You spin a spinner numbered from 1 to 8 twice., №17886603, 07.06.2021 21:48

Mathematics

You spin a spinner numbered from 1 to 8 twice. Find the probability of getting a 1 on the first spin and a 2 on the second spin.

Step-by-step answer

P Answered by PhD

$Probability = \frac{1}{64}$

Step-by-step explanation:

The sample space of the spinner is:

$Sample\ Space = \{1,2,3,4,5,6,7,8\}$

So:

n(S)= 8

All of which have the same probability.

Required

Determine the probability of 1, then 2 when spin twice

The probability of the first being 1 is:

P(1)= n(1)/n(S)

P(1)= 1/8

The probability of the second being 2 is:

P(2)= n(2)/n(S)

P(2)= 1/8

So, the required probability is:

Probability = P(1) * P(2)

Probability =1/8* 1/8

$Probability = \frac{1}{64}$

Mathematics

Will award 50 points & the brainiest answer 1. one spinner has three equally sized sectors labeled r, s, and t. a second spinner has two equally sized sectors labeled 3 and 5. each spinner is spun once. what is the sample space of outcomes? {rst, 35} {rr, rs, rt, sr, ss, st, tr, ts, tt, 33, 35, 53, 55} {r, s, t, 3, 5} {r3, r5, s3, s5, t3, t5} (my guess) 2. a spinner with three equal sectors is spun three times. what is the number of possible outcomes? 3 6 9 27 3. there are two spinners. the first spinner has three equal sectors labeled 1, 2

Step-by-step answer

P Answered by Specialist

1.
You are right, answer D.

2.
First spin = 3 possible outcomes
Second spin = 3 possible outcomes
Third spin = 3 possible outcomes
so there will be 3*3*3 = 27 possible outcomes.
Answer D.

3.
Not 1 on the first spinner (so 2 or 3) = 2 possible outcomes
4 on the second spinner = 1 possible outcome
so there will be 2*1 = 2 possible outcomes.
Answer A.

4.
Answer A. (A six-sided number cube is rolled and a coin is flipped.)
and
Answer B. (Two spinners are spun at the same time.)

5.
First we have 10 slips of paper and there are 3 slips with number that is a multiple of 3 (3, 6 and 9). So:

P(multiple of 3) = 3/10

Now, we have only 9 slips and there are 2 with number that is multiple of 4 (4 and 8) so:

P(multiple of 4) = 2/9

And finally:

P(multiple of 3 and then a multiple of 4) = P(multiple of 3) * P(multiple of 4) =
=3/10 * 2/9 = 1/15
Answer A.

6.
We have 8 possible outcomes but only 4 even (2, 4, 6 and 8), so

P(even number on the first spin) = 4/8 = 1/2

The second spin is the same as the first one

P(even number on the second spin) = 4/8 = 1/2

And

P(even and even) = P(first even) * P(second even) = 1/2 * 1/2 = 1/4
Answer A.

7.
∩ means AND

$P(A)\cdot P(B) = 0.2\cdot0.3=0.06=P(A\cap B)$

so P(A)*P(B) = P(A and B)
A and B are independent.

8.
Let B - like brownies and C - like cupcakes
From the table we know, that (total number):

$P(B)=0.3\\P(C)=0.5\\P(B\cap C)=0.15$

Calculete:

$P(B|C)=\dfrac{P(B\cap C)}{P(C)}=\dfrac{0.15}{0.5}=0.3=P(B)$

and

$P(C|B)=\dfrac{P(B\cap C)}{P(B)}=\dfrac{0.15}{0.3}=0.5=P(C)$

So P(B|C) = P(B) and P(C|B) = P(C) and B, C are independent.
Answer A.

9.
Answer A.

10.
Let G₁ - first ball is green and G₂ - second ball is green. We know that:

$P(G_1\cap G_2)=\dfrac{11}{50}\qquad\qquad P(G_1)=\dfrac{12}{25}$

so:

$P(G_2|G_1)=\dfrac{P(G_1\cap G_2)}{P(G_1)}=\dfrac{\frac{11}{50}}{\frac{12}{25}}=\dfrac{11\cdot25}{50\cdot12}=\boxed{\dfrac{11}{24}}$

Answer B.

11.
All possible outcomes = 8
Number less than 4 = {1, 2, 3}
Multiple of 4 = {4, 8}
There is "number less than 4 OR a multiple of 4", so we take all numbers from both sets = {1, 2, 3, 4, 8} (5 outcomes)

P(less than 4 or a multiple of 4) = 5/8
Answer B.

12.
All possible outcomes = 10
Odd number = {1, 3, 5, 7, 9}
Number greater than 4 = {5, 6, 7, 8, 9, 10}
There is "an odd number AND a number greater than 4" so we take only numbers that are in both sets = {5, 7, 9} (3 outcomes)

P(an odd number and a number greater than 4) = 3/10
Answer C.

