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25.12.2022

Surface Area of 40,40,40

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24.06.2023, solved by verified expert

Bhaskar Singh Bora

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64000

Step-by-step explanation:

40×40×40

Multiply 40 and 40 to get 1600.

1600×40

Multiply 1600 and 40 to get 64000.

64000

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Mathematics

Surface Area of 40,40,40

Step-by-step answer

P Answered by PhD

64000

Step-by-step explanation:

40×40×40

Multiply 40 and 40 to get 1600.

1600×40

Multiply 1600 and 40 to get 64000.

64000

Physics

Assume that the surface temperature of the lightbulb filament when it is plugged into an outlet of 120 v is about 3000 k and the power rating of the bulb is the electric energy it consumes (not what it radiates). incandescent lightbulbs usually radiate in visible light about 10% of the electric energy that they consume. estimate the surface area of a 40-watt lightbulb filament. express your answer with the appropriate units. a = 8.7×10−7 m2

Step-by-step answer

P Answered by Specialist

A= $8.7\times 10^{-7}m^{2}$

Explanation:

We have given power =40 W but only 10% of this power is used so actual power $P=\frac{40\times 10}{100}=4 W$

We know that from Stefan's law $p=\sigma AT^4$ where $\sigma$ is Boltzmann constant which value is $5.6\times 10^{-8}Wm^{-2}K^{-4}$

So $4=5.67\times 10^{-8}\times A\times 3000^4$

A= $8.7\times 10^{-7}m^{2}$

Physics

Step-by-step answer

P Answered by Specialist

A= $8.7\times 10^{-7}m^{2}$

Explanation:

We have given power =40 W but only 10% of this power is used so actual power $P=\frac{40\times 10}{100}=4 W$

We know that from Stefan's law $p=\sigma AT^4$ where $\sigma$ is Boltzmann constant which value is $5.6\times 10^{-8}Wm^{-2}K^{-4}$

So $4=5.67\times 10^{-8}\times A\times 3000^4$

A= $8.7\times 10^{-7}m^{2}$

Mathematics

Step-by-step answer

P Answered by PhD

Given the two similar solids as shown in the diagram:

a. Volume of Solid B = $\mathbf{480 $ cm^3}$

b. Surface Area of Solid A = $\mathbf{35 $ cm^2}$

Given that the two solids, A and B, are similar, therefore, assuming they have a pair of corresponding dimension, given as, a and b respectively, thus:

$\mathbf{\frac{Vol_A}{Vol_B} = \frac{a^3}{b^3}}$ (ratio of their volume to their corresponding sides) $\mathbf{\frac{A_A}{A_B} = \frac{a^2}{b^2}}$ (ratio of their surface area to their corresponding sides)

Thus:

a. Volume of Solid A = 60 $ cm^3

a = 3 cm

b = 6 cm

Substitute

$\frac{60}{Vol_B} = \frac{3^3}{6^3}\\\\\frac{60}{Vol_B} = \frac{27}{216}\\\\Vol_B = \frac{216 \times 60}{27} \\\\\mathbf{Vol_B = 480 $ cm^3}$

a. Area of Solid B = 140 $ cm^2

a = 3 cm

b = 6 cm

Substitute

$\frac{A_A}{140} = \frac{3^2}{6^2}\\\\\frac{A_A}{140} = \frac{9}{36}\\\\A_A = \frac{9 \times 140}{36} \\\\\mathbf{A_A = 35 $ cm^2}$

Therefore, given the two similar solids as shown in the diagram:

a. Volume of Solid B = $\mathbf{480 $ cm^3}$

b. Surface Area of Solid A = $\mathbf{35 $ cm^2}$

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Mathematics

The diagram shows a solid hemisphere. Surface area of a sphere = 40r2 Volume of a sphere = ar3 cm? The hemisphere has a total surface area of - The hemisphere has a volume of kn cm Find the value of k.

Step-by-step answer

P Answered by Specialist

Explanation:

This question has missing diagram, but I'll try to help you either way. We know that the surface area of a sphere is given by:

$S=4\pi r^2 \\ \\ \\ Where: \\ \\ r:\text{radius of the sphere}$

On the other hand, the volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

1. The hemisphere has a total surface area of:

The total surface area of the hemisphere is half the surface area of a sphere plus the area of the base of the hemisphere which is a circular base with radius r, in other words:

$S_{h}: \text{Surface area of the hemisphere} \\ \\ S_{h}=\frac{4\pi r^2}{2}+\pi r^2 \\ \\ s_{h}=2\pi r^2 + \pi r^2 \\ \\ s_{h}=3\pi r^2$

