25.09.2020

Suzette solved a system of three linear equations in three variables using substitution. The steps she used to solve the system are shown below.



3x + 5y + 2z = 3
2x + 3z = 2
x – y = –7



Step 1
x = y – 7
2(y – 7) + 3z = 2
3(y – 7) + 5y + 2z = 3

Step 2
2y + 3z = 16
4y + z = 12

Step 3
2y + 3z = 16
–12y – 3z = –36
Step 4
y = 2
x = (2) – 7
x = –5
2(–5) + 3z = 2
–10 + 3z = 2
3z = 12
z = 4
Therefore:
x = –5, y = 2, z = 4





Did Suzette make a mistake in solving the system of three linear equations in three variables, and if so, in which step did the mistake occur?

. 3

Step-by-step answer

15.12.2022, solved by verified expert
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1 students found this answer . helpful

Answer:

No mistake

Step-by-step explanation:

Given equations are 

3x + 5y + 2z = 3
2x + 3z = 2
x – y = –7

Solution is 

x = –5, y = 2, z = 4

As the values of x, y and z is satisfying all the three equations, therefore there is no mistake in any of the steps.

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