Mathematics: 6.51 divided by 3 25.64 divided by 15 12 divided by 2.436

Note - there is an error in 3rd part it should be 2.436 divided by 12. To avoid such confusion, please...

6.51 divided by 3 25.64 divided by 15 12 divided, №15231657, 07.05.2020 19:05

Computers and Technology

You want to calculate a bonus if the sold price was at least equal to the listing price, and if the house sold within 30 days after being listed. In cell L12, insert an IF function with a nested AND function to calculate a bonus. The AND function should ensure both conditions are met: Sold Price divided by the Listing Price is greater than or equal to 100% (cell L7) and the Days on Market are less than or equal to 30 (cell L8). If both conditions are met, the bonus is $1,000 (cell L9). Otherwise, the bonus is $0. Use mixed cell references to the

Step-by-step answer

P Answered by Specialist

Following are the solution to the given question:

Explanation:

Please find the following Excel form for calculating the bonus as required. Please ensure the equation is duplicated even so, with the sign "=." It is possible to insert this formula into cell L12. Then cut/paste the cell into other L12:L39 cells.

$=IF(AND(G12/F12 \geq \$L \$7,J12 \leq \$L\$8)=TRUE,\$L\$9,0)$

The mixed microbial reference here is used in L7, L8, and L9 so these cell references are not moved whenever the formula is copied to L12:L39.

Please verify that whenever the copy has also been copied, the cell formula appears beneath in each cell.

It must be as below in L12.

$=IF(AND(G12/F12 \geq \$L\$7,J12\leq \$L\$8)=TRUE,\$L\$9,0)$

It must be as follows in L13.

$=IF(AND(G13/F13\geq \$L\$7,J13\leq \$L\$8)=TRUE,\$L\$9,0)$

and so on.

Computers and Technology

You want to calculate a bonus if the sold price was at least equal to the listing price, and if the house sold within 30 days after being listed. In cell L12, insert an IF function with a nested AND function to calculate a bonus. The AND function should ensure both conditions are met: Sold Price divided by the Listing Price is greater than or equal to 100% (cell L7) and the Days on Market are less than or equal to 30 (cell L8). If both conditions are met, the bonus is $1,000 (cell L9). Otherwise, the bonus is $0. Use mixed cell references to the

Step-by-step answer

P Answered by Master

Following are the solution to the given question:

Explanation:

Please find the following Excel form for calculating the bonus as required. Please ensure the equation is duplicated even so, with the sign "=." It is possible to insert this formula into cell L12. Then cut/paste the cell into other L12:L39 cells.

$=IF(AND(G12/F12 \geq \$L \$7,J12 \leq \$L\$8)=TRUE,\$L\$9,0)$

The mixed microbial reference here is used in L7, L8, and L9 so these cell references are not moved whenever the formula is copied to L12:L39.

Please verify that whenever the copy has also been copied, the cell formula appears beneath in each cell.

It must be as below in L12.

$=IF(AND(G12/F12 \geq \$L\$7,J12\leq \$L\$8)=TRUE,\$L\$9,0)$

It must be as follows in L13.

$=IF(AND(G13/F13\geq \$L\$7,J13\leq \$L\$8)=TRUE,\$L\$9,0)$

and so on.

Mathematics

7.06 1. find the first six terms of the sequence. a1 = -7, an = 4 • an-1 a) -7, -28, -112, -448, -1792, -7168 b) -28, -112, -448, -1792, -7168, -28,672 c) -7, -28, -24, -20, -16, -12 d) 0, 4, -28, -24, -20, -16 2. find an equation for the nth term of the arithmetic sequence. -13, -8, -3, 2, an = -13 x 5(n - 1) an = -13 + 5(n - 1) an = -13 + 5(n + 2) an = -13 + 5(n + 1) 3. find an equation for the nth term of the arithmetic sequence. a15 = -53, a16 = -5 a) an = -725 - 48(n - 1) b) an = -725 + 48(n + 1) c) an = -725 + 48(n - 1) d) an = -725 - 48(n

Step-by-step answer

P Answered by PhD

21

1. A. According to the expression a_n=4*a_n-1, each term after a1 is four times the previous term. The first term is -7 as given, 2nd term should be -7*4=-28, 3rd term is -28*4=-112, ... A is the correct answer.

