Unscramble these letters d,r,a,l,a,o,i,r

Not very easy.

Make it easier and I will unscramble them.

-Ɽ3₮Ɽ0 Ⱬ3Ɽ0

Here is your answer It's these

Here is your answer It's these

Answers are mentioned along with explanations/

Explanation:

1. We are given D = 5R

where D = no. of diamonds and R = no. of rubies

a. In words, Number of diamonds = 5 times no. of rubies

In letters D = 5R

b. Given R = 4, so D = 5 x R = 5x 4

D = 20

c.  Given R = 10 , so D = 5 x R = 5x 10

D = 50

d. Given D = 15 , D = 5R so , R = D/5 = 15/5 = 3

R = 3

e. R =  because D = 5R

2. Given A = B + C

a. B = 5 , C = 2 => A= 5+2 => A= 7

b. B = A - C from above equation and given A = 10 , C = 2 , B= 10 - 2

B = 8

c.  two values of B and C for A to be 7

B = 4 C = 3 and vice versa as 4+3 = 7

d. B = A - C by moving C on the RHS thus changing its prefix sign.

3. Given A = 3x and B = 5x+1

a. B goes up faster because it is 5 times x plus 1 where A is just 3 times x

b. if x = 0, A = 3x = 3x0 = > A = 0

c. if x =1 , B = 5x+1 = 5x1 +1 = 5+1 => B = 6

4. Given A = 2x and B = x2 where x2 means x*x so,

a. if x=1 , A = 2*1 = 2 and B = 1*1 = 1

b. if x = 3, A = 3*1 = 3 and B = 3*3 = 9

5. Given D =2R

a. given R = 8 , D = 2*8 => D=16

b. given R =3 then D = 2*3 => D = 6

c. D= 20 given, R = D/2 = 20/2 => R = 10

d. D = 100 so R = D/2 = 100/2 => R =50

e. R = or D/2

6. Given C = π D and π  = 3.14

a. if D = 20, C = 3.14*20 => C = 62.8 centimeters

b. if D = 10, C = 3.14*10 => C = 31.4 inches

c. Given C = 18, D = C/31.4 = 18/3.14 => D = 5.732 inches

7. Given S = D/T

a. S = 12/3 = 4 feet/seconds

b. S = 100/5 = 20 miles/seconds

c. For S = 4feet per second , D = 8 ft and T = 2 seconds as S = D/T

Answers are mentioned along with explanations/

Explanation:

1. We are given D = 5R

where D = no. of diamonds and R = no. of rubies

a. In words, Number of diamonds = 5 times no. of rubies

In letters D = 5R

b. Given R = 4, so D = 5 x R = 5x 4

D = 20

c.  Given R = 10 , so D = 5 x R = 5x 10

D = 50

d. Given D = 15 , D = 5R so , R = D/5 = 15/5 = 3

R = 3

e. R =  because D = 5R

2. Given A = B + C

a. B = 5 , C = 2 => A= 5+2 => A= 7

b. B = A - C from above equation and given A = 10 , C = 2 , B= 10 - 2

B = 8

c.  two values of B and C for A to be 7

B = 4 C = 3 and vice versa as 4+3 = 7

d. B = A - C by moving C on the RHS thus changing its prefix sign.

3. Given A = 3x and B = 5x+1

a. B goes up faster because it is 5 times x plus 1 where A is just 3 times x

b. if x = 0, A = 3x = 3x0 = > A = 0

c. if x =1 , B = 5x+1 = 5x1 +1 = 5+1 => B = 6

4. Given A = 2x and B = x2 where x2 means x*x so,

a. if x=1 , A = 2*1 = 2 and B = 1*1 = 1

b. if x = 3, A = 3*1 = 3 and B = 3*3 = 9

5. Given D =2R

a. given R = 8 , D = 2*8 => D=16

b. given R =3 then D = 2*3 => D = 6

c. D= 20 given, R = D/2 = 20/2 => R = 10

d. D = 100 so R = D/2 = 100/2 => R =50

e. R = or D/2

6. Given C = π D and π  = 3.14

a. if D = 20, C = 3.14*20 => C = 62.8 centimeters

b. if D = 10, C = 3.14*10 => C = 31.4 inches

c. Given C = 18, D = C/31.4 = 18/3.14 => D = 5.732 inches

7. Given S = D/T

a. S = 12/3 = 4 feet/seconds

b. S = 100/5 = 20 miles/seconds

c. For S = 4feet per second , D = 8 ft and T = 2 seconds as S = D/T

B. Curious and Eager

Explanation:

I got it right on edgenuity.

Good luck! :)

P.E.T

Explanation:

Stud is a short form of stud wall which are typically vertical framing members in a wall of a building. Wall studs are available in standard lengths but since the height of ceiling vary, sometimes one has to cut the stud walls on site to fit. Therefore, there are pre-cut studs which are more efficient  in implementation. These are usually referred as Precision-End Trimmed studs, (P.E.T). Therefore, stud walls which are cut to exact length at the mill for modern construction are designated by letters P.E.T

P.E.T

Explanation:

Stud is a short form of stud wall which are typically vertical framing members in a wall of a building. Wall studs are available in standard lengths but since the height of ceiling vary, sometimes one has to cut the stud walls on site to fit. Therefore, there are pre-cut studs which are more efficient  in implementation. These are usually referred as Precision-End Trimmed studs, (P.E.T). Therefore, stud walls which are cut to exact length at the mill for modern construction are designated by letters P.E.T