Mathematics: 75 times 5.62 With explaination

Step-by-step explanation: To compute 75 times 5.62, we need to multiply 75 and 5.62 Steps are shown...

75 times 5.62 With explaination, №15255843, 09.09.2021 22:21

Mathematics

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25. Help pls i need this quick graphed series showing point 1, 2.25, point 2, 3.75, point 3, 8.25, point 4, 21.75, point 5, 62.25, and point 6, 183.75 graphed series showing point 1, 1.5, point 2, 3.75, point 3, 10.5, point 4, 30.75, point 5, 91.5, and point 6, 273.75 graphed series showing point 1, negative 9, point 2, negative 12, point 3, negative 16.5, point 4, negative 23.25, point 5, negative 33.38, and point 6, negative 48.56 A coordinate graph is shown. The points are at

Step-by-step answer

P Answered by PhD

6

S = {-6.25, -7.813, -9.766, -12.207, -15.259 and -19.703}

Step-by-step explanation:

The first term (a₁) and the common ration (r) of a finite sequence are provided.

a₁ = -6.25

r = 1.25

The nth term of a geometric sequence is:

$T_{n}=a_{1}\cdot r^{n-1}$

Compute the first six terms as follows:

$T_{1}=a_{1}\cdot r^{1-1}=a_{1}=-6.25\\\\T_{2}=a_{1}\cdot r^{2-1}=-6.25\times 1.25=-7.8125\approx -7.813\\\\T_{3}=a_{1}\cdot r^{3-1}=-6.25\times (1.25)^{2}=-9.765625\approx -9.766\\\\T_{4}=a_{1}\cdot r^{4-1}=-6.25\times (1.25)^{3}=-12.20703\approx -12.207\\\\T_{5}=a_{1}\cdot r^{5-1}=-6.25\times (1.25)^{4}=-15.25879\approx -15.259\\\\T_{6}=a_{1}\cdot r^{6-1}=-6.25\times (1.25)^{5}=-19.07349\approx -19.073$

Thus, the six terms of a finite sequence are:

S = {-6.25, -7.813, -9.766, -12.207, -15.259 and -19.703}

Mathematics

Graph the six terms of a finite sequence where a1 = −6.25 and r = 1.25. Help pls i need this quick graphed series showing point 1, 2.25, point 2, 3.75, point 3, 8.25, point 4, 21.75, point 5, 62.25, and point 6, 183.75 graphed series showing point 1, 1.5, point 2, 3.75, point 3, 10.5, point 4, 30.75, point 5, 91.5, and point 6, 273.75 graphed series showing point 1, negative 9, point 2, negative 12, point 3, negative 16.5, point 4, negative 23.25, point 5, negative 33.38, and point 6, negative 48.56 A coordinate graph is shown. The points are at

Step-by-step answer

P Answered by PhD

6

S = {-6.25, -7.813, -9.766, -12.207, -15.259 and -19.703}

Step-by-step explanation:

The first term (a₁) and the common ration (r) of a finite sequence are provided.

a₁ = -6.25

r = 1.25

The nth term of a geometric sequence is:

$T_{n}=a_{1}\cdot r^{n-1}$

Compute the first six terms as follows:

$T_{1}=a_{1}\cdot r^{1-1}=a_{1}=-6.25\\\\T_{2}=a_{1}\cdot r^{2-1}=-6.25\times 1.25=-7.8125\approx -7.813\\\\T_{3}=a_{1}\cdot r^{3-1}=-6.25\times (1.25)^{2}=-9.765625\approx -9.766\\\\T_{4}=a_{1}\cdot r^{4-1}=-6.25\times (1.25)^{3}=-12.20703\approx -12.207\\\\T_{5}=a_{1}\cdot r^{5-1}=-6.25\times (1.25)^{4}=-15.25879\approx -15.259\\\\T_{6}=a_{1}\cdot r^{6-1}=-6.25\times (1.25)^{5}=-19.07349\approx -19.073$

Thus, the six terms of a finite sequence are:

S = {-6.25, -7.813, -9.766, -12.207, -15.259 and -19.703}

Mathematics

1 point The area of an airplane s wings is related to the airplane s lifting force, which holds the airplane in the air. The table below lists several wing areas and the corresponding lifting forces. The ratio of lifting force to area is equivalent for all pairs in the table. What are the values of x and y?* AIRPLANE LIFTING FORCE Area of Wings Lifting Force (square feet) (pounds) 125 1,875 150 175 2,625 250 3,750 x 5,625 420 2,250 O x = 375 square feet and y = 7,500 pounds O x= 335 square feet and y = 6,300 pounds O x= 335 square feet and y =

Step-by-step answer

P Answered by PhD

13

x = 375 square feet and y = 6,300 pounds.

