Mathematics: What is the measure of N

Newtons are a measurement of force. By definition, 1 N is the amount of force required to accelerate...

What is the measure of N, №17886691, 18.06.2022 09:56

Chemistry

Use the table of water density at different temperatures to find the denisty of water at 23.60 °C. Include all seven decimal places provided in the table. Volume delivery analysis Mass delivered (9) Volume delivered (mL) Trial 1 3.959 Trial 2 3.979 Trial 3 3.981 Trial 4 3.966 Trial 5 3.964 Volume delivery statistics Volume (mL) Average Standard deviation Coefficient of variation (CV) True volume 4.000 Absolute error In the table above, you calculated the densities of a series of object, all made of the same material, and calculated the average

Step-by-step answer

P Answered by PhD

1. C. CV> 1.0%, measure of accuracy.
2. a. %error < 1.0%, measure of accuracy.
3. iv. Bias.
4. Coefficient of variation(CV) - In probability theory and statistics, the coefficient of variation (CV), also known as relative standard deviation (RSD), is a standardized measure of dispersion of a probability distribution or frequency distribution. It is often expressed as a percentage, and is defined as the ratio of the standard deviation. to the mean. (or its absolute value, ).
5. 2. Mass measurements have the greater impact because the mass CV with lightest object was lesser than its dimension CV.
6. D. My results don't agree at all - both my absolute error and standard deviation were greater than the claimed values.

Mathematics

Option 1—Individual There are many measurements of the human body that are positively correlated. For example, the length of one s forearm (measured from elbow to wrist) is approximately the same length as the foot (measured from heel to toe). They are positively correlated because, as one measurement increases, so does the other measurement. You will discover through this project whether a human s arm span (measured across the body with the arms extended) is correlated to his height. You will need to collect data from 11 people, which will give

Step-by-step answer

P Answered by PhD

1. Representation of data.
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit
*(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
*(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are
a=ZyZx^2-Z-x/nZx^2-(Zx)^2
b=ny-Zx/nZx^2-(Zx)^2.
This gave the regression equation:
y = 1.0595x - 4.1524.

(c) Interpretation.
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals.
The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.

(e) Predictions.
*(i) Height of person with 66 in arm span
y=1.0595x-4.1524;
66=1.0595x-4.1524;
70.1524=1.0595x;
x=70.1524/1.0595x=66 in.
A person with an arm span of 66 in should have a height of about 66 in.
*(ii) Arm span of 74 in tall person
y=1.0595x-4.1524;
=1.0595*74-4.1524;
=78.4030-4.1524;
=74 in.
A person who is 74 in tall should have an arm span of 74 in.

Mathematics

100 POINTS help! help! help! help! okay i need help im in algebra 2 and i have to make a scatter plot or something if you CAN help me answer & ill ask you how to do it in the comments please DO NOT answer just for points i really need help its due today at 12:00 noon and my teacher gave me an extra week last week and now its due and idk how to do it OKAY IM ASKING YOU PLEASE thank you in advance okay so i have to do this: Option 1 — Individual There are many measurements of the human body that are positively correlated. For example, the length

Step-by-step answer

P Answered by PhD

1. Representation of data.
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit
*(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
*(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are
a=ZyZx^2-Z-x/nZx^2-(Zx)^2
b=ny-Zx/nZx^2-(Zx)^2.
This gave the regression equation:
y = 1.0595x - 4.1524.

(c) Interpretation.
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals.
The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.

(e) Predictions.
*(i) Height of person with 66 in arm span
y=1.0595x-4.1524;
66=1.0595x-4.1524;
70.1524=1.0595x;
x=70.1524/1.0595x=66 in.
A person with an arm span of 66 in should have a height of about 66 in.
*(ii) Arm span of 74 in tall person
y=1.0595x-4.1524;
=1.0595*74-4.1524;
=78.4030-4.1524;
=74 in.
A person who is 74 in tall should have an arm span of 74 in.

