22.02.2020

Solve for x.
6x + 10 = 52

. 0

Step-by-step answer

24.06.2023, solved by verified expert
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7

Step-by-step explanation:

well let’s just think that there’s already 10. let’s ignore the 10 for later.

now let’s think about 6x. of course the x is unknown (variable) which we have to find, so what you want to do, (easy way) think of every multiple of the number 6. so that of course includes 6, 12, 18... etc. now if you continue, you will get to the number 42. now it might not click right there but 42... is what we need since we already have the 10. since 42 + 10 = 52, now we just need to find out what 42 divided by 6 is... 7! 7x6 or 7(6) is 42, plus the starting 10 is 52!

therefore, x = 7.

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Mathematics
Step-by-step answer
P Answered by PhD
X = 7
(6)(7) + 10 = 52
42 + 10 = 52
Mathematics
Step-by-step answer
P Answered by PhD

(III), (VI),(VII), (I), (IV)

Step-by-step explanation:

Solving the system of equations one by one by elimination method

(I) 2x+y=10

   x-3y= -2   ( multiply by 2)

we have unique solution

x=4, y=2

(II) 2x+y=10    (multiply by -3)

 -6x-3y= -2

No solution.

(III) x+2y=5   (multiply by 2)

    2x+y=4

Unique solution

x=1, y=2

(IV) 5x+ y= 33

     x=18-4y ---> x+4y=18    (multiply by 5)

Unique solution

x=6, y=3

(V) Y=13 -2x   > 2x+y=13     ( multiply by 4)

   8x + 4y =52

No solution

(VI) x+ 3y =5

    6x-y=11    (multiply by 3)

Unique solution

x=2, y=1

(VII) Y=10 + x    > -x+y=10   (multiply by 2)

      2x + 3y =45

Unique solution

x=3 , y=13

Values of x in increasing order= (III), (VI),(VII), (I), (IV)

Mathematics
Step-by-step answer
P Answered by PhD

(III), (VI),(VII), (I), (IV)

Step-by-step explanation:

Solving the system of equations one by one by elimination method

(I) 2x+y=10

   x-3y= -2   ( multiply by 2)

we have unique solution

x=4, y=2

(II) 2x+y=10    (multiply by -3)

 -6x-3y= -2

No solution.

(III) x+2y=5   (multiply by 2)

    2x+y=4

Unique solution

x=1, y=2

(IV) 5x+ y= 33

     x=18-4y ---> x+4y=18    (multiply by 5)

Unique solution

x=6, y=3

(V) Y=13 -2x   > 2x+y=13     ( multiply by 4)

   8x + 4y =52

No solution

(VI) x+ 3y =5

    6x-y=11    (multiply by 3)

Unique solution

x=2, y=1

(VII) Y=10 + x    > -x+y=10   (multiply by 2)

      2x + 3y =45

Unique solution

x=3 , y=13

Values of x in increasing order= (III), (VI),(VII), (I), (IV)

Mathematics
Step-by-step answer
P Answered by PhD

6 , 2 , 5 , 7 , 4 , 1 , 3

Step by Step:

1) x - 3(10 - 2x) = -2

x - 30 + 6x = -2

7x - 30 = -2

7x = 28

x = 4

2) x + 2(4 - 2x) = 5

x + 8 - 4x = 5

-3x + 8 = 5

-3x = -3

x = 1

3) 5(18 - 4y) + y = 33

90 - 20y + y = 33

90 - 19y = 33

-19y = -57

y = 3

x = 18 - 4(3)

x = 18 - 12

x = 6

4) 8x + 4(13 - 2x) = 52

8x + 52 - 8x = 52

52 = 52

5) x + 3(-11 + 6x) = 5

x - 33 + 18x = 5

19x - 33 = 5

19x = 38

x = 2

6) -6(5 - 2y) - 3y = -2

-30 + 12y - 3y = -2

-30 + 9y = -2

9y = 28

y = 3

2x + 3(3) = 5

2x + 9 = 5

2x = -4

x = -2

7) 2x + 3(10+x) = 45

2x + 30 + 3x = 45

5x + 30 = 45

5x = 15

x = 3

Mathematics
Step-by-step answer
P Answered by PhD

6 , 2 , 5 , 7 , 4 , 1 , 3

Step by Step:

