Mathematics : asked on franky2871

20.10.2020

Consider squares ABCD and EFGH. Which of the following is true?

22

Step-by-step answer

09.02.2022, solved by verified expert

Bhaskar Singh Bora

Mathematics, Physics. Q&A Expert

24 118 answers

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Square EFGH has greater sides than that of square ABCD.

Through dilation size of an object can be changed: enlarge or reduce.

Square EFGH can be obtained from square ABCD using only dilation

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Mathematics

Consider squares ABCD and EFGH. Which of the following is true? Square EFGH can be obtained from square ABCD using only reflection. Square EFGH can be obtained from square ABCD using only dilation. Square EFGH cannot be obtained from square ABCD. Square EFGH can be obtained from square ABCD using only translation.

Step-by-step answer

P Answered by PhD

3

I can't answer this because there is no attachment. I do not see a photo.

Step-by-step explanation:

It is not possible to do this without any other info such as the location of the points.

Mathematics

Consider squares ABCD and EFGH. Which of the following is true? Square EFGH can be obtained from square ABCD using only reflection. Square EFGH can be obtained from square ABCD using only dilation. Square EFGH cannot be obtained from square ABCD. Square EFGH can be obtained from square ABCD using only translation.

Step-by-step answer

P Answered by PhD

3

I can't answer this because there is no attachment. I do not see a photo.

Step-by-step explanation:

It is not possible to do this without any other info such as the location of the points.

Mathematics

ABCD, EFGH, and HIJK are squares. AABCD = 400 cm2, O is the center of the circle, O ∈ FE , FG and BC tangent to the circle (see the picture on the right). Find the length of AM .

Step-by-step answer

P Answered by PhD

40/3 cm

Step-by-step explanation:

FE : DC

1 : 3

Since area ABCD = 400

s² = 400

s = 20

FE = ⅓(20) = 20/3 cm

AM = DC - FE

AM = 20 - 20/3 = 40/3

Mathematics

ABCD, EFGH, and HIJK are squares. AABCD = 400 cm2, O is the center of the circle, O ∈ FE , FG and BC tangent to the circle (see the picture on the right). Find the area of the square HIJK.

Step-by-step answer

P Answered by PhD

400/81 cm²

Step-by-step explanation:

FE : DC

1 : 3

Since area ABCD = 400

s² = 400

s = 20

FE = ⅓(20) = 20/3 cm

IH : FE

1 : 3

IH = ⅓(20/3) = 20/9 cm

Area of HIJK:

(20/9)² = 400/81 cm²

Mathematics

ABCD, EFGH, and HIJK are squares. AABCD = 400 cm2, O is the center of the circle, O ∈ FE , FG and BC tangent to the circle (see the picture on the right). Find the area of the square HIJK.

Step-by-step answer

P Answered by PhD

400/81 cm²

Step-by-step explanation:

FE : DC

1 : 3

Since area ABCD = 400

s² = 400

s = 20

FE = ⅓(20) = 20/3 cm

IH : FE

1 : 3

IH = ⅓(20/3) = 20/9 cm

Area of HIJK:

(20/9)² = 400/81 cm²

Mathematics

Geometry question: abcd and efgh are squares. if jh = 4 cm and jc = 9 cm, then what is the area of the shaded region?

Step-by-step answer

P Answered by PhD

18

Hello!

First you have to find the area of the bigger square

When it goes from the center to a corner you multiply the value by 2 to find one side

9 * 2 =18

Now you find the area

18 * 18 = 324

Now we find the area of the smaller region

4 * 2 = 8

Find the area

8 * 8 = 64

Now we subtract these

324 - 64 = 260

The answer is 260

Hope this helps!

Mathematics

Geometry ! abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Step-by-step answer

P Answered by Master

4

I have the same problem. if i find the answer i will give it to you

Mathematics

Geometry question: abcd and efgh are squares. if jh = 4 cm and jc = 9 cm, then what is the area of the shaded region?

Step-by-step answer

P Answered by PhD

18

Hello!

First you have to find the area of the bigger square

When it goes from the center to a corner you multiply the value by 2 to find one side

9 * 2 =18

Now you find the area

18 * 18 = 324

Now we find the area of the smaller region

4 * 2 = 8

Find the area

8 * 8 = 64

Now we subtract these

324 - 64 = 260

The answer is 260

Hope this helps!

Mathematics

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Step-by-step answer

P Answered by Master

14

The squares are shown in the attached picture.

As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.

In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).

The area of a square know the diagonal is given by the formula:
A = d² ÷ 2

A(ABCD) = (2×JC)² ÷ 2
= (2×9)² ÷ 2
= 162 cm²

A(EFGH) = (2×JH)² ÷ 2
   = (2×4)² ÷ 2
   = 32 cm²

Therefore:
A = A(ABCD) - A(EFGH)
   = 162 - 32
   = 130 cm²

The area of the shaded region is 130 cm².

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Mathematics

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Step-by-step answer

P Answered by Specialist

14

The squares are shown in the attached picture.

As you can see, JC is half the diagonal of ABCD and JH is half the diagonal of EFGH.

In order to find the area of the shaded figure, we need to subtract the area of the white square (EFGH) from the area of the big square (ABCD).

The area of a square know the diagonal is given by the formula:
A = d² ÷ 2

A(ABCD) = (2×JC)² ÷ 2
= (2×9)² ÷ 2
= 162 cm²

A(EFGH) = (2×JH)² ÷ 2
   = (2×4)² ÷ 2
   = 32 cm²

Therefore:
A = A(ABCD) - A(EFGH)
   = 162 - 32
   = 130 cm²

The area of the shaded region is 130 cm².

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

Abcd and efgh are squares. if jh= 4cm and jc=9cm, then what is the area of the shaded region?

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