Explanation:

The table is:

AIRPLANE LIFTING FORCE

Area of Wings Lifting Force

(square feet) (pounds)

125 1,875

150 2,250

175 2,625

250 3,750

x 5,625

420 y

The ratio of lifting force to the area is equivalent for all pairs in the table. What are the values of x and y?

1. Calculate x:

Ratio of lifting force to the area for the first pair (row):

125/1,875

Ratio of lifting force to area for the pair with x:

x/5,625

Set the proportion:

Equal the two ratios

x/5,625 = 125/1,875

Multiply both sides by 5,625 (multiplication property of equalities):

x = 5,625 × 125/1,875x = 375 ← answer

2. Calculate y:

You can use the same know ratio for the first pair: 125/1,875

And set the corresponding proportion, with y:

420/y = 125/1,875

Invert both sides:

y/420 = 1,875/125

Multiply both sides by 420

y = 420 × 1,875/125 y = 6,300 ← answer

The answer is x = 375 square feet and y = 6,300 pounds.

Mathematics

1 point The area of an airplane s wings is related to the airplane s lifting force, which holds the airplane in the air. The table below lists several wing areas and the corresponding lifting forces. The ratio of lifting force to area is equivalent for all pairs in the table. What are the values of x and y?* AIRPLANE LIFTING FORCE Area of Wings Lifting Force (square feet) (pounds) 125 1,875 150 175 2,625 250 3,750 x 5,625 420 2,250 O x = 375 square feet and y = 7,500 pounds O x= 335 square feet and y = 6,300 pounds O x= 335 square feet and y =

Step-by-step answer

P Answered by PhD

13

x = 375 square feet and y = 6,300 pounds.

Explanation:

The table is:

AIRPLANE LIFTING FORCE

Area of Wings Lifting Force

(square feet) (pounds)

125 1,875

150 2,250

175 2,625

250 3,750

x 5,625

420 y

The ratio of lifting force to the area is equivalent for all pairs in the table. What are the values of x and y?

1. Calculate x:

Ratio of lifting force to the area for the first pair (row):

125/1,875

Ratio of lifting force to area for the pair with x:

x/5,625

Set the proportion:

Equal the two ratios

x/5,625 = 125/1,875

Multiply both sides by 5,625 (multiplication property of equalities):

x = 5,625 × 125/1,875x = 375 ← answer

2. Calculate y:

You can use the same know ratio for the first pair: 125/1,875

And set the corresponding proportion, with y:

420/y = 125/1,875

Invert both sides:

y/420 = 1,875/125

Multiply both sides by 420

y = 420 × 1,875/125 y = 6,300 ← answer

The answer is x = 375 square feet and y = 6,300 pounds.

Mathematics

which measure correctly completes the statement? 1,127.5 milligrams=? grams 112.75 grams 11.275 grams 1.1275 grams 1,127.5 grams 2. which measure correctly completes the statement? 627.532 l= ? ml 6.27532 ml 627,532 ml 62,753.2 ml 627,532,000 ml 3. estimate the area of a circle with a radius of 16 meters. use 22/7 for r. 62 square meters 531 square meters 805 square meters 1,608 square meters

Step-by-step answer

P Answered by Specialist

4

The answer to number 1 is C. Not sure how to get that, I just got it off line converting it with a website.

The answer to number 2 in B, also got that offline by converting it.

3.) Area of a circle:
Radius-16
16×16×3.14=803.84 rounded to the nearest number is 804.

Since this says ESTIMATED we look for the closest answer to 804.
The answer is C. 805 square meters.

