Mathematics : asked on Will1119
 02.01.2020

X^2-4x-12 square meters and a length of x+2

. 5

Faq

Mathematics
Step-by-step answer
P Answered by PhD
The width is x-6.

Step-by-step explanation:

Givens:

Area of the rectangle x^2-4x-12 square meters.The length is x+2

We know that, the are of a rectangle is:

A=(length)(width)

x^2-4x-12=(x+2)w

\frac{x^2-4x-12}{x+2}=w

Now, to solve this, we factorize the numerator.

x^2-4x-12=(x-a)(x+b)

So, we need to find two number which product is 12 and difference is 4.

x^2-4x-12=(x-6)(x+2)

Now, we replace this result in the fraction expression:

\frac{x^2-4x-12}{x+2}=w\\w=\frac{(x-6)(x+2)}{(x+2)}\\w=x-6

Therefore, the width is x-6.

Mathematics
Step-by-step answer
P Answered by PhD
The width is x-6.

Step-by-step explanation:

Givens:

Area of the rectangle x^2-4x-12 square meters.The length is x+2

We know that, the are of a rectangle is:

A=(length)(width)

x^2-4x-12=(x+2)w

\frac{x^2-4x-12}{x+2}=w

Now, to solve this, we factorize the numerator.

x^2-4x-12=(x-a)(x+b)

So, we need to find two number which product is 12 and difference is 4.

x^2-4x-12=(x-6)(x+2)

Now, we replace this result in the fraction expression:

\frac{x^2-4x-12}{x+2}=w\\w=\frac{(x-6)(x+2)}{(x+2)}\\w=x-6

Therefore, the width is x-6.

Mathematics
Step-by-step answer
P Answered by PhD

Width = \frac{c^2 - 4x - 12  }{x+2}

Step-by-step explanation:

All we have to do is to use the method of changing the subject. First we know that length * width is equal to area.

Area = length * width

We have the area and the length but we don't have the width. So we substitute the values we have int the equation and make the width (w) the subject.

(c^2 - 4x - 12) = (x + 2) * w

(c^2 - 4x - 12) = w(x +2)

Divide both sides by (x+2) so w can stand alone.

\frac{c^2 - 4x - 12}{x+2} = \frac{w(x+2)}{x+2}

w = \frac{c^2 - 4x - 12  }{x+2}

Mathematics
Step-by-step answer
P Answered by PhD

Width = \frac{c^2 - 4x - 12  }{x+2}

Step-by-step explanation:

All we have to do is to use the method of changing the subject. First we know that length * width is equal to area.

Area = length * width

We have the area and the length but we don't have the width. So we substitute the values we have int the equation and make the width (w) the subject.

(c^2 - 4x - 12) = (x + 2) * w

(c^2 - 4x - 12) = w(x +2)

Divide both sides by (x+2) so w can stand alone.

\frac{c^2 - 4x - 12}{x+2} = \frac{w(x+2)}{x+2}

w = \frac{c^2 - 4x - 12  }{x+2}

Mathematics
Step-by-step answer
P Answered by PhD

Width = x-6 metres

Step-by-step explanation:

The formula for the area of a rectangle is represented by Length (l) × Width (w).

If the area is x^2-4x -12, which is an algebraic expression, The best way to find its length and breadth which would be a product of themselves is by FACTORIZATION.

To factorize x^2-4x -12, we say:

×^2 = a, -4x = b, -12 = c

Product: a×c; -12 × x^2= -12x^2

Sum: b; -4x derived by saying (-6x+2x)

Note that the expression of the sum (-6x+2x) must be able to be multiplied to give product (-12x^2).

Hence, we rewrite our algebraic expression using the sum expression.

x2 - 6x + 2x - 12

We then factorize by using a common factor (x and 2)

x( x - 6) + 2 (x - 6)

(x+2) (x-6)

Thus, the factors are x+2 and x-6

This means that (x+2) and (x-6) will be multiplied to give x^2-4x-12. Therefore, if x+2 metres is the Length, x-6 metres is the width.

Mathematics
Step-by-step answer
P Answered by PhD

Width = x-6 metres

Step-by-step explanation:

The formula for the area of a rectangle is represented by Length (l) × Width (w).

If the area is x^2-4x -12, which is an algebraic expression, The best way to find its length and breadth which would be a product of themselves is by FACTORIZATION.

To factorize x^2-4x -12, we say:

×^2 = a, -4x = b, -12 = c

Product: a×c; -12 × x^2= -12x^2

Sum: b; -4x derived by saying (-6x+2x)

Note that the expression of the sum (-6x+2x) must be able to be multiplied to give product (-12x^2).

Hence, we rewrite our algebraic expression using the sum expression.

x2 - 6x + 2x - 12

We then factorize by using a common factor (x and 2)

x( x - 6) + 2 (x - 6)

(x+2) (x-6)

Thus, the factors are x+2 and x-6

This means that (x+2) and (x-6) will be multiplied to give x^2-4x-12. Therefore, if x+2 metres is the Length, x-6 metres is the width.

Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

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