2. B. The sequence is -13, -8, -3, 2... It's obvious that each term is equal to the previous term plus 5. This is an arithmetic sequence with initial term -13 and common difference 5. We know a1=-13, so a_n=-13+5*(n-1). The answer is B.

3. A. We are given a15=-53, a16=-5. The common difference of the arithmetic sequence is -5-(-53)=48. The formula for a_n term is a1+48*(n-1). We know that a15=-13; plug in n=15, a15=-53=a1+48*(15-1), a1=-725. So a_n=-725+48*(n-1).

4. Diverge. We are given a few terms, 11, 44, 176, 704... Observe that each term is four times the previous one. 11*4=44, 44*4=176, 176*4=704... This is a geometric series with common ratio>1. You can keep multiplying by 4 and the series goes to infinity, so it diverges.

5. D. We have -4, -16, -64, -256... Same as above, each term is four times the previous one. The initial term is a1=-4. The common ratio d=4. So a_n=a1*d^(n-1)=-4*4^(n-1)=-4^n. (D).

6. The answer is A. a2=-2, a5=16. Suppose the common ratio is D. a_n=a1*d^(n-1). a2=a1*d; a5=a1*d^4. Plug in a2 and a5: -2=a1*d, 16=a1*d^4. 16/-2=d^3=-8, d=-2, a1=1. So a_n=1*(-2)^(n-1).

7. B. We are given the sequence 4, -24, 144,... Each term is -6 times the previous one. The first term a0=4, the n^th term a_(n-1) is a1*d^n=4*(-6)^n. To express the sum, we simply have to use the sigma notation and sum 4*(-6)^n from n=0 to infinity. The answer is B.

8. D. We are given -3 + 6 + 15 + 24... 132. Each term is equal to the previous one plus 9. First term a0=-3, n^th term a_n-1 is -3+9*n. The last term is 132. 132 =-3+9n, n=15. So we have to sum -3+9n from n=0 to n=15.

9. B. 343 + 512 + 729 + 1000+... 343=7^3, 512=8^3, 729=9^3, 1000=10^3. This is a sequence of perfect cubes. Therefore, the sum is n^3 from n=7 to infinity. (The initial term is 343=7^3).

10. B. We are given 3, 5, 7, 9, ... 21. The common difference is 2. There are (21-3)/2+1=10 terms. The initial term a1=3, and last term is a10=21. The sum is (a1+a10)*10/2=(3+21)*10/2=120.

11. C. 4/3, 16/3, 64/3, 256/3, 1024/3. Each term is four times the previous one. This is a geometric series with initial term a1=4/3 and common ratio r=4. 1024/3 is the 5th term of the sequence. So sum=a1*(1-r^n)/(1-r)=4/3*(1-4^5)/(1-4)=-4/9*-1023=1364/3.

12. B. 10,12,14,... This is an arithmetic sequence. a1=10, and common difference d=2. There are 20 terms (20 rows). a20=a1+d*(n-1)=10+2*(20-1)=48. So the sum S=(a1+an)*n/2=(10+48)*20/2=580.

13. 10 + 20 + 30 + ... + 10n = 5n(n + 1). When n=1, this expression is true, since 10=5*1*(1+1). Suppose when n=k, this statement is true, then when n=k+1, the left side is 10+...+10n+10(n+1), the right side is 5(n+1)(n+2). The left side adds 10(n+1) compared to the previous one. The right side adds 5(n+1)(n+2)-5n(n+1)=5(n+1)(n+2-n)=10(n+1). So the statement holds true.

14. The height at week 0 is a0=300 (initial height). Common difference is 4.2 (weekly increment). a_n=300+4.2n. At week n, the height of the tree is 300+4.2*n centimeters.

