 with the 2 to get 20

x =    \frac{27 - 20}{30}

x =  \frac{7}{30}

Hopefully you understand

28.

1.2 = m - 2.5

1.2 + 2.5 = m

carry the 2.5 over the equal sign to get the m by itself...this is because you are trying to find m

when the negative number goes over the equal sign it will become positive...this is why you add it to the 1.2

m= 3.7

you can do the other on your own

the error in 30 is that the 7 should not be added to the 13 but subtracted

..this is because when you carry the positive number over the equal sign it will become negative..hence you subtract it

x  + 7 = 13

x = 13 - 7

x = 6

and for 31...the 12 should not be subtracted but added since when it goes over the equal sign it will become positive.

34= y - 12

34 + 12 = y

y = 46

Mathematics
Step-by-step answer
P Answered by Specialist

For a function to be continuous at an x-value of -3 you need to make sure two things line up:

First, we need to show that the limit from the left equals the limit from the right.

     \lim_{x \to -3^{-}} f(x) =  \lim_{x \to -3^{+}} f(x)

Second, we need to show that this limit equals the functions value.

    \lim_{x \to -3} f(x) = f(-3)

The left hand limit involves the first piece, f(x) = x^2 - 9:

    \begin{aligned} \lim_{x \to -3^{-}} f(x) &=  \lim_{x \to -3^{-}} (x^2-9)\\[0.5em]&=   (-3)^2-9\\[0.5em]&=   0\endaligned}

The right hand limit invovles the second piece, f(x) = 0:

    \begin{aligned} \lim_{x \to -3^{+}} f(x) &=  \lim_{x \to -3^{+}} (0)\\[0.5em]&=   0\endaligned}

Since the two one-sided limits do match, we can just say:

    \lim_{x \to -3} f(x)  = 0  

(no one-sided pieces needed now)

So that was step #1, to make sure the limit exists.  Next we need to make sure the limit is headed to the same place where the functions.  Since we're using x=-3, we'll use the top piece of the function because x=-3 fits with that piece ( x ≤ -3 ).

    f(-3) = (-3)^2-9 = 0

From this, we know that \lim_{x \to -3} f(x)  = f(-3), so the function is continuous at -3.  (We also know parabolas and lines are continuous in general, so we only needed to check where the two pieces came together at x = -3.)

History
Step-by-step answer
P Answered by Master

**FOREWARNING**

Okay, so I have not done this assignment or any type of work like this, so I am not guaranteeing that my response will be correct. But I tried my best and answer thoughtfully, so hopefully this is a good enough answer. :)

**Actual Response**

Robert Lindneux created this painting to show the struggle the Native Americans had to deal with as they were forced to leave their homelands because of Andrew Jackson's Indian Removal Act. It was meant to express the crowded migration they had to deal with, and the unsanitary, non-idealistic conditions as they headed away from their heritage and homes. If you were to look closely and carefully at the painting, you can tell that Lindneux had exaggerated and purposefully made the faces on the characters in the painting sorrowful and depressed. The conditions were exaggerated as well, notice the people having to walk and carry sacks on their backs, and people crouching over in their cloaks avoiding the sand and dust. The environment is exaggerated as well and in the landscape you can see dark, stormy clouds, meaning a bad/ dark/ depressing mood. Along with a dusty, windy ground that is surely irritating the Natives' eyes.

Hope this helps. Have a good day and good luck! :)

Your friend, Pengoon

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