Daniel walked 2/5 mile in 1/4 hour. How fast, №17886154, 14.11.2022 23:54

Mathematics

Daniel walked 2/5 mile in 1/4 hour. How fast did he walk, in miles per hour?

Step-by-step answer

P Answered by PhD

2

Step-by-step explanation:

$v=\frac{d}{t}\\ \\ v=\frac{\frac{2}{5}}{\frac{1}{4}}\\ \\ v=\frac{2}{5}\left(\frac{4}{1}\right)\\ \\ v=\frac{8}{5}\\ \\ v=1.6\ \frac{mi}{hr}$

History

Faast will giving brainliest when reporting the speed, we need to include the value, units and direction the object was traveling. question 1 options: true false question 2 (1 point) saved when reporting the velocity of an object, we need to include the value, the units and the direction the object was traveling. question 2 options: true false question 3 (1 point) an object travels 10 meters to the right and 7 meters to the left, what distance has it traveled? question 3 options: 17 17 meters 3 3 meters question 4 (1 point) an object travels 5

Step-by-step answer

P Answered by Specialist

1

The answers to the questions asked are

question 1 : false

question 2: True

question 3: 17 meters

question 4: 2 meters

question 5: she did not do anything wrong

question 6: 28 mph

question 7: 12 mph

question 8: 0.27 m/s

question 9: True

question 10: false

Explanation:

question 1: speed is the total distance covered by an object over a given time regardless of the direction of the distance hence when reporting we report only the value and unit of the speed which ( km/h )or ( m/s )

question 2: velocity is change in distance covered by an object ( on a straight line) also known as displacement. over a given time by the object hence the direction of the object is considered

question 3: to calculate for distance traveled by an object you have to sum up the total distance traveled by the object on a straight line i.e ( 10 + 7 ) = 17 meters

question 4: displacement is change in distance traveled by an object on a straight line in opposite direction i.e ( 7 - 5 ) = 2 meters

question 5: displacement is change in distance traveled on a straight line in opposite direction hence her answer was correct i.e ( 13 - 10) = 3 meters

question 6: speed = distance/time equation 1

distance = 5 + 2 = 7 miles

time = 1/4 hour = 0.25 hour

equation 1 becomes

speed = 7/0.25 = 28 mph

question 7: Average velocity = displacement/time equation 1

displacement = 5 - 2 = 3 miles

time = 1/4 = 0.25 hour

equation 1 becomes

average velocity = 3/0.25 = 12 mph

question 8: Average speed = total distance / total time equation 1

total distance = 0.75 + 0.75 + 0.75 = 2.25 meters

this is considered the total distance because for each trial she covered ramp which was 0.75 meters

total time = 2.5 + 2.75 + 2.98 = 8.23 seconds

equation 1 becomes

average speed = 2.25 / 8.23 = 0.27 m/s

question 9: It is true because precise is a data that is repeated over and over which might not actually be the actual/correct value while accurate is the data that is closest to the known value

question 10: from the definition in question 9 above the answer is false

History

Faast will giving brainliest when reporting the speed, we need to include the value, units and direction the object was traveling. question 1 options: true false question 2 (1 point) saved when reporting the velocity of an object, we need to include the value, the units and the direction the object was traveling. question 2 options: true false question 3 (1 point) an object travels 10 meters to the right and 7 meters to the left, what distance has it traveled? question 3 options: 17 17 meters 3 3 meters question 4 (1 point) an object travels 5

