Mathematics : asked on timozy95
 19.07.2021

The principal is 2200.00 and the rate of interest is 7% what is the final account balance after two years

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24.06.2023, solved by verified expert
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2508

Step-by-step explanation:

We are given that

Principal ,P=2200

Rate of interest, r=7%

Time, t=2 year

We have to find the final account balance after two years.

The principal is 2200.00 and the rate of interest, №17886236, 19.07.2021 10:57

Using the formula

The principal is 2200.00 and the rate of interest, №17886236, 19.07.2021 10:57

Amount=P+S.I

Amount=2200+308

Amount=2508

Hence,  the final account balance after two years=2508

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Mathematics
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P Answered by PhD

2508

Step-by-step explanation:

We are given that

Principal ,P=2200

Rate of interest, r=7%

Time, t=2 year

We have to find the final account balance after two years.

S.I=\frac{P\times r\times t}{100}

Using the formula

S.I=\frac{2200\times 7\times 2}{100}=308

Amount=P+S.I

Amount=2200+308

Amount=2508

Hence,  the final account balance after two years=2508

Mathematics
Step-by-step answer
P Answered by PhD

Answers:

13. E 8500 < x < 12,000

14. D 6∠x∠8

15. E 1600 < x < 2200

16.  A1.02s > t > 0 s

17. 6.25 years

18. A5000 > (1500)(10)x

19. E 20.3 < 35 - 9.8t < 30.1

20. D$4167

Step-by-step explanation:

13.E 8500 < x < 12,000 ( the amount of money spent lies between 8500 and $12,000)

14. D 6∠x∠8 (subtracting 2 from both 8 and 10 will give 6 and 8 hours respectively

15. E 1600 < x < 2200 subtracting 600 calories for women

16. A1.02s > t > 0 s puttin the value of t=12,20

17. 6.25 years using the formula I=P*R*T/100

18.  A5000 > (1500)(10)x

19.E 20.3 < 35 - 9.8t < 30.1

20  D$4167

Mathematics
Step-by-step answer
P Answered by PhD

Answers:

13. E 8500 < x < 12,000

14. D 6∠x∠8

15. E 1600 < x < 2200

16.  A1.02s > t > 0 s

17. 6.25 years

18. A5000 > (1500)(10)x

19. E 20.3 < 35 - 9.8t < 30.1

20. D$4167

Step-by-step explanation:

13.E 8500 < x < 12,000 ( the amount of money spent lies between 8500 and $12,000)

14. D 6∠x∠8 (subtracting 2 from both 8 and 10 will give 6 and 8 hours respectively

15. E 1600 < x < 2200 subtracting 600 calories for women

16. A1.02s > t > 0 s puttin the value of t=12,20

17. 6.25 years using the formula I=P*R*T/100

18.  A5000 > (1500)(10)x

19.E 20.3 < 35 - 9.8t < 30.1

20  D$4167

Mathematics
Step-by-step answer
P Answered by PhD

Part 1) 8.3\ years  

Part 2) \$2,424.27  

Part 3) \$2,266.02  

Part 4) In the procedure

Step-by-step explanation:

Part 1) we know that    

The compound interest formula is equal to  

A=P(1+i)^{n}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

i is the interest  rate  in decimal

n is number of years  

n is the number of times interest is compounded per year

in this problem we have  

P=\$2,200\\ A=\$2,500\\ r=0.0155\\n=?  

substitute in the formula above  

\$2,500=\$2,200(1+0.0155)^{n}  

(2,500/2,200)=(1.0155)^{n}  

Applying log both sides

log(2,500/2,200)=(n)log(1.0155)  

n=log(2,500/2,200)/log(1.0155)

n=8.3\ years  

Part 2)

in this problem we have  

P=?\\ A=\$2,500\\ r=0.0155\\n=2\ years  

substitute in the formula above  

\$2,500=P(1+0.0155)^{2}  

\$2,500=P(1.0155)^{2}  

P=\$2,500/(1.0155)^{2}  

P=\$2,424.27  

Part 3) in this problem we have  

P=\$2,000\\ r=0.018\\n=7\ years  

substitute in the formula above  

P=\$2,000(1+0.018)^{7}=\$2,266.02  

The money is not enough

Part 4)

I would personally increase the investment from 2,200 dollars so that it grows to 2,500 dollars at the time I want to make the trip, for example if I wanted to make the trip in two years, I would increase the initial investment from 2200 dollars to 2427 dollars.

Mathematics
Step-by-step answer
P Answered by PhD

Part 1) 8.3\ years  

Part 2) \$2,424.27  

Part 3) \$2,266.02  

Part 4) In the procedure

Step-by-step explanation:

Part 1) we know that    

The compound interest formula is equal to  

A=P(1+i)^{n}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

i is the interest  rate  in decimal

n is number of years  

n is the number of times interest is compounded per year

in this problem we have  

P=\$2,200\\ A=\$2,500\\ r=0.0155\\n=?  

substitute in the formula above  

\$2,500=\$2,200(1+0.0155)^{n}  

(2,500/2,200)=(1.0155)^{n}  

Applying log both sides

log(2,500/2,200)=(n)log(1.0155)  

n=log(2,500/2,200)/log(1.0155)

n=8.3\ years  

Part 2)

in this problem we have  

P=?\\ A=\$2,500\\ r=0.0155\\n=2\ years  

substitute in the formula above  

\$2,500=P(1+0.0155)^{2}  

\$2,500=P(1.0155)^{2}  

P=\$2,500/(1.0155)^{2}  

P=\$2,424.27  

Part 3) in this problem we have  

P=\$2,000\\ r=0.018\\n=7\ years  

substitute in the formula above  

P=\$2,000(1+0.018)^{7}=\$2,266.02  

The money is not enough

Part 4)

I would personally increase the investment from 2,200 dollars so that it grows to 2,500 dollars at the time I want to make the trip, for example if I wanted to make the trip in two years, I would increase the initial investment from 2200 dollars to 2427 dollars.

Mathematics
Step-by-step answer
P Answered by Master

SEE EXPLANATIONS

Step-by-step explanation:

PART 1:

you have 2,200 and interest is 1.55%

A = 2200(1+0.0155)1   A = 2,234.10

A = 2200(1+0.0155)10   A = 2,565.80

A = 2200(1+0.0155)9   A = 2,526.63

A = 2200(1+0.0155)8   A = 2,488.07

9 Years with $2,526.63


PART 2:

A = 2425(1+0.0155)2   A = 2,500.76

You need to invest $2,425.00


PART 3:

A = 2000(1+0.018)7   A = 2,266.02

You have $2,266.02 which is underbudget


PART 4:

Personally, I would add to the investment of $2,200 so that it will grow to $2,500 faster. If I waited for just the $2,200 to grow alone it would take 9 years and if I'm looking at a trip now I would like to go sooner. So if I keep adding to the original $2,200 overtime it will collect interest faster and I would be able to take the trip sooner. I justify my answer with PART 2.

Mathematics
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P Answered by PhD
Answer: 440 grams for 1.54 is the better value
Explanation:
Take the price and divide by the number of grams
1.54 / 440 =0.0035 per gram
1.26 / 340 =0.003705882 per gram
0.0035 per gram < 0.003705882 per gram
Mathematics
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P Answered by PhD

The answer is in the image 

The answer is in the image 
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Step-by-step answer
P Answered by PhD

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

Mathematics
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P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

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