Mathematics

100 POINTS Project 1—Individual There are many measurements of the human body that are positively correlated. For example, the length of one s forearm (measured from elbow to wrist) is approximately the same length as the foot (measured from heel to toe). They are positively correlated because, as one measurement increases, so does the other measurement. You will discover through this project whether a human s arm span (measured across the body with the arms extended) is correlated to his height. You will need to collect data from 11 people, which

Step-by-step answer

P Answered by PhD

1. Representation of data.
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit
*(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
*(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are
a=ZyZx^2-Z-x/nZx^2-(Zx)^2
b=ny-Zx/nZx^2-(Zx)^2.
This gave the regression equation:
y = 1.0595x - 4.1524.

(c) Interpretation.
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals.
The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.

(e) Predictions.
*(i) Height of person with 66 in arm span
y=1.0595x-4.1524;
66=1.0595x-4.1524;
70.1524=1.0595x;
x=70.1524/1.0595x=66 in.
A person with an arm span of 66 in should have a height of about 66 in.
*(ii) Arm span of 74 in tall person
y=1.0595x-4.1524;
=1.0595*74-4.1524;
=78.4030-4.1524;
=74 in.
A person who is 74 in tall should have an arm span of 74 in.

Mathematics

Project 1—Individual There are many measurements of the human body that are positively correlated. For example, the length of one s forearm (measured from elbow to wrist) is approximately the same length as the foot (measured from heel to toe). They are positively correlated because, as one measurement increases, so does the other measurement. You will discover through this project whether a human s arm span (measured across the body with the arms extended) is correlated to his height. You will need to collect data from 11 people, which will give

Step-by-step answer

P Answered by PhD

1. Representation of data.
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit
*(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
*(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are
a=ZyZx^2-Z-x/nZx^2-(Zx)^2
b=ny-Zx/nZx^2-(Zx)^2.
This gave the regression equation:
y = 1.0595x - 4.1524.

(c) Interpretation.
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals.
The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.

(e) Predictions.
*(i) Height of person with 66 in arm span
y=1.0595x-4.1524;
66=1.0595x-4.1524;
70.1524=1.0595x;
x=70.1524/1.0595x=66 in.
A person with an arm span of 66 in should have a height of about 66 in.
*(ii) Arm span of 74 in tall person
y=1.0595x-4.1524;
=1.0595*74-4.1524;
=78.4030-4.1524;
=74 in.
A person who is 74 in tall should have an arm span of 74 in.

Mathematics

Project 1—Individual There are many measurements of the human body that are positively correlated. For example, the length of one s forearm (measured from elbow to wrist) is approximately the same length as the foot (measured from heel to toe). They are positively correlated because, as one measurement increases, so does the other measurement. You will discover through this project whether a human s arm span (measured across the body with the arms extended) is correlated to his height. You will need to collect data from 11 people, which will give

Step-by-step answer

P Answered by PhD

1. Representation of data.
I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit
*(a) Variables
I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).
It seems to me that arm span depends on your height rather than the other way around.
*(b) Regression equation
The calculation is easy but tedious, so I asked Excel to do it.
For the equation y = ax + b, the formulas are
a=ZyZx^2-Z-x/nZx^2-(Zx)^2
b=ny-Zx/nZx^2-(Zx)^2.
This gave the regression equation:
y = 1.0595x - 4.1524.

(c) Interpretation.
The line shows how arm span depends on height.
The slope of the line says that arm span increases about 6 % faster than height.
The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals.
The residuals appear to be evenly distributed above and below the predicted values.
A graph of all the residuals confirms this observation.
The equation usually predicts arm span to within 4 in.

(e) Predictions.
*(i) Height of person with 66 in arm span
y=1.0595x-4.1524;
66=1.0595x-4.1524;
70.1524=1.0595x;
x=70.1524/1.0595x=66 in.
A person with an arm span of 66 in should have a height of about 66 in.
*(ii) Arm span of 74 in tall person
y=1.0595x-4.1524;
=1.0595*74-4.1524;
=78.4030-4.1524;
=74 in.
A person who is 74 in tall should have an arm span of 74 in.

Social Studies

Recruitment and Selection for Relationships For this assignment your group will identify a type of relationship in which both individuals can self-select into or out of (i.e., not family, coworkers, etc.). This relationship can be romantic (e.g., spouse, partner, etc.), non-romantic or platonic (e.g., friends), or professional (e.g., mentor). The purpose of the assignment is to explicate how one would go about finding and choosing an individual for one of these positions. You should assume that this plan is detailed enough that someone else could

Step-by-step answer

P Answered by PhD

Follows are the solution to this question:

Explanation:

Type: Working partnership. Mentor in total

Talent source (for example: of where you're recruiting or why) for all of this situation?

