12.11.2022

Question 3 of 10
What is i^30?
O A. -1
B. -1
C. i
O D. 1
SUB

. 0

Step-by-step answer

09.07.2023, solved by verified expert
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-1

Step-by-step explanation:

Rewrite

Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Factor out Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Rewrite Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Rewrite Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Rewrite Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Rewrite Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Raise -1 to the power of 2.

Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

One to any power is one.

Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22

Multiply Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22  by 1.

Rewrite Question 3 of 10 What is i^30? O A. -1 B. -1, №18009907, 12.11.2022 03:22 as -1

[RevyBreeze]

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Mathematics
Step-by-step answer
P Answered by Master

-1

Step-by-step explanation:

Rewrite

i^3^0 as (i^4)^7i^2.

Factor out i^2^8.

i^2^8i^2

Rewrite i^2^8 as (i^4)^7

Rewrite i^4 as 1

Rewrite i^4 as (i^2)^2.

((i^2)^2)^7i^2

Rewrite i^2 as -1.

Raise -1 to the power of 2.

1^7i^2.

One to any power is one.

1i^2

Multiply i^2  by 1.

Rewrite i^2 as -1

[RevyBreeze]

Mathematics
Step-by-step answer
P Answered by PhD

1. -9p - 17 = 10

-9p = 10 + 17

-9p = 27

p = -3

2. w/4 - 4 = 3

w/4 =  3 + 4

w/4 = 7

w = 7 · 4

w = 28

3. x/5 + 6 = 10

x/5 = 10 - 6

x/5 = 4

x = 4 · 5

x = 20

4. -2(m - 30) = -6m

-2m + 60 = -6m

-2m + 6m = -60

4m = -60

m = -15

5. 3.75 + 3.7 = 1.7 + 1.75x

1.75x = 3.75 + 3.7 - 1.7

1.75x = 5.75

x = 23/7

6. -6 - 7(c + 10)

= -6 -7c - 70

= -76 - 7c

7. 2x + 3(x - 2) - 2(x - 6)

= 2x + 3x - 6 - 2x + 12

= 3x + 6

8. c + 6 -3

= c + 3

10. -5p > -30

p < 6

13.  29 - 5x = 4; $5.00

14. 64 + w = 2w + 8; 56 pounds

For Q#5, 7, 8, and 10, I got a different answer from the one you provided. I did it the way I was taught to do it, which might be different from what you were taught. Sorry about that; I tried my best.

Mathematics
Step-by-step answer
P Answered by PhD

1. -9p - 17 = 10

-9p = 10 + 17

-9p = 27

p = -3

2. w/4 - 4 = 3

w/4 =  3 + 4

w/4 = 7

w = 7 · 4

w = 28

3. x/5 + 6 = 10

x/5 = 10 - 6

x/5 = 4

x = 4 · 5

x = 20

4. -2(m - 30) = -6m

-2m + 60 = -6m

-2m + 6m = -60

4m = -60

m = -15

5. 3.75 + 3.7 = 1.7 + 1.75x

1.75x = 3.75 + 3.7 - 1.7

1.75x = 5.75

x = 23/7

6. -6 - 7(c + 10)

= -6 -7c - 70

= -76 - 7c

7. 2x + 3(x - 2) - 2(x - 6)

= 2x + 3x - 6 - 2x + 12

= 3x + 6

8. c + 6 -3

= c + 3

10. -5p > -30

p < 6

13.  29 - 5x = 4; $5.00

14. 64 + w = 2w + 8; 56 pounds

For Q#5, 7, 8, and 10, I got a different answer from the one you provided. I did it the way I was taught to do it, which might be different from what you were taught. Sorry about that; I tried my best.

Mathematics
Step-by-step answer
P Answered by PhD

The answers are as follows:

TrueFalseFalseFalseFalse

Step-by-step explanation:

Let us look at the statements one by one

1. The additive inverse of 10 is -10.

The additive inverse of a number is the opposite of a number with respect to sign.

The sum of a number and its additive inverse is zero.

10+(-10) = 10-10 = 0

This statement is true.

2. Zero is a positive number.

Zero is neither a positive number nor a negative number. It is only used as reference to decide whether a number is positive or negative.

This statement is false.

3. To divide two unlike signs, the quotient is always positive.

When two unlike signs are divided, the answer will be negative as division involves multiplication, and multiplication of two numbers with unlike signs will always be negative.

This statement is false.

4. Commutative Property states that:

a + (b + c ) = (a + b ) + c

Commutative property deals with two numbers or variables only. The property with three numbers or varibales is associative property. Hence,

This statement is false.