Mathematics

Will award 50 points & the brainiest answer 1. one spinner has three equally sized sectors labeled r, s, and t. a second spinner has two equally sized sectors labeled 3 and 5. each spinner is spun once. what is the sample space of outcomes? {rst, 35} {rr, rs, rt, sr, ss, st, tr, ts, tt, 33, 35, 53, 55} {r, s, t, 3, 5} {r3, r5, s3, s5, t3, t5} (my guess) 2. a spinner with three equal sectors is spun three times. what is the number of possible outcomes? 3 6 9 27 3. there are two spinners. the first spinner has three equal sectors labeled 1, 2

Step-by-step answer

P Answered by Specialist

1.
You are right, answer D.

2.
First spin = 3 possible outcomes
Second spin = 3 possible outcomes
Third spin = 3 possible outcomes
so there will be 3*3*3 = 27 possible outcomes.
Answer D.

3.
Not 1 on the first spinner (so 2 or 3) = 2 possible outcomes
4 on the second spinner = 1 possible outcome
so there will be 2*1 = 2 possible outcomes.
Answer A.

4.
Answer A. (A six-sided number cube is rolled and a coin is flipped.)
and
Answer B. (Two spinners are spun at the same time.)

5.
First we have 10 slips of paper and there are 3 slips with number that is a multiple of 3 (3, 6 and 9). So:

P(multiple of 3) = 3/10

Now, we have only 9 slips and there are 2 with number that is multiple of 4 (4 and 8) so:

P(multiple of 4) = 2/9

And finally:

P(multiple of 3 and then a multiple of 4) = P(multiple of 3) * P(multiple of 4) =
=3/10 * 2/9 = 1/15
Answer A.

6.
We have 8 possible outcomes but only 4 even (2, 4, 6 and 8), so

P(even number on the first spin) = 4/8 = 1/2

The second spin is the same as the first one

P(even number on the second spin) = 4/8 = 1/2

And

P(even and even) = P(first even) * P(second even) = 1/2 * 1/2 = 1/4
Answer A.

7.
∩ means AND

$P(A)\cdot P(B) = 0.2\cdot0.3=0.06=P(A\cap B)$

so P(A)*P(B) = P(A and B)
A and B are independent.

8.
Let B - like brownies and C - like cupcakes
From the table we know, that (total number):

$P(B)=0.3\\P(C)=0.5\\P(B\cap C)=0.15$

Calculete:

$P(B|C)=\dfrac{P(B\cap C)}{P(C)}=\dfrac{0.15}{0.5}=0.3=P(B)$

and

$P(C|B)=\dfrac{P(B\cap C)}{P(B)}=\dfrac{0.15}{0.3}=0.5=P(C)$

So P(B|C) = P(B) and P(C|B) = P(C) and B, C are independent.
Answer A.

9.
Answer A.

10.
Let G₁ - first ball is green and G₂ - second ball is green. We know that:

$P(G_1\cap G_2)=\dfrac{11}{50}\qquad\qquad P(G_1)=\dfrac{12}{25}$

so:

$P(G_2|G_1)=\dfrac{P(G_1\cap G_2)}{P(G_1)}=\dfrac{\frac{11}{50}}{\frac{12}{25}}=\dfrac{11\cdot25}{50\cdot12}=\boxed{\dfrac{11}{24}}$

Answer B.

11.
All possible outcomes = 8
Number less than 4 = {1, 2, 3}
Multiple of 4 = {4, 8}
There is "number less than 4 OR a multiple of 4", so we take all numbers from both sets = {1, 2, 3, 4, 8} (5 outcomes)

P(less than 4 or a multiple of 4) = 5/8
Answer B.

12.
All possible outcomes = 10
Odd number = {1, 3, 5, 7, 9}
Number greater than 4 = {5, 6, 7, 8, 9, 10}
There is "an odd number AND a number greater than 4" so we take only numbers that are in both sets = {5, 7, 9} (3 outcomes)

P(an odd number and a number greater than 4) = 3/10
Answer C.

Mathematics

Aspinner has 8 equal sectors labeled from 1 to 8. the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin? a. 1/4 b. 7/8 c. 5/16 d. 3/16

Step-by-step answer

P Answered by Specialist

6

1/4

I just took the test, hope I could help you with yours!

Aspinner has 8 equal sectors labeled from 1 to 8. the spinner is spun twice. what is the probabilit

Mathematics

Aspinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin? answer choices: 1/4 7/8 5/16 3/16

Step-by-step answer

P Answered by PhD

A. $\frac{1}{4}$

Step-by-step explanation:

We have been given that a spinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. We are asked to find the probability of getting an even number on the first spin and another even number on the second spin.

