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01.10.2022

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21.05.2023, solved by verified expert

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Mathematics

Can I have help on this question, please? A teacher randomly chooses a two-person leadership team from a group of four qualified students. Three of the students, Sandra, Marta, and Jane, are girls. The fourth student, Franklin, is a boy. Using the sample space of possible outcomes listed below, where each student is represented by the first letter of his or her name, answer each of the following questions. What is P(A), the probability that the first student is a girl? What is P(B), the probability that the second student is a girl? What is P(A

Step-by-step answer

P Answered by Specialist

6

p(a)=3/4

p(b)=3/4

p(a and b)=1/2

not independent

Mathematics

1- a student purchases 6 different colored folders for her classes (red, blue, yellow, green, purple, and black). she randomly chooses two folders to use for her first two classes. what is the probability that her first choice is red and her second choice is blue? 1 36 1 30 1 5 1 6 2-while playing a board game, you roll two different colored standard dice. what is the probability of rolling a 5 on the black die and a number less than 4 on the red die? 1 10 2 3 1 2 1 12 3-you randomly draw cards from a standard deck and place them face up on the

Step-by-step answer

P Answered by Master

8

The first answer is

Step-by-step explanation:

1 /30

Mathematics

1- a student purchases 6 different colored folders for her classes (red, blue, yellow, green, purple, and black). she randomly chooses two folders to use for her first two classes. what is the probability that her first choice is red and her second choice is blue? 1 36 1 30 1 5 1 6 2-while playing a board game, you roll two different colored standard dice. what is the probability of rolling a 5 on the black die and a number less than 4 on the red die? 1 10 2 3 1 2 1 12 3-you randomly draw cards from a standard deck and place them face up on the

Step-by-step answer

P Answered by Master

8

The first answer is

Step-by-step explanation:

1 /30

Chemistry

Transformation of Energy Lab Report Instructions: In Part One of the Transformation of Energy lab, you will research and experiment with a Rube Goldberg Machine simulation to show the transformation of energy from one object to another to complete a simple task. In Part Two, you will design your own Rube Goldberg device. Record your observations and work in the lab report below. You will submit your completed lab report for both Part One and Part Two of the lab. Name and Title: Title of Lab: Student Name: Instructor: Date: Part One: Rube Goldberg

Step-by-step answer

P Answered by PhD

54

The guy copy and pasted it from answer from 2018 just so you know

Explanation:

Spanish

Worth 99 points read and choose the correct option. a teacher talking to a student the first day of class: señora vila: sara, tú 1. la mochila y los libros en mi clase. ¿tienes el uniforme? sara: no. yo 2. el uniforme. ¿yo 3. un cuaderno, señora vila? señora vila: sí, sara, tú 4. un cuaderno y unos lápices. 1. necesito 2. necesito 3. necesitas 4. necesita 1. necesitas 2. necesito 3. necesito 4. necesitas 1. necesitas 2. necesita 3. necesita 4. necesito 1. necesita 2. necesitas 3. necesito 4. necesito

Step-by-step answer

P Answered by Master

4

necesitas

necesito

necesita

necesitos

hope this helps

Chemistry

Transformation of Energy Lab Report Instructions: In Part One of the Transformation of Energy lab, you will research and experiment with a Rube Goldberg Machine simulation to show the transformation of energy from one object to another to complete a simple task. In Part Two, you will design your own Rube Goldberg device. Record your observations and work in the lab report below. You will submit your completed lab report for both Part One and Part Two of the lab. Name and Title: Title of Lab: Student Name: Instructor: Date: Part One: Rube Goldberg

Step-by-step answer

P Answered by PhD

54

The guy copy and pasted it from answer from 2018 just so you know

Explanation:

Spanish

Worth 99 points read and choose the correct option. a teacher talking to a student the first day of class: señora vila: sara, tú 1. la mochila y los libros en mi clase. ¿tienes el uniforme? sara: no. yo 2. el uniforme. ¿yo 3. un cuaderno, señora vila? señora vila: sí, sara, tú 4. un cuaderno y unos lápices. 1. necesito 2. necesito 3. necesitas 4. necesita 1. necesitas 2. necesito 3. necesito 4. necesitas 1. necesitas 2. necesita 3. necesita 4. necesito 1. necesita 2. necesitas 3. necesito 4. necesito

Step-by-step answer

P Answered by Specialist

4

necesitas

necesito

necesita

necesitos

hope this helps

Physics

An inquisitive physics student and mountain climber climbs a 52.0 m cliff that overhangs a calm pool of water. he throws (not drops) two stones vertically downward, 1.00 s apart, and observes that they cause a single splash. the first stone has an initial speed of 2.05 m/s downward. hint: because the motion is only in the downward direction, choose the positive y-axis to point downward.(a) how long after release of the first stone do the two stones hit the water? (b) what initial velocity must the second stone have if they are to hit simultaneously?

