Answer:
See detailed explanation belowStep-by-step explanation:
Error: volume of cone when dimensions are doubled is 8 times of the original cone.
Proof:
Volume of cone V = πr²h/3
V ∝ r²h (since π and 3 are constants)
Let V1, r1 and h1 are the volume, radius and height of the first cone respectively.
And Let V2, r2 and h2 are the volume, radius and height of the second cone (with 2× dimensions of 1st cone i.e. r2 = 2r1 and h2 = 2h1) respectively.
V2/V1 = (r1)²h1/(r2)²h2
= (r1)²h1/(2r1)²(2h1)
= (r1)²h1/8(r1)²h1
V2/V1 = 1/8
V2 = 8V1