Answer:
(y-2)^2 = 8(x+2)
Step-by-step explanation:
Here the vertex of the parabols is (-2, 2)
The equation is of the form of
(y-k)^2 = 4A(x-h) .....(1)
Where (h,k) is the vertex of the parabola.
Here h = -2 and k = 2
Putting these values in (1)
(y-2)^2 = 4A(x+2)
A is the distance of the focus from the vertex. Coordinate of focus of the parabols is (0,2)
A = 2
Therefoe, equation is
(y-2)^2 = 4*2(x+2) = 8(x+2)
Eq. of the parabola in standard form is given as:
(y-2)^2 = 8(x+2)