Step-by-step answer

P Answered by PhD

Part a)

t = 3.06 s

Part b)

v_2 = 15.22 m/s

Part c)

$v_{2f} = 35.4 m/s$

Explanation:

Part a)

as we know that speed of the stone is 2.05 m/s

displacement of the stone is 52 m downwards

now we can use kinematics

$d = v_i t + \frac{1}{2}at^2$

$52 = 2.05 t + \frac{1}{2}(9.8)t^2$

4.9 t^2 + 2.05 t - 52 = 0

t = 3.06 s

Part b)

Since second stone is projected downwards with speed v after time t = 1 s

so relative separation between two stones is given as

$d = vt + \frac{1}{2}at^2$

$d = (2.05)(1.00) + \frac{1}{2}(9.8)(1^2)$

d = 6.95 m

so now we can say that if both stone hit the water simultaneously so here second stone will approach 1st atone after t = 3.06 - 1 = 2.06 s

so we have

$v_{rel} t = d_{rel}[tex](v_2 - v_1) \times (2.06)= 6.95$

here v1 is the speed of first stone after t = 1 s

v_1 = 2.05 + 9.8(1) = 11.85 m/s

now we will have

$v_2 - 11.85 = \frac{6.95}{2.06}$

v_2 = 15.22 m/s

Part c)

speed of first atone when it hit the water

$v_{1f} = v_1 + at$

$v_{1f} = 2.05 + (9.81)(3.06)$

$v_{1f} = 32.1 m/s$

speed of 2nd stone when it will hit the water

$v_{2f} = v_2 + at$

$v_{2f} = 15.22 + (9.81)(2.06)$

$v_{2f} = 35.4 m/s$

Mathematics

1. a bag contains 5 red marbles and 4 green marbles. what is the probability of choosing a red marble then a green marble, without replacement? 25/81 20/81 5/18 25/72 2. adam, jack and sheila are the three seniors who have been elected to student council. the president and vice president are randomly selected from these three seniors by drawing their names from a hat. what is the probability that jack will be selected first for president and sheila will be selected second for vice president? 5/6 1/9 2/3 1/6 3. john rolls a six-sided number cube

Step-by-step answer

P Answered by PhD

13

1) probability=number of specific outcomes/number of possible outcomes.

probability of two events occurring is the product of the two probabilities.

So without replacement:

P(RandG)=(5/9)*(4/8)=5/18

2)

P(JandS)=(1/3)(1/2)=1/6

3)

P(EandO)=(1/2)(1/2)=1/4

4)

P(3Cand3I)=(1/2)(1/2)(1/2)(1/2)(1/2)(1/2)=(1/2)^6=1/64

Mathematics

1. a bag contains 5 red marbles and 4 green marbles. what is the probability of choosing a red marble then a green marble, without replacement? 25/81 20/81 5/18 25/72 2. adam, jack and sheila are the three seniors who have been elected to student council. the president and vice president are randomly selected from these three seniors by drawing their names from a hat. what is the probability that jack will be selected first for president and sheila will be selected second for vice president? 5/6 1/9 2/3 1/6 3. john rolls a six-sided number cube

Step-by-step answer

P Answered by PhD

13

1) probability=number of specific outcomes/number of possible outcomes.

probability of two events occurring is the product of the two probabilities.

So without replacement:

P(RandG)=(5/9)*(4/8)=5/18

2)

P(JandS)=(1/3)(1/2)=1/6

3)

P(EandO)=(1/2)(1/2)=1/4

4)

P(3Cand3I)=(1/2)(1/2)(1/2)(1/2)(1/2)(1/2)=(1/2)^6=1/64

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