Step-by-step answer

P Answered by Specialist

1

The answers to the questions asked are

question 1 : false

question 2: True

question 3: 17 meters

question 4: 2 meters

question 5: she did not do anything wrong

question 6: 28 mph

question 7: 12 mph

question 8: 0.27 m/s

question 9: True

question 10: false

Explanation:

question 1: speed is the total distance covered by an object over a given time regardless of the direction of the distance hence when reporting we report only the value and unit of the speed which ( km/h )or ( m/s )

question 2: velocity is change in distance covered by an object ( on a straight line) also known as displacement. over a given time by the object hence the direction of the object is considered

question 3: to calculate for distance traveled by an object you have to sum up the total distance traveled by the object on a straight line i.e ( 10 + 7 ) = 17 meters

question 4: displacement is change in distance traveled by an object on a straight line in opposite direction i.e ( 7 - 5 ) = 2 meters

question 5: displacement is change in distance traveled on a straight line in opposite direction hence her answer was correct i.e ( 13 - 10) = 3 meters

question 6: speed = distance/time equation 1

distance = 5 + 2 = 7 miles

time = 1/4 hour = 0.25 hour

equation 1 becomes

speed = 7/0.25 = 28 mph

question 7: Average velocity = displacement/time equation 1

displacement = 5 - 2 = 3 miles

time = 1/4 = 0.25 hour

equation 1 becomes

average velocity = 3/0.25 = 12 mph

question 8: Average speed = total distance / total time equation 1

total distance = 0.75 + 0.75 + 0.75 = 2.25 meters

this is considered the total distance because for each trial she covered ramp which was 0.75 meters

total time = 2.5 + 2.75 + 2.98 = 8.23 seconds

equation 1 becomes

average speed = 2.25 / 8.23 = 0.27 m/s

question 9: It is true because precise is a data that is repeated over and over which might not actually be the actual/correct value while accurate is the data that is closest to the known value

question 10: from the definition in question 9 above the answer is false

Mathematics

You and a friend start hiking toward each other from opposite ends of a 17.5-mile hiking trail. you hike 2/3 mile every 1/4 hour. your friend hikes 2 1/3 miles per hour. a. who hikes faster? how much faster? b. after how many hours did you meet? c. when you meet, who hiked farther? how much farther? answer this asap! you!

Step-by-step answer

P Answered by Master

a. I hike faster by $\frac{8}{7}$ times faster;

b. You meet after 3.5 hours;

c. I hiked 1.167 miles farther than my friend;

Step-by-step explanation: a) To determine who hiked faster, we have to find speed of each person:

I hike 2/3 mile every 1/4 hour, so:

speed = $\frac{2}{3}$ ÷ $\frac{1}{4}$

speed = $\frac{2}{3}$ .4 = $\frac{8}{3}$

speed = 2.667 mph

My friend hikes $2.\frac{1}{3}$ mph:

speed = $\frac{7}{3}$

speed = 2.334 mph

Comparing the speed, I hike faster than my friend by:

$\frac{\frac{8}{3} }{\frac{7}{3} }$ = $\frac{8}{3} . \frac{3}{7}$ = $\frac{8}{7}$ times faster.

b) Suppose time in hours is t.

I hiked a distance of $\frac{8}{3}$ t

My friend hiked a distance of $\frac{7}{3}$ t

They will meet when the sum of the distances equals 17.5 miles:

$\frac{8}{3}.t + \frac{7}{3}.t = 17.5$

$\frac{15}{3}$ t = 17.5

t = 3.5 h

After 3 and a half hours, my friend and I meet.

c) To know who hiked farther, we determine the distance my friend and I hiked when we met:

distance for me: $\frac{8}{3}$ t

distance when we met: $\frac{8}{3}$ .3.5 = 9.334 miles

distance for mu friend: $\frac{7}{3}$ t

distance when we met: $\frac{7}{3}$ .3.5 = 8.167 miles

When we met, I hiked 9.334 - 8.167 = 1.167 miles farther than my friend.

Mathematics

You and a friend start hiking toward each other from opposite ends of a 17.5-mile hiking trail. you hike 2/3 mile every 1/4 hour. your friend hikes 2 1/3 miles per hour. a. who hikes faster? how much faster? b. after how many hours did you meet? c. when you meet, who hiked farther? how much farther? answer this asap! you!