Even number from 1-8 are: 2, 4 , 6, 8

Total numbers: 8

$\text{Probability of getting an even number on 1st spin}=\frac{4}{8}\\\\\text{Probability of getting an even number on 1st spin}=\frac{1}{2}$

Since spinning of the spinner is independent event, so probability of getting an even number on both spins will be probability of getting an even number on 1st spin times probability of getting an even number 2nd time.

$\text{Probability of getting an even number on 2nd spin}=\frac{4}{8}\\\\\text{Probability of getting an even number on 2nd spin}=\frac{1}{2}$

$\text{Probability of getting an even number on both spins}=\frac{1}{2}\times \frac{1}{2}}\\\\\text{Probability of getting an even number on both spins}=\frac{1}{4}$

Therefore, option A is the correct choice.

Mathematics

Aspinner has 8 equal sectors labeled from 1 to 8. the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin? a. 1/4 b. 7/8 c. 5/16 d. 3/16

Step-by-step answer

P Answered by Master

6

1/4

I just took the test, hope I could help you with yours!

Mathematics

Aspinner has 8 equal sectors labeled from 1 to 8. the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin? 7/8 5/16 3/16 1/4

Step-by-step answer

P Answered by Specialist

30

On your first spin the chance is 1/2. The same goes for your second spin, but the chance of getting two consecutive even numbers is 1/2 x 1/2.
So the answer is 1/4.

Mathematics

Aspinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. what is the probability of getting an even number on the first spin and another even number on the second spin? answer choices: 1/4 7/8 5/16 3/16

Step-by-step answer

P Answered by PhD

A. $\frac{1}{4}$

Step-by-step explanation:

We have been given that a spinner has 8 equal sectors labeled from 1-8 the spinner is spun twice. We are asked to find the probability of getting an even number on the first spin and another even number on the second spin.

Even number from 1-8 are: 2, 4 , 6, 8

Total numbers: 8

$\text{Probability of getting an even number on 1st spin}=\frac{4}{8}\\\\\text{Probability of getting an even number on 1st spin}=\frac{1}{2}$

Since spinning of the spinner is independent event, so probability of getting an even number on both spins will be probability of getting an even number on 1st spin times probability of getting an even number 2nd time.

$\text{Probability of getting an even number on 2nd spin}=\frac{4}{8}\\\\\text{Probability of getting an even number on 2nd spin}=\frac{1}{2}$

$\text{Probability of getting an even number on both spins}=\frac{1}{2}\times \frac{1}{2}}\\\\\text{Probability of getting an even number on both spins}=\frac{1}{4}$

Therefore, option A is the correct choice.

Mathematics

PLEASE ANSWER ASAP Rico spins the spinner twice and determines the product of the spins. What is the probability that Rico will get a product of 20? The figure shows a spinner as a circle. The circle is divided into 3 equal parts labeled as 2, 4, and 5. An arrow is shown in the portion labeled as 2. A. 1 3 B. 1 20 C. 2 9 D. 1 8

Step-by-step answer

P Answered by PhD

1

2/9 is the correct option.

Step-by-step explanation:

As the spinner is numbered 2, 4 and 5

The general formula for probability :

P(A) = n(A) / n(S)

n(S) is the number of whole states occur in two spins which is 3 × 3 = 9

n(A) is the event that Rico will get a product of 20.

n(A) = 2 ∵ 4 × 5 and 5 × 4 will bring the product 20.

Therefor, the probability that Rico will get a product of 20 when Rico spins the spinner twice will be:

P(A) = n(A) / n(S)

= 2/9

Therefore, 2/9 is the correct option.

Mathematics

Rico spins the spinner twice and determines the sums of the spins. Fill in the sample space to determine the possible outcomes. What is the probability that Rico will get a sum less than or equal to 8? A 13 frac{1}{3} 3 1 B 23 frac{2}{3} 3 2 C 89 frac{8}{9} 9 8 D 59 frac{5}{9} 9 5

Step-by-step answer

P Answered by Master

2/3

Step-by-step explanation:

Sample space for the sum of 2 spins :

Number on spinner = 2, 5, 4

____ 2 ___ 5 _____4

2___ 4 ___ 7 _____ 6

|

5___ 7 ___ 10 ____ 9

|

4___ 6 ___ 9 ____ 8

Hence,

(4, 7, 6, 7, 10, 9, 6, 9, 8)

Probability of getting a sum less than or equal to 8;

Probability = required outcome / Total possible outcomes

Required outcome =, sum ≤ 8 = 6

Total possible outcomes = 9

P(sum ≤ 8) = 6/9 = 2/3

You spin a spinner numbered from 1 to 8 twice. Find the probability of getting a 1 on the first spin and a 2 on the second spin.

Step-by-step answer

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