Mathematics

which measure correctly completes the statement? 1,127.5 milligrams=? grams 112.75 grams 11.275 grams 1.1275 grams 1,127.5 grams 2. which measure correctly completes the statement? 627.532 l= ? ml 6.27532 ml 627,532 ml 62,753.2 ml 627,532,000 ml 3. estimate the area of a circle with a radius of 16 meters. use 22/7 for r. 62 square meters 531 square meters 805 square meters 1,608 square meters

Step-by-step answer

P Answered by Master

4

The answer to number 1 is C. Not sure how to get that, I just got it off line converting it with a website.

The answer to number 2 in B, also got that offline by converting it.

3.) Area of a circle:
Radius-16
16×16×3.14=803.84 rounded to the nearest number is 804.

Since this says ESTIMATED we look for the closest answer to 804.
The answer is C. 805 square meters.

Computers and Technology

Univariate linear regression Note: Solutions to this problem must follow the method described in class and the linear regression handout. There is some flexibility in how your solution is coded, but you may not use special functions that automatically perform linear regression for you. Load in the BodyBrain Weight.csv dataset. Perform linear regression using two different models: M1: brain_weight = w0 + w1 x body_weight M2: brain_weight = w0 + w1 x body_weight + w2 x body_weight2 a. For each model, follow the steps shown in class to solve for w.

Step-by-step answer

P Answered by Specialist

regression line is Y = 124.9281 + 0.9370 *x

SSE= (SSxx * SSyy - SS²xy)/SSxx = 7317401.270

Explanation:

See the attached image file

Univariate linear regression Note: Solutions to this problem must follow the method described in cla

Mathematics

Gold used to make jewerly is often a blend of gold, silver, and copper. consider three alloys of these metals. the first alloy is 75% gold, 5% silver, and 20% copper. the second alloy is 75% gold, 12.5% silver, and 12.5% copper. the third alloy is 37.5% gold and 62.5% silver. if 100 g of the first alloy costs $2500.40, 100 g of the second alloy costsnbsp $ 2537.75, and 100 g of the third alloy costs $ 1550.00, how much does each metal cost?

Step-by-step answer

P Answered by PhD

Gold - $33, Silver - $5, Copper - $0.02

Step-by-step explanation:

Let $x be the price of one gram of gold, $y - price of 1 g of silver and $z - price of 1 g of copper.

1. The first alloy is 75% gold, 5% silver, and 20% copper, so in 100 g there are 75 g of gold, 5 g of silver and 20 g of copper. If 100 g of the first alloy costs $2500.40, then

75x+5y+20z=2500.40

2. The second alloy is 75% gold, 12.5% silver, and 12.5% copper, so in 100 g there are 75 g of gold, 12.5 g of silver and 12.5 g of copper. If 100 g of the first alloy costs $2537.75, then

75x+12.5y+12.5z=2537.75

3. The third alloy is 37.5% gold and 62.5% silver, so in 100 g there are 37.5 g of gold and 62.5 g of silver . If 100 g of the first alloy costs $1550.00, then

37.5x+62.5y=1550.00

Solve the system of three equations:

$\left\{\begin{array}{l}75x+5y+20z=2500.40\\75x+12.5y+12.5z=2537.75\\37.5x+62.5y=1550.00\end{array}\right.$

Find all determinants

$\Delta=\|\left[\begin{array}{ccc}75&5&20\\75&12.5&12.5\\37.5&62.5&0\end{array}\right] \|=28125\\ \\\Delta_x=\|\left[\begin{array}{ccc}2500.40&5&20\\2537.75&12.5&12.5\\1550.00&62.5&0\end{array}\right] \|=928125\\ \\\Delta_y=\|\left[\begin{array}{ccc}75&2500.40&20\\75&2537.75&12.5\\37.5&1550&0\end{array}\right] \|=140625\\ \\\Delta_z=\|\left[\begin{array}{ccc}75&5&2500.40\\75&12.5&2537.75\\37.5&62.5&1550\end{array}\right] \|=562.5\\ \\$

So,

$x=\dfrac{\Delta_x}{\Delta}=\dfrac{928125}{28125}=33\\ \\\\y=\dfrac{\Delta_y}{\Delta}=\dfrac{140625}{28125}=5\\ \\\\z=\dfrac{\Delta_z}{\Delta}=\dfrac{562.5}{28125}=0.02\\ \\$

Mathematics

Gold used to make jewerly is often a blend of gold, silver, and copper. consider three alloys of these metals. the first alloy is 75% gold, 5% silver, and 20% copper. the second alloy is 75% gold, 12.5% silver, and 12.5% copper. the third alloy is 37.5% gold and 62.5% silver. if 100 g of the first alloy costs $2500.40, 100 g of the second alloy costsnbsp $ 2537.75, and 100 g of the third alloy costs $ 1550.00, how much does each metal cost?