Step-by-step answer

P Answered by PhD

13

Since you hike $\frac{2}{3}$ miles every $\frac{1}{4}$ hour, you'll hike $\frac{2}{3}*4=\frac{8}{3}=2\frac{2}{3}$ every hour. Comparing this to your friend's rate, we can see that you hike more miles in one hour. You hike $\frac{\frac{8}{3}}{\frac{7}{3}}=\frac{8}{3}*\frac{3}{7}=\frac{8}{7}$ times faster.

a) You hike faster. You hike $\frac{8}{7}$ times faster.

The two of you will meet when the total distance you've traveled sum up to 17.5

miles. You can find the distance both you and your friends traveled by multiplying your rate with the time you've been hiking. Since you both need to arrive at the same time, we will assign the same variable, t, to determine after how many hours you will meet.

$\frac{8}{3}t+ \frac{7}{3}t=17.5$
$\frac{15}{3}t=17.5$
$t=17.5*\frac{3}{15}=3.5$

b. The two of you will meet after 3.5 hours.

As said earlier, we just multiply the rate with the number of hours you've traveled to find the distance you've hiked.

You traveled: $\frac{8}{3}* \frac{7}{2} = \frac{28}{3}=9.33$ miles
Your friend traveled: $\frac{7}{3}* \frac{7}{2} = \frac{49}{6}=8.17$ miles

You hiked $\frac{28}{3}-\frac{49}{6} = \frac{7}{6}=1.167$ miles farther.

c)You hiked farther. You hiked 1.167 miles farther.

Mathematics

You and a friend start hiking toward each other from opposite ends of a 17.5-mile hiking trail. you hike 2/3 mile every 1/4 hour. your friend hikes 2 1/3 miles per hour. a. who hikes faster? how much faster? b. after how many hours did you meet? c. when you meet, who hiked farther? how much farther? answer this asap! you!

Step-by-step answer

P Answered by PhD

13

Since you hike $\frac{2}{3}$ miles every $\frac{1}{4}$ hour, you'll hike $\frac{2}{3}*4=\frac{8}{3}=2\frac{2}{3}$ every hour. Comparing this to your friend's rate, we can see that you hike more miles in one hour. You hike $\frac{\frac{8}{3}}{\frac{7}{3}}=\frac{8}{3}*\frac{3}{7}=\frac{8}{7}$ times faster.

a) You hike faster. You hike $\frac{8}{7}$ times faster.

The two of you will meet when the total distance you've traveled sum up to 17.5

miles. You can find the distance both you and your friends traveled by multiplying your rate with the time you've been hiking. Since you both need to arrive at the same time, we will assign the same variable, t, to determine after how many hours you will meet.

$\frac{8}{3}t+ \frac{7}{3}t=17.5$
$\frac{15}{3}t=17.5$
$t=17.5*\frac{3}{15}=3.5$

b. The two of you will meet after 3.5 hours.

As said earlier, we just multiply the rate with the number of hours you've traveled to find the distance you've hiked.

You traveled: $\frac{8}{3}* \frac{7}{2} = \frac{28}{3}=9.33$ miles
Your friend traveled: $\frac{7}{3}* \frac{7}{2} = \frac{49}{6}=8.17$ miles

You hiked $\frac{28}{3}-\frac{49}{6} = \frac{7}{6}=1.167$ miles farther.

c)You hiked farther. You hiked 1.167 miles farther.

Mathematics

Joseph ran LaTeX: 2 frac{3}{4}2 3 4 miles in LaTeX: frac{2}{5}2 5 of an hour. How fast did Lin run in 1 hour? (try to leave your answer in a fraction) Nathaniel ran LaTeX: 8 frac{2}{3}8 2 3 miles in LaTeX: frac{4}{3}4 3 of an hour. How fast did Nathaniel run in 1 hour? (try to leave your answer in a fraction) Who ran the fastest, Nathaniel or Joseph?

Step-by-step answer

P Answered by PhD

Nathaniel ran fastest

Step-by-step explanation:

For Joseph

Joseph ran 2 3/4 miles 2 /5 of an hour.