5. One is the identity element of for addition.

Additive identity is a number that when added to a number x, the result will always be x. Zero is additive identity.

Hence,

This statement is false.

The answers are as follows:

TrueFalseFalseFalseFalse
Mathematics
Step-by-step answer
P Answered by PhD

The answers are as follows:

TrueFalseFalseFalseFalse

Step-by-step explanation:

Let us look at the statements one by one

1. The additive inverse of 10 is -10.

The additive inverse of a number is the opposite of a number with respect to sign.

The sum of a number and its additive inverse is zero.

10+(-10) = 10-10 = 0

This statement is true.

2. Zero is a positive number.

Zero is neither a positive number nor a negative number. It is only used as reference to decide whether a number is positive or negative.

This statement is false.

3. To divide two unlike signs, the quotient is always positive.

When two unlike signs are divided, the answer will be negative as division involves multiplication, and multiplication of two numbers with unlike signs will always be negative.

This statement is false.

4. Commutative Property states that:

a + (b + c ) = (a + b ) + c

Commutative property deals with two numbers or variables only. The property with three numbers or varibales is associative property. Hence,

This statement is false.

5. One is the identity element of for addition.

Additive identity is a number that when added to a number x, the result will always be x. Zero is additive identity.

Hence,

This statement is false.

The answers are as follows:

TrueFalseFalseFalseFalse
Chemistry
Step-by-step answer
P Answered by Master

c. 6,3x10⁻¹¹M

Explanation:

The solubility of a buffer is defined as the concentration of the dissolved solid in a saturated solution. For the Cd(OH)₂, solubility is:

[Cd²⁺] = S

The dissolution of Cd(OH)₂ is:

Cd(OH)₂ ⇄ Cd²⁺ + 2OH⁻

And the ksp is defined as:

ksp = [Cd²⁺][OH⁻]²

As ksp = 2,5x10⁻¹⁴ and [OH⁻] at pH=12,30 = 10^-(14-12,30) = 0,01995M

2,5x10⁻¹⁴ = [Cd²⁺]×(0,01995M)²

[Cd²⁺] = 6,3x10⁻¹¹M

That means solubility is c. 6,3x10⁻¹¹M

I hope it helps!

Chemistry
Step-by-step answer
P Answered by Master

c. 6,3x10⁻¹¹M

Explanation:

The solubility of a buffer is defined as the concentration of the dissolved solid in a saturated solution. For the Cd(OH)₂, solubility is:

[Cd²⁺] = S

The dissolution of Cd(OH)₂ is:

Cd(OH)₂ ⇄ Cd²⁺ + 2OH⁻

And the ksp is defined as:

ksp = [Cd²⁺][OH⁻]²

As ksp = 2,5x10⁻¹⁴ and [OH⁻] at pH=12,30 = 10^-(14-12,30) = 0,01995M

2,5x10⁻¹⁴ = [Cd²⁺]×(0,01995M)²

[Cd²⁺] = 6,3x10⁻¹¹M

That means solubility is c. 6,3x10⁻¹¹M

I hope it helps!

Mathematics
Step-by-step answer
P Answered by Master

D

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate of the denominator.

Note that i² = - 1

The conjugate of 10 + 3i is 10 - 3i , then

\frac{(3+5i)(10-3i)}{(10+3i)(10-3i)} ← Expand numerator/denominator using FOIL

= \frac{30-9i+50i-15i^2}{100-30i+30i-9i^2} ← simplify

= \frac{30+41i+15}{100+9}

= \frac{45+41i}{109} → D

Mathematics
Step-by-step answer
P Answered by Master

D

Step-by-step explanation:

Multiply the numerator and denominator by the conjugate of the denominator.

Note that i² = - 1

The conjugate of 10 + 3i is 10 - 3i , then

\frac{(3+5i)(10-3i)}{(10+3i)(10-3i)} ← Expand numerator/denominator using FOIL

= \frac{30-9i+50i-15i^2}{100-30i+30i-9i^2} ← simplify

= \frac{30+41i+15}{100+9}

= \frac{45+41i}{109} → D

Chemistry
Step-by-step answer
P Answered by PhD

Given:

The rate constant of the reaction, (K) = 2.3 × 10 -4 s-1

To find:

The half-life of a reaction.

Formula used:

Given:The rate constant of the reaction, (K) = 2.3 × 10 -4 s-1To find:The half-life of a reaction.Fo

The half-life of the reaction = 3.013 sec             (option A. is correct)

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