Step-by-step answer

P Answered by PhD

Gold - $33, Silver - $5, Copper - $0.02

Step-by-step explanation:

Let $x be the price of one gram of gold, $y - price of 1 g of silver and $z - price of 1 g of copper.

1. The first alloy is 75% gold, 5% silver, and 20% copper, so in 100 g there are 75 g of gold, 5 g of silver and 20 g of copper. If 100 g of the first alloy costs $2500.40, then

75x+5y+20z=2500.40

2. The second alloy is 75% gold, 12.5% silver, and 12.5% copper, so in 100 g there are 75 g of gold, 12.5 g of silver and 12.5 g of copper. If 100 g of the first alloy costs $2537.75, then

75x+12.5y+12.5z=2537.75

3. The third alloy is 37.5% gold and 62.5% silver, so in 100 g there are 37.5 g of gold and 62.5 g of silver . If 100 g of the first alloy costs $1550.00, then

37.5x+62.5y=1550.00

Solve the system of three equations:

$\left\{\begin{array}{l}75x+5y+20z=2500.40\\75x+12.5y+12.5z=2537.75\\37.5x+62.5y=1550.00\end{array}\right.$

Find all determinants

$\Delta=\|\left[\begin{array}{ccc}75&5&20\\75&12.5&12.5\\37.5&62.5&0\end{array}\right] \|=28125\\ \\\Delta_x=\|\left[\begin{array}{ccc}2500.40&5&20\\2537.75&12.5&12.5\\1550.00&62.5&0\end{array}\right] \|=928125\\ \\\Delta_y=\|\left[\begin{array}{ccc}75&2500.40&20\\75&2537.75&12.5\\37.5&1550&0\end{array}\right] \|=140625\\ \\\Delta_z=\|\left[\begin{array}{ccc}75&5&2500.40\\75&12.5&2537.75\\37.5&62.5&1550\end{array}\right] \|=562.5\\ \\$

So,

$x=\dfrac{\Delta_x}{\Delta}=\dfrac{928125}{28125}=33\\ \\\\y=\dfrac{\Delta_y}{\Delta}=\dfrac{140625}{28125}=5\\ \\\\z=\dfrac{\Delta_z}{\Delta}=\dfrac{562.5}{28125}=0.02\\ \\$

Mathematics

Check and correct these answer 30 : d: d write the ratio in the simplest form. 45: 15 9: 3 3: 1*** 1: 3 4: 1 solve the following proportion. (solve p) p/3 = 8/12 2*** 8 12 24 a recipe calls for 3 cups of flour to make 3 dozen cookies. use the proportion to calculate how much flour is needed to make 9 dozen cookies. 3 cups x cups = 3 dozen 9 dozen 6 cups 3.5 cups 9 cups*** 12 cups chase sold 48 tickets to the school dance, and justine sold 14 tickets. what is the ratio, in simplest form, of the number of tickets justine sold to the number of tickets

Step-by-step answer

P Answered by Specialist

4

Copied the questions I found to be incorrect and corrected them showing you the work to verify.

A map of a bike race has a scale of 2 inches = 50 miles. The distance to the first aid station from the starting lines is about 1.25 inches. How far is it from the starting line to the first aid station in miles? Round to the nearest mile.
25 miles
31 miles☆☆☆☆☆☆☆
62 miles
49 miles

1.25/x=2/50
2x=(1.25)(50)
2x=62.5
2/2x=62.5/2=31.25≈31 miles

Write the ratio as a fraction in simplest form.
24 to 20
1/4
6/5☆☆☆☆☆☆☆
24/20
5/6

24 /20 reduces by 4/4 to become 6/ 5

75 times 5.62 With explaination

Step-by-step answer

Faq

Try asking the Studen AI a question.