The area of a typical eardrum is about 5.00 10-5 m2. (a) Calculate the average sound power incident on an eardrum at the threshold of pain, which corresponds to an intensity of 1.00 W/m2. 5e-5 Correct: Your answer is correct. W (b) How much energy is transferred to the eardrum exposed to this sound for 4.10 min

5 * 10^-5 W

1.23 * 10^-2 J

Step-by-step explanation:

Given that :

Area = 5 * 10^-5 m²

Threshold of Pain = Intensity = 1.00 W/m2

Using the relation:

Intensity = power / Area

Hence,

Power = Intensity * Area

Power = 1 W/m² * 5 * 10^-5 m²

Power = 5 * 10^-5 W

Energy transferred to eardrum. Exposed for 4.10 minutes :

Using the relation :

Energy = Power * time

Energy = 5 * 10^-5 * (4.10 * 60 seconds)

Energy = 5 * 10^-5 W * 246 s

Energy = 0.0123

= 1.23 * 10^-2 J

The answer is in the image 

The answer is in the image 

The solution is in the following image

The answer is in the image 

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The answer is in the image 

The solution is given in the image below

Here,

tip=18%of $32

tip=(18/100)*32

=0.18*32

=$5.76

Total payment=32+5.76=$37.76