1) x - 3(10 - 2x) = -2

x - 30 + 6x = -2

7x - 30 = -2

7x = 28

x = 4

2) x + 2(4 - 2x) = 5

x + 8 - 4x = 5

-3x + 8 = 5

-3x = -3

x = 1

3) 5(18 - 4y) + y = 33

90 - 20y + y = 33

90 - 19y = 33

-19y = -57

y = 3

x = 18 - 4(3)

x = 18 - 12

x = 6

4) 8x + 4(13 - 2x) = 52

8x + 52 - 8x = 52

52 = 52

5) x + 3(-11 + 6x) = 5

x - 33 + 18x = 5

19x - 33 = 5

19x = 38

x = 2

6) -6(5 - 2y) - 3y = -2

-30 + 12y - 3y = -2

-30 + 9y = -2

9y = 28

y = 3

2x + 3(3) = 5

2x + 9 = 5

2x = -4

x = -2

7) 2x + 3(10+x) = 45

2x + 30 + 3x = 45

5x + 30 = 45

5x = 15

x = 3

Mathematics
Step-by-step answer
P Answered by Master

Part 1) x=3

Part 2) x = −1.11 and x = 1.11

Part 3) 105

Part 4) a = −6, b = 9, c = −7

Part 5) x equals 5 plus or minus the square root of 33, all over 2

Part 6) In the procedure

Part 7) -0.55

Part 8) The denominator is 2

Part 9) a = −6, b = −8, c = 12

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

Part 1)

in this problem we have

x^{2} -6x+9=0  

so

a=1\\b=-6\\c=9

substitute in the formula

x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(9)}} {2(1)}

x=\frac{6(+/-)\sqrt{0}} {2}

x=\frac{6} {2}=3

Part 2) in this problem we have

49x^{2} -60=0  

so

a=49\\b=0\\c=-60

substitute in the formula

x=\frac{0(+/-)\sqrt{0^{2}-4(49)(-60)}} {2(49)}

x=\frac{0(+/-)\sqrt{11,760}} {98}

x=(+/-)1.11

Part 3) When the solution of x2 − 9x − 6 is expressed as 9 plus or minus the square root of r, all over 2, what is the value of r?

in this problem we have

x^{2} -9x-6=0  

so

a=1\\b=-9\\c=-6

substitute in the formula

x=\frac{-(-9)(+/-)\sqrt{-9^{2}-4(1)(-6)}} {2(1)}

x=\frac{9(+/-)\sqrt{105}} {2}

therefore

r=105

Part 4) What are the values a, b, and c in the following quadratic equation?

−6x2 = −9x + 7

in this problem we have

-6x^{2}=-9x+7  

-6x^{2}+9x-7=0  

so

a=-6\\b=9\\c=-7

Part 5) Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0.

In this problem we have  

x^{2} -5x-2=0  

so

a=1\\b=-5\\c=-2

substitute in the formula

x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(1)(-2)}} {2(1)}

x=\frac{5(+/-)\sqrt{33}} {2}

therefore  

x equals 5 plus or minus the square root of 33, all over 2

Part 6) Quadratic Formula proof

we have

ax^{2} +bx+c=0  

Divide both sides by a

x^{2} +(b/a)x+(c/a)=0  

Complete the square

x^{2} +(b/a)x=-(c/a)  

x^{2} +\frac{b}{a}x+\frac{b^{2}}{4a^{2}} =-\frac{c}{a}+\frac{b^{2}}{4a^{2}}

Rewrite the perfect square trinomial on the left side of the equation as a binomial squared

(x+\frac{b}{2a})^{2}=-\frac{4ac}{a^{2}}+\frac{b^{2}}{4a^{2}}

Find a common denominator on the right side of the equation

(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}

Take the square root of both sides of the equation

(x+\frac{b}{2a})=(+/-)\sqrt{\frac{b^{2}-4ac}{4a^{2}}}

Simplify the right side of the equation

(x+\frac{b}{2a})=(+/-)\frac{\sqrt{b^{2}-4ac}}{2a}

Subtract the quantity b over 2 times a from both sides of the equation

x=-\frac{b}{2a}(+/-)\frac{\sqrt{b^{2}-4ac}}{2a}

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

Part 7) in this problem we have  

3x^{2} +45x+24=0  

so

a=3\\b=45\\c=24

substitute in the formula

x=\frac{-(45)(+/-)\sqrt{45^{2}-4(3)(24)}} {2(3)}

x=\frac{-(45)(+/-)\sqrt{1,737}} {6}

x1=\frac{-(45)(+)\sqrt{1,737}} {6}=-0.55

x2=\frac{-(45)(-)\sqrt{1,737}} {6}=-14.45

therefore

The other solution is

-0.55

Part 8) in this problem we have

2x^{2} -8x+7=0  

so

a=2\\b=-8\\c=7

substitute in the formula

x=\frac{-(-8)(+/-)\sqrt{-8^{2}-4(2)(7)}} {2(2)}

x=\frac{8(+/-)\sqrt{8}} {4}

x=\frac{8(+/-)2\sqrt{2}} {4}

x=\frac{4(+/-)\sqrt{2}} {2}

therefore

The denominator is 2

Part 9) What are the values a, b, and c in the following quadratic equation?

−6x2 − 8x + 12

in this problem we have

-6x^{2} -8x+12=0  

so

a=-6\\b=-8\\c=12

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