Mathematics

7.06 1. find the first six terms of the sequence. a1 = -7, an = 4 • an-1 a) -7, -28, -112, -448, -1792, -7168 b) -28, -112, -448, -1792, -7168, -28,672 c) -7, -28, -24, -20, -16, -12 d) 0, 4, -28, -24, -20, -16 2. find an equation for the nth term of the arithmetic sequence. -13, -8, -3, 2, an = -13 x 5(n - 1) an = -13 + 5(n - 1) an = -13 + 5(n + 2) an = -13 + 5(n + 1) 3. find an equation for the nth term of the arithmetic sequence. a15 = -53, a16 = -5 a) an = -725 - 48(n - 1) b) an = -725 + 48(n + 1) c) an = -725 + 48(n - 1) d) an = -725 - 48(n

Step-by-step answer

P Answered by PhD

21

1. A. According to the expression a_n=4*a_n-1, each term after a1 is four times the previous term. The first term is -7 as given, 2nd term should be -7*4=-28, 3rd term is -28*4=-112, ... A is the correct answer.

2. B. The sequence is -13, -8, -3, 2... It's obvious that each term is equal to the previous term plus 5. This is an arithmetic sequence with initial term -13 and common difference 5. We know a1=-13, so a_n=-13+5*(n-1). The answer is B.

3. A. We are given a15=-53, a16=-5. The common difference of the arithmetic sequence is -5-(-53)=48. The formula for a_n term is a1+48*(n-1). We know that a15=-13; plug in n=15, a15=-53=a1+48*(15-1), a1=-725. So a_n=-725+48*(n-1).

4. Diverge. We are given a few terms, 11, 44, 176, 704... Observe that each term is four times the previous one. 11*4=44, 44*4=176, 176*4=704... This is a geometric series with common ratio>1. You can keep multiplying by 4 and the series goes to infinity, so it diverges.

5. D. We have -4, -16, -64, -256... Same as above, each term is four times the previous one. The initial term is a1=-4. The common ratio d=4. So a_n=a1*d^(n-1)=-4*4^(n-1)=-4^n. (D).

6. The answer is A. a2=-2, a5=16. Suppose the common ratio is D. a_n=a1*d^(n-1). a2=a1*d; a5=a1*d^4. Plug in a2 and a5: -2=a1*d, 16=a1*d^4. 16/-2=d^3=-8, d=-2, a1=1. So a_n=1*(-2)^(n-1).

7. B. We are given the sequence 4, -24, 144,... Each term is -6 times the previous one. The first term a0=4, the n^th term a_(n-1) is a1*d^n=4*(-6)^n. To express the sum, we simply have to use the sigma notation and sum 4*(-6)^n from n=0 to infinity. The answer is B.

8. D. We are given -3 + 6 + 15 + 24... 132. Each term is equal to the previous one plus 9. First term a0=-3, n^th term a_n-1 is -3+9*n. The last term is 132. 132 =-3+9n, n=15. So we have to sum -3+9n from n=0 to n=15.

9. B. 343 + 512 + 729 + 1000+... 343=7^3, 512=8^3, 729=9^3, 1000=10^3. This is a sequence of perfect cubes. Therefore, the sum is n^3 from n=7 to infinity. (The initial term is 343=7^3).

10. B. We are given 3, 5, 7, 9, ... 21. The common difference is 2. There are (21-3)/2+1=10 terms. The initial term a1=3, and last term is a10=21. The sum is (a1+a10)*10/2=(3+21)*10/2=120.

11. C. 4/3, 16/3, 64/3, 256/3, 1024/3. Each term is four times the previous one. This is a geometric series with initial term a1=4/3 and common ratio r=4. 1024/3 is the 5th term of the sequence. So sum=a1*(1-r^n)/(1-r)=4/3*(1-4^5)/(1-4)=-4/9*-1023=1364/3.

12. B. 10,12,14,... This is an arithmetic sequence. a1=10, and common difference d=2. There are 20 terms (20 rows). a20=a1+d*(n-1)=10+2*(20-1)=48. So the sum S=(a1+an)*n/2=(10+48)*20/2=580.

