6(x + y)
for x = 1 and y = 1

Let's solve ~

plug in the given values,

12

Step-by-step explanation:

All you have to is plug in the values. (Don't forget PEMDAS.)

Parentheses (Comes first)

Exponents

Multiplication

Division

Addition

Subtraction (Comes last)

x = 1

y = 1

6(1+1)

6(2)

= 12

Hope this helped! :)

The answers would be

1. C

2. B

3. A

Step-by-step explanation:

The term product refers to multiplication. So in question 1, when we see the term quotient, we are looking to multiply.

The term quotient refers to division. So in questions 2 and 3, when we see this term, we look to divide.

The answers would be

1. C

2. B

3. A

Step-by-step explanation:

The term product refers to multiplication. So in question 1, when we see the term quotient, we are looking to multiply.

The term quotient refers to division. So in questions 2 and 3, when we see this term, we look to divide.

The question is :

2x²y'' + 5xy' + y = x² - x;

y = c1x^(1/2) + c2x^(-1) + 1/15(x^2) - 1/6(x), (0,infinity)

The functions (x^-1/2) and (x^-1) satisfy the differential equation and are linearly independent since W(x^-1/2, x^-1)= ? for 0

The functions x^(-1/2) and x^(-1) are linearly independent since their wronskian is (-1/2)x^(-5/2) ≠ 0.

Step-by-step explanation:

Suppose the functions x^(-1/2) and x^(-1) satisfy the differential equation 2x²y'' + 5xy' + y = x² - x;

and are linearly independent, then their wronskian is not zero.

Wronskian of y1 and y2 is given as

W(y1, y2) = y1y2' - y1'y2

Let y1 = x^(-1/2)

y1' = (-1/2)x^(-3/2)

Let y2 = x^(-1)

y2' = -x^(-2)

W(y1, y2) =

x^(-1/2)(-x^(-2)) - (-1/2)x^(-3/2)x^(-1)

= -x^(-5/2) + (1/2)(x^(-5/2)

= (-1/2)x^(-5/2)

So, W(y1, y2) = (-1/2)x^(-5/2) ≠ 0

Which means the functions are linearly independent.

B)

B)

D)

Step-by-step explanation:

1.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

B)

B)

D)

Step-by-step explanation:

1.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

2.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer

3.

The GCF of all the term of the above polynomial is , hence we take it outside and form a bracket

The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer

The answer is in the image 

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5