2. The hemisphere has a volume of kn cm^3 . Find the value of k.

As I understand this question we want to know what is the value of k given the volume of a sphere, in other words, the volume of a sphere is:

$V=\frac{4}{3}\pi r^3$

And the volume of a hemisphere is:

$V_{h}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

So the hemisphere has a volume:

$V_{h}=\frac{1}{2}V$

In other words:

$k=\frac{1}{2}$

Mathematics

Cylinder A is mathematically similar to cylinder B. The height of cylinder A is 10cm and its surface area is 440cm2 . The surface area of cylinder B is 3960cm2 . Calculate the height of cylinder B

Step-by-step answer

P Answered by PhD

$440 = 2\pi {r}^{2} + 2\pi(r)10 \\$

$3960 = 2\pi {r}^{2} + 2\pi(r)h$

$\frac{3960 = 2\pi {r}^{2} + 2\pi(r)h}{440 = 2\pi {r }^{2} + 2\pi(r)10 }$

$9 = \frac{h}{10}$

h=90

Mathematics

Step-by-step answer

P Answered by PhD

Given the two similar solids as shown in the diagram:

a. Volume of Solid B = $\mathbf{480 $ cm^3}$

b. Surface Area of Solid A = $\mathbf{35 $ cm^2}$

Given that the two solids, A and B, are similar, therefore, assuming they have a pair of corresponding dimension, given as, a and b respectively, thus:

Thus:

a. Volume of Solid A = 60 $ cm^3

a = 3 cm

b = 6 cm

Substitute

$\frac{60}{Vol_B} = \frac{3^3}{6^3}\\\\\frac{60}{Vol_B} = \frac{27}{216}\\\\Vol_B = \frac{216 \times 60}{27} \\\\\mathbf{Vol_B = 480 $ cm^3}$

a. Area of Solid B = 140 $ cm^2

a = 3 cm

b = 6 cm

Substitute

$\frac{A_A}{140} = \frac{3^2}{6^2}\\\\\frac{A_A}{140} = \frac{9}{36}\\\\A_A = \frac{9 \times 140}{36} \\\\\mathbf{A_A = 35 $ cm^2}$

Therefore, given the two similar solids as shown in the diagram:

a. Volume of Solid B = $\mathbf{480 $ cm^3}$

b. Surface Area of Solid A = $\mathbf{35 $ cm^2}$

Learn more here:

link

Mathematics

Cylinder A is mathematically similar to cylinder B. The height of cylinder A is 10cm and its surface area is 440cm2 . The surface area of cylinder B is 3960cm2 . Calculate the height of cylinder B

Step-by-step answer

P Answered by PhD

$440 = 2\pi {r}^{2} + 2\pi(r)10 \\$

$3960 = 2\pi {r}^{2} + 2\pi(r)h$

$\frac{3960 = 2\pi {r}^{2} + 2\pi(r)h}{440 = 2\pi {r }^{2} + 2\pi(r)10 }$

$9 = \frac{h}{10}$

h=90

Computers and Technology

Hydraulic pressure is the same throughout the inside of a set of brake lines. What determines the amount of resulting mechanical force is the size of the piston in the wheel cylinder or caliper. For example: 100 psi of fluid pressure acting against a caliper piston with 4 square inches of surface area will result in 400 lbs of clamping force. A fluid line with 200 psi in it acting against a piston with 3 square inches of area would result in 600 lbs of force. A fluid line with 50 psi acting on a larger piston with 12 square inches of surface area

Step-by-step answer

P Answered by Master

1000 square ponds of force hope you know the answer

Explanation: i guessed

Mathematics

Step-by-step answer

P Answered by Specialist

Explanation:

This question has missing diagram, but I'll try to help you either way. We know that the surface area of a sphere is given by:

$S=4\pi r^2 \\ \\ \\ Where: \\ \\ r:\text{radius of the sphere}$

On the other hand, the volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

1. The hemisphere has a total surface area of:

The total surface area of the hemisphere is half the surface area of a sphere plus the area of the base of the hemisphere which is a circular base with radius r, in other words:

$S_{h}: \text{Surface area of the hemisphere} \\ \\ S_{h}=\frac{4\pi r^2}{2}+\pi r^2 \\ \\ s_{h}=2\pi r^2 + \pi r^2 \\ \\ s_{h}=3\pi r^2$

2. The hemisphere has a volume of kn cm^3 . Find the value of k.

As I understand this question we want to know what is the value of k given the volume of a sphere, in other words, the volume of a sphere is:

$V=\frac{4}{3}\pi r^3$

And the volume of a hemisphere is:

$V_{h}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

So the hemisphere has a volume:

$V_{h}=\frac{1}{2}V$

In other words:

$k=\frac{1}{2}$

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