13. 10 + 20 + 30 + ... + 10n = 5n(n + 1). When n=1, this expression is true, since 10=5*1*(1+1). Suppose when n=k, this statement is true, then when n=k+1, the left side is 10+...+10n+10(n+1), the right side is 5(n+1)(n+2). The left side adds 10(n+1) compared to the previous one. The right side adds 5(n+1)(n+2)-5n(n+1)=5(n+1)(n+2-n)=10(n+1). So the statement holds true.

14. The height at week 0 is a0=300 (initial height). Common difference is 4.2 (weekly increment). a_n=300+4.2n. At week n, the height of the tree is 300+4.2*n centimeters.

SAT

The following data is on X=Automobile Stock per capita, P= Relative price of automobiles and Id= Real disposable income per capita Years Xt Pt Idt Years Xt Pt Idt 1921 4.8 120.9 407.8 1937 8.34 100 551.2 1922 5.42 111.2 460.4 1938 7.78 109.3 511 1923 6.88 100.6 509.2 1939 7.72 104.9 547.9 1924 7.84 90.9 509.3 1940 8.22 97.1 578.8 1925 8.41 81.7 525.6 1941 9.17 120.1 642.7 1926 8.93 92.6 532.3 1942 7.42 119 719.1 1927 8.77 105.6 543.3 1943 5.79 204.7 741.6 1928 9.13 91 545.1 1944 4.45 356.7 798 1929 9.69 95.1 576.2 1945 3.51 449.3 787.2 1930 9.09

Step-by-step answer

P Answered by Master

gamsahabnida gamsahabnida

The following data is on

X=Automobile Stock per capita,P= Relative price of automobiles andId= Rea

Mathematics

1. Work out these calculations 104 divide to 4 = 168 divide to 7 = 342 divide to 6 = 423 divide to 9 = 472 divide to 8 = 305 divide to 5 = 112 divide to 7 = 207 divide to 9 = 2. Work out these division calculations with their remainders (e.g.: 25r1) 351 divide to 6 = 509 divide to 9 = 398 divide to 8 = 375 divide to 4 = 436 divide to 7 = 296 divide to 3 = 254 divide to 9 = 345 divide to 6 = 396 divide to 7 = 964 divide to 5 = 231 divide to 4 = 3. What is the missing digit? ?7 x 9 = 333

Step-by-step answer

P Answered by PhD

1

1:

26

24

57

47

59

61

16

23

2:

58.5

56.556

49.75

93.75

62.2857142857

98.667

28.223

57.5

56.5714285714

19.28

57.75

Mathematics

1. Work out these calculations 104 divide to 4 = 168 divide to 7 = 342 divide to 6 = 423 divide to 9 = 472 divide to 8 = 305 divide to 5 = 112 divide to 7 = 207 divide to 9 = 2. Work out these division calculations with their remainders (e.g.: 25r1) 351 divide to 6 = 509 divide to 9 = 398 divide to 8 = 375 divide to 4 = 436 divide to 7 = 296 divide to 3 = 254 divide to 9 = 345 divide to 6 = 396 divide to 7 = 964 divide to 5 = 231 divide to 4 = 3. What is the missing digit? ?7 x 9 = 333

Step-by-step answer

P Answered by PhD

1

1:

26

24

57

47

59

61

16

23

2:

58.5

56.556

49.75

93.75

62.2857142857

98.667

28.223

57.5

56.5714285714

19.28

57.75

Mathematics

Write TRUE if tue statement is correct and FALSE if it is wrong. 1. The additive inverse of 10 is -10. 2. Zero is a positive number. 3. To divide two unlike signs, the quotient is always positive. 4. Commutative Property states that: a + (b + c ) = (a + b ) + c 5. One is the identity element of for addition. Identify the following. 1. It is a distance from zero to any point. 2. A set of number from negative, zero and positive numbers. 3. A horizontal and vertical line with equal scale of negative, zero and positive numbers. 4. It is neither positive

Step-by-step answer

P Answered by PhD

4

The answers are as follows:

TrueFalseFalseFalseFalse

Step-by-step explanation:

Let us look at the statements one by one

1. The additive inverse of 10 is -10.

The additive inverse of a number is the opposite of a number with respect to sign.

