If paul is older than bill and fred is younger than bill, then bill’s age is between paul’s and fred’s.
Write the given statement.

Explanation:

It is given than Paul is older than Bill.

Let age of Bill= x years, as x is a  natural number.

Then, age of Paul = (x + a) Years, where a is any natural number.

And, Fred is younger than Bill.

So, age of Fred= x - k, where k is any natural number.

So, if we arrange the ages of Fred, Bill and Paul, their ages would be

Fred < Bill < Paul

x-k < x < x+a

Hence, we can say that , Paul is eldest, and Fred is smallest member between  three.

Explanation:

It is given than Paul is older than Bill.

Let age of Bill= x years, as x is a  natural number.

Then, age of Paul = (x + a) Years, where a is any natural number.

And, Fred is younger than Bill.

So, age of Fred= x - k, where k is any natural number.

So, if we arrange the ages of Fred, Bill and Paul, their ages would be

Fred < Bill < Paul

x-k < x < x+a

Hence, we can say that , Paul is eldest, and Fred is smallest member between  three.

I just saw that my answer to this was removed because is removing some content to make room for more learning.

Since my answer seemed to help a lot of people, i'm reposting it!

Here's my Paul is the oldest, then bill, and Fred is the youngest.

The total nom of  code that can be used is equal to 5+3 = 8

The answer is in the image 

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg