Mathematics: Based on my answers from number 1 & 2 I need help with question 3 and 4 the graph

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Based on my answers from number 1 & 2 I, №15258124, 07.11.2022 05:50

Physics

1-D Kinematics EXTRA CREDIT Please show your work as well as the answers. Make sure your answers have units and also a direction if it is a vector. Each correct question is 3 bonus points up to a maximum of 100 on the quiz. For questions 1 and 2: A cart rolls 2 m to the right then rolls back 1 m to the left. What is the total distance rolled by the cart? The cart rolled 3 meters What is the displacement of the cart from the initial to the final positions? For questions 3 and 4: A child observes a caterpillar walking on a window sill. The caterpillar

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P Answered by Specialist

1

Please ask questions 1 by1

I have answered most of these in the previous questions

Mathematics

Question 1 (multiple choice) (mc) rewrite the radical as a rational exponent. the fourth root of 7 to the fifth power 7 to the 5 over 4 power 720 7 7 to the 4 over 5 power question 2 (multiple choice) (mc) rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 7 over 8 power, all over 2 to the 1 over 4 power the eighth root of 2 to the fifth power the fifth root of 2 to the eighth power the square root of 2 to the 5 over 8 power the fourth root of 2 to the sixth power question 3 (multiple choice) (mc)

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P Answered by PhD

61

Q1. The answer is 7 to the 5 over 4 power
Let's write the fourth root of 7 to the fifth power as a radical. 7 to the fifth power is 7⁵. The fourth root of 7 to the fifth power is $\sqrt[4]{7^{5} }$ .
Now, to rewrite it as a rational exponent, we will use the following:
$x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$
Our radical is $\sqrt[4]{7^{5} }$ which means that n = 4, m = 5.
So, the rational exponent it will be:
$\sqrt[4]{ 7^{5}} =7^{ \frac{5}{4}}$ which is the same as 7 to the 5 over 4 power

Q2. The answer is the eighth root of 2 to the fifth power.
Let's present 2 to the 7 over 8 power, all over 2 to the 1 over 4 power as a rational exponent.
2 to the 7 over 8 power is $2^{ \frac{7}{8}}$
2 to the 1 over 4 power is $2^{ \frac{1}{4} }$
2 to the 7 over 8 power, all over 2 to the 1 over 4 power is $\frac{2^{ \frac{7}{8}}}{2^{ \frac{1}{4} }}$
Using the rule: $\frac{x^{a} }{ x^{b} }= x^{a-b}$ we have:
$\frac{2^{ \frac{7}{8}}}{2^{ \frac{1}{4} }} =2^{ \frac{7}{8}- \frac{1}{4}} = 2^{ \frac{7}{8}- \frac{2}{8}}= 2^{ \frac{7-2}{8} } = 2^{ \frac{5}{8} }$
Since: $x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$ , then n = 8, m = 5
Therefore
$2^{ \frac{5}{8} = \sqrt[8]{ 2^{5} }$

Q3. The answer is 9 inches squared.
The area of the rectangle (A) is
A = l · w (l - length, w - width).
It is given:
l = the cube root of 81 inches = $\sqrt[3]{81}= \sqrt[3]{3^{4} } =3^{ \frac{4}{3} }$
w = 3 to the 2 over 3 = $3^{ \frac{2}{3}}$

A = $3^{ \frac{4}{3} } * 3^{ \frac{2}{3} }$
Since: $x^{a} * x^{b}= x^{a+b}$ then:
A = $3^{ \frac{4}{3}+ \frac{2}{3}}= 3^{ \frac{4+2}{3} } = 3^{ \frac{6}{3} } = 3^{2}=9$

Q4. The answer is By simplifying 25 to 5² to make both powers base five and subtracting the exponents
5 to the fourth power, over 25 = 52 is $\frac{ 5^{4}}{25}= 5^{2}$
Now, let's simplify 25 to 5²:
$\frac{ 5^{4}}{ 5^{2} }=5^{2}$
Since $\frac{x^{a} }{ x^{b} }= x^{a-b}$ , we will subtract the exponents:
$5^{4-2} = 5^{2}$
⇒ $5^{2} = 5^{2}$

Q5. The answer is the ninth root of 3
3 to the 2 over 3 power is $3^{ \frac{2}{3} }$
3 to the 2 over 3 power, to the 1 over 6 power is $(3^{ \frac{2}{3} } } )^{ \frac{1}{6} }$
Since $(x^{a})^{b} =x ^{a*b}$ then:
$(3^{ \frac{2}{3}}) ^{ \frac{1}{6} } = 3^{ \frac{2}{3} * \frac{1}{6} } = 3^{ \frac{2}{18} }= 3^{ \frac{1}{9} }$
Since: $x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$ , then: n = 9, m = 1
$3^{ \frac{1}{9} }= \sqrt[9]{3^{1} } = \sqrt[9]{3}$

Spanish

¿qué hora es? write the times using complete sentences. follow the model. modelo 3: 00 p.m. son las tres de la tarde. question 1 with 1 blank 11: 15 a.m. question 2 with 1 blank 9: 45 p.m. question 3 with 1 blank 12: 35 p.m. question 4 with 1 blank 12: 00 a.m. question 5 with 1 blank 6: 30 a.m. question 6 with 1 blank 7: 23 p.m. question 7 with 1 blank 10: 10 a.m. preguntas answer the questions using the times given. use complete sentences and write the numbers as words. question 1 with 1 blank ¿a qué hora es la clase de historia? (2: 20) question

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P Answered by PhD

7

Ey, gusto saludarte y ayudarte. Aquí van las respuestas:Respuesta 1:

En esta primera pregunta, debemos responder a la pregunta:

¿Qué hora es?

Siguiendo el modelo a continuación:

Modelo 3:00 p.m. Son las tres de la tarde.

En español, usamos el verbo ser para dar la hora, conjugado como es si nos referimos a la hora desde 1:00 hasta 1:59, para el resto usamos la conjugación son. De esta manera podemos responder la pregunta:

11:15 a.m. Son las once y quince de la tarde

9:45 p.m. Son las nueve y cuarenta y cinco de la tarde

12:35 p.m. Son las doce y treinta y cinco de la tarde

12:00 a.m. Son las doce de la madrugada

6:30 a.m. Son las seis y media de la mañana

7:23 p.m. Son las siete y veintitrés de la noche

10:10 a.m. Son las diez y diez de la mañana

Respuesta 2:

En este ejercicio, tenemos que responder a las preguntas con la hora correcta partiendo de los números en paréntesis. Dado que no se indica a.m o p.m, asumimos que los que dialogan saben a qué momento del día se refiere. De hecho, es fácil inferir que en el caso de las 2:20 se refiere a la tarde. Sin embargo, las 8:50 podría ser tanto de la mañana como de la tarde. De esta manera, tenemos:

1. ¿A qué hora es la clase de historia?

La clase de historia es a las dos y veinte

2. ¿Qué hora es?

Es la una

3. ¿A qué hora es el programa?

El programa es a las ocho y cincuenta

4. ¿A qué hora es la prueba?

La prueba es a la una y quince

5. ¿Qué hora es?

Son las cinco y media

6. ¿A qué hora es la clase de español?

La clase de español es a las once y cuarenta y cinco

Physics

1-D Kinematics EXTRA CREDIT Please show your work as well as the answers. Make sure your answers have units and also a direction if it is a vector. Each correct question is 3 bonus points up to a maximum of 100 on the quiz. For questions 1 and 2: A cart rolls 2 m to the right then rolls back 1 m to the left. What is the total distance rolled by the cart? The cart rolled 3 meters What is the displacement of the cart from the initial to the final positions? For questions 3 and 4: A child observes a caterpillar walking on a window sill. The caterpillar

Step-by-step answer

P Answered by Master

1

Please ask questions 1 by1

I have answered most of these in the previous questions

Mathematics

Plz do not delete these questions. i will give 50 points for the question, a brainliest, a , and a five stars rate. 1. the soup company wants to package its soup in a new can which is in the shape of a cylinder. the new label will completely cover the sides of the can but not the top and bottom of the can. the company has four choices for the cans. which can will need the least amount of paper to make the new label? soup can choices can radius height a 2 inches 6 inches b 2.5 inches 5 inches c 3 inches 4 inches d 3.2 inches 3 inches recall the

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P Answered by PhD

26

Ques 1)

CAN D

Ques 2)

252 pi in.^2

Ques 3)

288 pi cm^3

Ques 4)

2080 pi ft. ^2

Ques 5)

540 pi in. ^3

Step-by-step explanation:

Let r denote the radius of the cylinder.

and h denote the height of the cylinder.

Ques 1)

We know that the least amount of paper is required by the can whose lateral surface area is the smallest.

We know that the lateral surface area of cylinder is given by:

$LA=2\pi rh$

CAN Radius Height Lateral Area

A 2 in. 6 in. 75.36 square in.

B 2.5 in. 5 in. 78.5 square in.

C 3 in. 4 in. 75.36 square in.

D 3.2 in. 3 in. 60.288 square in.

Hence, the can that requires the least amount of paper is:

CAN D.

Ques 2)

r=6 in.

h=15 in.

The surface area of cylinder is calculated as:

$SA=2\pi r^2+2\pi rh$

Hence, on putting the given values in the formula we have:

$SA=2\pi\times 6^2+2\pi \times 6\times 15\\\\SA=252\pi\ in.^2$

Hence,

SA=252 pi in.^2.

Ques 3)

diameter(d)=8 cm.

This means that:

r=d/2=4 cm.

h=18 cm.

Hence, the volume(V) of the cylinder is calculated as:

$V=\pi r^2h\\\\V=\pi\times (4)^2\times 18\\\\V=288\pi\ cm^3$

Hence,

Volume is: 288 pi cm^3

Ques 4)

d=40 feet.

h=32 feet.

Hence, r=d/2=40/2=20 feet.

Hence, the surface area of the cylinder is calculated as:

$SA=2\pi r^2+2\pi rh\\\\SA=2\pi\times (20)^2+2\pi\times 20\times 32\\\\SA=2080\pi\ ft.^2$

Hence, SA=2080 pi ft. ^2

Ques 5)

r=6 in.

h=15 in.

Hence, the volume of the cylinder is given by:

$V=\pi r^2h\\\\V=\pi \times (6)^2\times 15\\\\V=540\pi\ in.^3$

Hence,

Volume= 540 pi in. ^3

Spanish

¿qué hora es? write the times using complete sentences. follow the model. modelo 3: 00 p.m. son las tres de la tarde. question 1 with 1 blank 11: 15 a.m. question 2 with 1 blank 9: 45 p.m. question 3 with 1 blank 12: 35 p.m. question 4 with 1 blank 12: 00 a.m. question 5 with 1 blank 6: 30 a.m. question 6 with 1 blank 7: 23 p.m. question 7 with 1 blank 10: 10 a.m. preguntas answer the questions using the times given. use complete sentences and write the numbers as words. question 1 with 1 blank ¿a qué hora es la clase de historia? (2: 20) question

Step-by-step answer

P Answered by PhD

7

Ey, gusto saludarte y ayudarte. Aquí van las respuestas:Respuesta 1:

En esta primera pregunta, debemos responder a la pregunta:

¿Qué hora es?

Siguiendo el modelo a continuación:

Modelo 3:00 p.m. Son las tres de la tarde.

En español, usamos el verbo ser para dar la hora, conjugado como es si nos referimos a la hora desde 1:00 hasta 1:59, para el resto usamos la conjugación son. De esta manera podemos responder la pregunta:

11:15 a.m. Son las once y quince de la tarde

9:45 p.m. Son las nueve y cuarenta y cinco de la tarde

12:35 p.m. Son las doce y treinta y cinco de la tarde

12:00 a.m. Son las doce de la madrugada

6:30 a.m. Son las seis y media de la mañana

7:23 p.m. Son las siete y veintitrés de la noche

10:10 a.m. Son las diez y diez de la mañana

Respuesta 2:

En este ejercicio, tenemos que responder a las preguntas con la hora correcta partiendo de los números en paréntesis. Dado que no se indica a.m o p.m, asumimos que los que dialogan saben a qué momento del día se refiere. De hecho, es fácil inferir que en el caso de las 2:20 se refiere a la tarde. Sin embargo, las 8:50 podría ser tanto de la mañana como de la tarde. De esta manera, tenemos:

1. ¿A qué hora es la clase de historia?

La clase de historia es a las dos y veinte

2. ¿Qué hora es?

Es la una

3. ¿A qué hora es el programa?

El programa es a las ocho y cincuenta

4. ¿A qué hora es la prueba?

La prueba es a la una y quince

5. ¿Qué hora es?

Son las cinco y media

6. ¿A qué hora es la clase de español?

La clase de español es a las once y cuarenta y cinco

Mathematics

tea costs $4.48 for 8 ounces. what is the cost per one ounce? question 1 options: $1.79 per ounce $0.56 per ounce $35.84 per ounce $0.056 per ounce question 2 (2 points) jaziah bought 6 1/2 pounds of bananas for $5.20. what is the cost per pound of bananas? question 2 options: $0.08 per pound of bananas $0.88 per pound of bananas $0.80 per pound of bananas $0.89 per pound of bananas question 3 (2 points) the values in the table show the relationship between times measured in seconds and distances measured in meters. seconds (x) meters (y) 5 20

Step-by-step answer

P Answered by PhD

2

Q1. 0.56

Q2. 0.08

Q3. 5 mps

Q4. 24

Q5. 0.69

Q6. 48 mph

Q7. 5.05

hope this helps!

Mathematics

Question 1 (multiple choice) (mc) rewrite the radical as a rational exponent. the fourth root of 7 to the fifth power 7 to the 5 over 4 power 720 7 7 to the 4 over 5 power question 2 (multiple choice) (mc) rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 7 over 8 power, all over 2 to the 1 over 4 power the eighth root of 2 to the fifth power the fifth root of 2 to the eighth power the square root of 2 to the 5 over 8 power the fourth root of 2 to the sixth power question 3 (multiple choice) (mc)

Step-by-step answer

P Answered by PhD

61

Q1. The answer is 7 to the 5 over 4 power
Let's write the fourth root of 7 to the fifth power as a radical. 7 to the fifth power is 7⁵. The fourth root of 7 to the fifth power is $\sqrt[4]{7^{5} }$ .
Now, to rewrite it as a rational exponent, we will use the following:
$x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$
Our radical is $\sqrt[4]{7^{5} }$ which means that n = 4, m = 5.
So, the rational exponent it will be:
$\sqrt[4]{ 7^{5}} =7^{ \frac{5}{4}}$ which is the same as 7 to the 5 over 4 power

Q2. The answer is the eighth root of 2 to the fifth power.
Let's present 2 to the 7 over 8 power, all over 2 to the 1 over 4 power as a rational exponent.
2 to the 7 over 8 power is $2^{ \frac{7}{8}}$
2 to the 1 over 4 power is $2^{ \frac{1}{4} }$
2 to the 7 over 8 power, all over 2 to the 1 over 4 power is $\frac{2^{ \frac{7}{8}}}{2^{ \frac{1}{4} }}$
Using the rule: $\frac{x^{a} }{ x^{b} }= x^{a-b}$ we have:
$\frac{2^{ \frac{7}{8}}}{2^{ \frac{1}{4} }} =2^{ \frac{7}{8}- \frac{1}{4}} = 2^{ \frac{7}{8}- \frac{2}{8}}= 2^{ \frac{7-2}{8} } = 2^{ \frac{5}{8} }$
Since: $x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$ , then n = 8, m = 5
Therefore
$2^{ \frac{5}{8} = \sqrt[8]{ 2^{5} }$

Q3. The answer is 9 inches squared.
The area of the rectangle (A) is
A = l · w (l - length, w - width).
It is given:
l = the cube root of 81 inches = $\sqrt[3]{81}= \sqrt[3]{3^{4} } =3^{ \frac{4}{3} }$
w = 3 to the 2 over 3 = $3^{ \frac{2}{3}}$

A = $3^{ \frac{4}{3} } * 3^{ \frac{2}{3} }$
Since: $x^{a} * x^{b}= x^{a+b}$ then:
A = $3^{ \frac{4}{3}+ \frac{2}{3}}= 3^{ \frac{4+2}{3} } = 3^{ \frac{6}{3} } = 3^{2}=9$

Q4. The answer is By simplifying 25 to 5² to make both powers base five and subtracting the exponents
5 to the fourth power, over 25 = 52 is $\frac{ 5^{4}}{25}= 5^{2}$
Now, let's simplify 25 to 5²:
$\frac{ 5^{4}}{ 5^{2} }=5^{2}$
Since $\frac{x^{a} }{ x^{b} }= x^{a-b}$ , we will subtract the exponents:
$5^{4-2} = 5^{2}$
⇒ $5^{2} = 5^{2}$

Q5. The answer is the ninth root of 3
3 to the 2 over 3 power is $3^{ \frac{2}{3} }$
3 to the 2 over 3 power, to the 1 over 6 power is $(3^{ \frac{2}{3} } } )^{ \frac{1}{6} }$
Since $(x^{a})^{b} =x ^{a*b}$ then:
$(3^{ \frac{2}{3}}) ^{ \frac{1}{6} } = 3^{ \frac{2}{3} * \frac{1}{6} } = 3^{ \frac{2}{18} }= 3^{ \frac{1}{9} }$
Since: $x^{ \frac{m}{n}}= \sqrt[n]{ x^{m} }$ , then: n = 9, m = 1
$3^{ \frac{1}{9} }= \sqrt[9]{3^{1} } = \sqrt[9]{3}$

Physics

Question 1 (1 point) in a magnet, what type of poles are attracted to each other? question 1 options: north poles unlike or different poles south poles like poles question 2 (1 point) saved magnets are surrounded by question 2 options: positively charged matter gravitational fields magnetic fields electric fields question 3 (1 point) bar magnets have poles. question 3 options: 4 3 1 2 question 4 (1 point) saved what elements have magnetic properties and will be attracted to magnets? question 4 options: sodium, cobalt and iron iron, cobalt, and

Step-by-step answer

P Answered by PhD

27

Question 1 - unlike or different poles

Question 2 - magnetic fields

Question 3 - 2

Question 4 - Iron, cobalt, and nickel

Question 5 - electrons

Question 6 - False

Question 7 - Electromagnets

Question 8 - True

Question 9 - molten iron in the Earth's core

Question 10 - True

Question 11 - False

I hope this helps

Mathematics

tea costs $4.48 for 8 ounces. what is the cost per one ounce? question 1 options: $1.79 per ounce $0.56 per ounce $35.84 per ounce $0.056 per ounce question 2 (2 points) jaziah bought 6 1/2 pounds of bananas for $5.20. what is the cost per pound of bananas? question 2 options: $0.08 per pound of bananas $0.88 per pound of bananas $0.80 per pound of bananas $0.89 per pound of bananas question 3 (2 points) the values in the table show the relationship between times measured in seconds and distances measured in meters. seconds (x) meters (y) 5 20

Step-by-step answer

P Answered by PhD

2

Q1. 0.56

Q2. 0.08

Q3. 5 mps

Q4. 24

Q5. 0.69

Q6. 48 mph

Q7. 5.05

hope this helps!

Based on my answers from number 1 & 2 I need help with question 3 and 4 the graph

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