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Mathematics : asked on laugusta07
 20.12.2021

Matthew has a bag with 9 coins. He has twice as many dimes as quarters. He has the same number of quarters and nickels. He has one penny. Each coin is worth $0.25 or less. What is the total value of matthew’s coins?

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10.05.2023, solved by verified expert
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Rajat Thapa
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Mathematics, DAV Post Graduate College
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Answer:

$1.01

Step-by-step explanation:

Let the number of quarters Matthew has be x. 

So, according to the question, 

Number of dimes = 2x

Number of nickels = x

Number of penny = 1

Total number of coins = 9

Thus, 

x + 2x + x + 1 = 9

4x = 8

So, x = 2

Now, we know that :

1 dime = $0.10

1 quarter = $0.25

1 nickel = $0.05

1 penny = $0.01

Thus, total money Matthew has = 2x($0.10) + x($0.25) + x($0.05) + 1($0.01) 

Putting value of x, 

Total money = 4($0.10) + 2($0.25) + 2($0.05) + 1($0.01) 

= $(0.40 + 0.50 + 0.10 + 0.01) 

= $1.01

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