20.12.2022

Move values to the lines to complete each equation.
|8| =
|-8| =
-|8| =
-|-8| =

. 0

Step-by-step answer

24.06.2023, solved by verified expert
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1 students found this answer . helpful

I think this is what you meant not sure tho

Step-by-step explanation:

|8| = correct as it is

|-8| = correct as it is

-|8| = |-8|

-|-8| = |8|

It is was helpful?

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Mathematics
Step-by-step answer
P Answered by PhD

I think this is what you meant not sure tho

Step-by-step explanation:

|8| = correct as it is

|-8| = correct as it is

-|8| = |-8|

-|-8| = |8|

Mathematics
Step-by-step answer
P Answered by Specialist

1.-t₁  =  0,625 s

2.-h(max)  =  6,25 f

3.-t = 1,25 s

Step-by-step explanation:

V₀  =  20 f/s

h(t)  =  - 16*t² + 20*t

h(max)  =  ??

h´(t)  = - 32*t + 20

h(max) will occurs when  V = 0   dh/dt  = 0  then

- 32*t  + 20  = 0

- 32*t  =  -20

t  =  20/32

t₁  =  0,625 s

h(max) = h(0,625)    =  - 16*(0,625)² + 20*0,625

h(max)  =  - 6,25  +  12,5

h(max)  =  6,25 f

c) The ball will hit the ground

t = 2*t₁

t  = 2*0,625

t = 1,25 s

Mathematics
Step-by-step answer
P Answered by Master

You have the first 2 here's most of the rest. Write the equation that models the height of the roller coaster. Start by writing the equation of the circle . (Recall that the general form of a circle with the center at the origin isx2+ y2 = r2. x^2+y^2=30^2, The radius is 30 ftx^2+y^2=900 Now  solve  this  equation  for y.  Remember  the  roller  coaster  is  above  ground,  so  you  are  only interested in the positive root. y = √(900 -x^2) Graph the model of the roller coaster using the graphing calculator. Take a screenshot of your graph and paste the image below, or sketch a graph by hand. (Put this in you should be good ) y= root (900)-x^2 x^2+y^2=900 all your points should equal 30 and look like a semi circle, but on the top part of the top not the bottom. Write the equation you would need to solve to find the horizontal distance each beam is from the origin.(x=√30^2-25^2)  Algebraically solve the equation you found in step 3. Round your answer to the nearest hundredth. 16.584.Explain where to place the two beams x= -16.58x=16.58 Graph the cable and the strut on the model of the roller coaster using the graphing calculator. Take a screenshot of your graph and paste the image below, or sketch a graph by hand 900= x^2 +y^2 y=root(900-x^2) y= ^2x +8 y= x-8 the intersection should be -10 and positive 10 enter those equation into your calculator. That's all I know so far

Step-by-step explanation:

Mathematics
Step-by-step answer
P Answered by PhD
Part I
Let
x--------> represent the length of the cuts

For any given cut, the available distance is reduced by twice the length of the cut.
So
we can create the following equations for length, width, and height.
width:  w = 12 - 2x
length: l = 18 - 2x
height: h = x

Part II
v = l * w * h
v = (18 - 2x)(12 - 2x)x
v = (216 - 36x - 24x + 4x^2)x
v = (216 - 60x + 4x^2)x
v = 216x - 60x^2 + 4x^3
v = 4x^3 - 60x^2 + 216x

Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard  
So
0 < x < 6
If we use a value of x=1 in
we get a volume of:
v = 4x^3 - 60x^2 + 216x
v = 4*1^3 - 60*1^2 + 216*1
v = 4*1 - 60*1 + 216
v = 4 - 60 + 216v = 160 in³
Too small,
so
let's try x=2 in
v = 4x^3 - 60x^2 + 216x
v = 4*2^3 - 60*2^2 + 216*2
v = 4*8 - 60*4 + 216*2
v = 32 - 240 + 432v = 224 in³
And that's the desired volume.
So
let's choose a value of x=2 in
Reason?
It meets the inequality of
0 < x < 6
and it also gives the desired volume of 224 cubic inches.

Part IV
the table in the attached figure

Part V     
Based on your table, what x-value creates a box with a volume of 224 in3?

based on the table
 the answer Part V is
x=2 in

Part VI
width:  w = 12 - 2x-----> w=12-2*2----> w=8 in
length: l = 18 - 2x-----> l=18-2*2-----> l=14 in
height: h = x----------> h=x------> h=2 in
6. sabrina is making an open box from a piece of cardboard that has a width of 12 inches and a lengt
Mathematics
Step-by-step answer
P Answered by PhD
Part I
Let
x--------> represent the length of the cuts

For any given cut, the available distance is reduced by twice the length of the cut.
So
we can create the following equations for length, width, and height.
width:  w = 12 - 2x
length: l = 18 - 2x
height: h = x

Part II
v = l * w * h
v = (18 - 2x)(12 - 2x)x
v = (216 - 36x - 24x + 4x^2)x
v = (216 - 60x + 4x^2)x
v = 216x - 60x^2 + 4x^3
v = 4x^3 - 60x^2 + 216x

Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard  
So
0 < x < 6
If we use a value of x=1 in
we get a volume of:
v = 4x^3 - 60x^2 + 216x
v = 4*1^3 - 60*1^2 + 216*1
v = 4*1 - 60*1 + 216
v = 4 - 60 + 216v = 160 in³
Too small,
so
let's try x=2 in
v = 4x^3 - 60x^2 + 216x
v = 4*2^3 - 60*2^2 + 216*2
v = 4*8 - 60*4 + 216*2
v = 32 - 240 + 432v = 224 in³
And that's the desired volume.
So
let's choose a value of x=2 in
Reason?
It meets the inequality of
0 < x < 6
and it also gives the desired volume of 224 cubic inches.

Part IV
the table in the attached figure

Part V     
Based on your table, what x-value creates a box with a volume of 224 in3?

based on the table
 the answer Part V is
x=2 in

Part VI
width:  w = 12 - 2x-----> w=12-2*2----> w=8 in
length: l = 18 - 2x-----> l=18-2*2-----> l=14 in
height: h = x----------> h=x------> h=2 in
6. sabrina is making an open box from a piece of cardboard that has a width of 12 inches and a lengt

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