Speed = Distance/Time

Speed = 2 3/4 miles ÷ 2/5 hour

= 11/4 ÷ 2/5

= 11/4 × 5/2

= 55/8 miles/hour or 6.875 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

2/5 hour = 55/8 miles per hour

1 hour = x

Cross Multiply

x = 55/8 ÷ 2/5

x = 55/8 × 5/2

x = 275/16 miles per hour

x = 17 3/16 miles per hour

Nathaniel ran LaTeX: 8 2/3 miles in 4 /3 of an hour. How fast did Nathaniel run in 1 hour? (try to leave your answer in a fraction)

Speed = Distance/Time

Speed = 8 2/3 miles ÷ 4/3hour

= 26/3 ÷ 4/3

= 26/3 × 3/4

= 26/4 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

4/3 hour = 26/4miles per hour

1 hour = x

Cross Multiply

x = 26/4 ÷ 4/3

x = 26/4 × 3/4

x = 78/16 miles per hour

x = 4 14/16 miles per hour

= 4 7/8 miles per hour

Who ran the fastest, Nathaniel or Joseph?

Hence, from the calculation above, Nathaniel ran fastest

Mathematics

Joseph ran LaTeX: 2 frac{3}{4}2 3 4 miles in LaTeX: frac{2}{5}2 5 of an hour. How fast did Lin run in 1 hour? (try to leave your answer in a fraction) Nathaniel ran LaTeX: 8 frac{2}{3}8 2 3 miles in LaTeX: frac{4}{3}4 3 of an hour. How fast did Nathaniel run in 1 hour? (try to leave your answer in a fraction) Who ran the fastest, Nathaniel or Joseph?

Step-by-step answer

P Answered by PhD

Nathaniel ran fastest

Step-by-step explanation:

For Joseph

Joseph ran 2 3/4 miles 2 /5 of an hour.

Speed = Distance/Time

Speed = 2 3/4 miles ÷ 2/5 hour

= 11/4 ÷ 2/5

= 11/4 × 5/2

= 55/8 miles/hour or 6.875 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

2/5 hour = 55/8 miles per hour

1 hour = x

Cross Multiply

x = 55/8 ÷ 2/5

x = 55/8 × 5/2

x = 275/16 miles per hour

x = 17 3/16 miles per hour

Nathaniel ran LaTeX: 8 2/3 miles in 4 /3 of an hour. How fast did Nathaniel run in 1 hour? (try to leave your answer in a fraction)

Speed = Distance/Time

Speed = 8 2/3 miles ÷ 4/3hour

= 26/3 ÷ 4/3

= 26/3 × 3/4

= 26/4 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

4/3 hour = 26/4miles per hour

1 hour = x

Cross Multiply

x = 26/4 ÷ 4/3

x = 26/4 × 3/4

x = 78/16 miles per hour

x = 4 14/16 miles per hour

= 4 7/8 miles per hour

Who ran the fastest, Nathaniel or Joseph?

Hence, from the calculation above, Nathaniel ran fastest

Mathematics

yesterday Noah ran 2 1/2 miles in 3/5 hour. emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour. how fast, in miles per hour, did each person run? who ran the fastest.

Step-by-step answer

P Answered by Master

3

Anna

Step-by-step explanation:

she was the fastest

Mathematics

Mr. anderson drove 168 miles in 3 1/2 hours. he then drove the next 2 1/4 hours at a rate of 5 miles per hour faster than the first rate. how many miles did mr. anderson drive during the 5 3/4 hour road trip? answer in improper fraction.

Step-by-step answer

P Answered by Specialist

7

First we need to know how many miles per hour they drove the first time. This would be found by division. 168/3.5=48
Then we need to add 5 miles per hour for the average.48+5= 53
Next we need to multiply 2 1/4 by the new miles per hour 53*2.25=119.25
After that we need to know how many miles they drove 119.25+168=287.25 miles.
Finally to get an improper fraction we need to change 287.25 miles to it.
We already have 1/4 for .25 so we multiply 287 by 4 and add it to the 1/4 we already have and it makes it out to be 1149/4

Hope this helps!

Daniel walked 2/5 mile in 1/4 hour. How fast did he walk, in miles per hour?

Step-by-step answer

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