09.03.2021

16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x^2=1.

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24.06.2023, solved by verified expert
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Foci 16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Vertices:16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Eccentricity, e=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Length of latus rectum=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Step-by-step explanation:

We are given that

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41 (Along y-axis)

We get

a=1, b=1/4

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Therefore,

The coordinates of foci=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

The coordinated of vertices=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Eccentricity, e=c/a

16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Length of latus rectum=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

Length of latus rectum=16: Find the coordinates of the foci and the, №17886531, 09.03.2021 06:41

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Mathematics
Step-by-step answer
P Answered by PhD

Foci (0,\pm\frac{\sqrt{17}}{4})

Vertices:(0,\pm 1)

Eccentricity, e=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{1}{8}

Step-by-step explanation:

We are given that

y^2-16x^2=1

y^2-\frac{x^2}{(\frac{1}{4})^2}=1

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

y^2/a^2-x^2/b^2=1 (Along y-axis)

We get

a=1, b=1/4

a^2+b^2=c^2

1+\frac{1}{16}=c^2

\frac{16+1}{16}=c^2

c^2=\frac{17}{16}

c=\pm \frac{\sqrt{17}}{4}

Therefore,

The coordinates of foci=(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})

The coordinated of vertices=(0,\pm a)=(0,\pm 1)

Eccentricity, e=c/a

e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{2b^2}{a}

Length of latus rectum=2\times \frac{1}{16}=\frac{1}{8}

Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

The answer is in the image 

The answer is in the image 
Mathematics
Step-by-step answer
P Answered by PhD

For every 8 cars there are 7 trucks

Therefore,

Cars:Truck=8:7

Answer is B)8:7

Mathematics
Step-by-step answer
P Answered by PhD

The solution is in the following image

The solution is in the following image
Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

Mathematics
Step-by-step answer
P Answered by PhD

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

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