The sum of a number and its additive inverse is zero.

10+(-10) = 10-10 = 0

This statement is true.

2. Zero is a positive number.

Zero is neither a positive number nor a negative number. It is only used as reference to decide whether a number is positive or negative.

This statement is false.

3. To divide two unlike signs, the quotient is always positive.

When two unlike signs are divided, the answer will be negative as division involves multiplication, and multiplication of two numbers with unlike signs will always be negative.

This statement is false.

4. Commutative Property states that:

a + (b + c ) = (a + b ) + c

Commutative property deals with two numbers or variables only. The property with three numbers or varibales is associative property. Hence,

This statement is false.

5. One is the identity element of for addition.

Additive identity is a number that when added to a number x, the result will always be x. Zero is additive identity.

Hence,

This statement is false.

The answers are as follows:

TrueFalseFalseFalseFalse

Mathematics

Write TRUE if tue statement is correct and FALSE if it is wrong. 1. The additive inverse of 10 is -10. 2. Zero is a positive number. 3. To divide two unlike signs, the quotient is always positive. 4. Commutative Property states that: a + (b + c ) = (a + b ) + c 5. One is the identity element of for addition. Identify the following. 1. It is a distance from zero to any point. 2. A set of number from negative, zero and positive numbers. 3. A horizontal and vertical line with equal scale of negative, zero and positive numbers. 4. It is neither positive

Step-by-step answer

P Answered by PhD

4

The answers are as follows:

TrueFalseFalseFalseFalse

Step-by-step explanation:

Let us look at the statements one by one

1. The additive inverse of 10 is -10.

The additive inverse of a number is the opposite of a number with respect to sign.

The sum of a number and its additive inverse is zero.

10+(-10) = 10-10 = 0

This statement is true.

2. Zero is a positive number.

Zero is neither a positive number nor a negative number. It is only used as reference to decide whether a number is positive or negative.

This statement is false.

3. To divide two unlike signs, the quotient is always positive.

When two unlike signs are divided, the answer will be negative as division involves multiplication, and multiplication of two numbers with unlike signs will always be negative.

This statement is false.

4. Commutative Property states that:

a + (b + c ) = (a + b ) + c

Commutative property deals with two numbers or variables only. The property with three numbers or varibales is associative property. Hence,

This statement is false.

5. One is the identity element of for addition.

Additive identity is a number that when added to a number x, the result will always be x. Zero is additive identity.

Hence,

This statement is false.

The answers are as follows:

TrueFalseFalseFalseFalse

Mathematics

Fast plz im timed 99 pts 1.which describes the correct way to convert minutes to hours? divide the number of minutes by 24. multiply the number of minutes by 24. divide the number of minutes by 60. multiply the number of minutes by 60. 2.fernando bought 8 pints of milk. how many fluid ounces of milk did fernando buy? 16 fluid ounces 64 fluid ounces 128 fluid ounces 256 fluid ounces 3.how many gallons equal 8 quarts? 2 gallons 4 gallons 12 gallons 32 gallons 4.why is a capacity of 25 fluid ounces more than a capacity of 3 cups? because when you

Step-by-step answer

P Answered by Master

13

Hello!

1. To convert minutes to hours, we must multiply the number of minutes by 60, because that is how many minutes there are in an hour.

2. 1 pint = 16 ounces

16 × 8 = 128

Fernando bought 128 fluid ounces of milk.

3. 1 quart = 0.25 gallons

0.25 × 8 = 2

2 gallons are equivalent to 8 quarts.

4. Because when you divide 25 by 8, the result is greater than 3.

5. By dividing 6,400 by 2,000, because that is how you will find the exact equivalent of 6,400 pounds in tons.

7. 1 pound = 16 ounces

16 × 80 = 1,280

1,280 ounces is equivalent to 80 pounds.

9.

The missing value in the table is 918, because:

1 yard = 3 feet

3 × 306 = 918

306 yards = 918 feet

6.51 divided by 3
25.64 divided by 15
12 divided by 2.436

Step-by-step answer

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