Experts from the subject matter, lecturers, professors, scholars

Within my professional network, I will search for them, including the organizations, clubs, and commissions I'm a member of or know about them first-hand.

Three KSAs required for the role

Standard practice:

Expert in the area of my preference or subject matter. It also published papers, carried out work, and demonstrated skills. Encounter in advising, advising, and assisting people with the potential for development.

Any KSA have established why that's important (believe job analysis;

for what? "I like it very much" is inadequate).

Mine tutor needs to have such KSAs although, its absence isn't beneficial in my career growth. A good mentor will unlock gates, and a weak one can put an end to my progress. Thus it is necessary for all the earlier in this thread-mentioned tutor to become a good one for us both.

In each KSA, it indicated how the KSA involvement is assessed or calculated

Professional: Ali will describe this person's personal experience and reputation because I realize he/she is also an expert, and an individual will direct me in the field of preference. Publishing: They would classify the papers, documentation, and analysis carried out by that entity and checked, validated, and verified by peers.Experience: It will take a glance at both the number of individuals and one's quality. What they do and what long it took to achieve the targets will help me assess the mentorship ability of such an individual.

Social Studies

Recruitment and Selection for Relationships For this assignment your group will identify a type of relationship in which both individuals can self-select into or out of (i.e., not family, coworkers, etc.). This relationship can be romantic (e.g., spouse, partner, etc.), non-romantic or platonic (e.g., friends), or professional (e.g., mentor). The purpose of the assignment is to explicate how one would go about finding and choosing an individual for one of these positions. You should assume that this plan is detailed enough that someone else could

Step-by-step answer

P Answered by PhD

Follows are the solution to this question:

Explanation:

Type: Working partnership. Mentor in total

Talent source (for example: of where you're recruiting or why) for all of this situation?

Experts from the subject matter, lecturers, professors, scholars

Within my professional network, I will search for them, including the organizations, clubs, and commissions I'm a member of or know about them first-hand.

Three KSAs required for the role

Standard practice:

Expert in the area of my preference or subject matter. It also published papers, carried out work, and demonstrated skills. Encounter in advising, advising, and assisting people with the potential for development.

Any KSA have established why that's important (believe job analysis;

for what? "I like it very much" is inadequate).

Mine tutor needs to have such KSAs although, its absence isn't beneficial in my career growth. A good mentor will unlock gates, and a weak one can put an end to my progress. Thus it is necessary for all the earlier in this thread-mentioned tutor to become a good one for us both.

In each KSA, it indicated how the KSA involvement is assessed or calculated

Professional: Ali will describe this person's personal experience and reputation because I realize he/she is also an expert, and an individual will direct me in the field of preference. Publishing: They would classify the papers, documentation, and analysis carried out by that entity and checked, validated, and verified by peers.Experience: It will take a glance at both the number of individuals and one's quality. What they do and what long it took to achieve the targets will help me assess the mentorship ability of such an individual.

Chemistry

14. Two jewelers were asked to measure the mass of a gold nugget. The true mass of the nugget is 0.856 grams (g). Each jeweler took three measurements. The average of the three measurements was reported as the official” measurement with the following results: Jeweler A: 0.863 g, 0.869 g, 0.859 g Jeweler B: 0.875 g, 0.834 g, 0.858 g Which jeweler s official measurement was more accurate? Which jeweler s measure- ments were more precise? In each case, what was the error and percent error in the official measurement?

Step-by-step answer

P Answered by PhD

2

Jeweler B = more accurate

Jeweler A = more precise

Error:

0.008, 0

% error :

0.934% ; 0

Explanation:

Given that:

True mass of nugget = 0.856

Jeweler A: 0.863 g, 0.869 g, 0.859 g

Jeweler B: 0.875 g, 0.834 g, 0.858 g

Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864

Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556

Accuracy = closeness of a measurement to the true value

Accuracy = true value - official measurement

Jeweler A's accuracy :

0.856 - 0.864 = - 0.008

Jeweler B's accuracy :

0.856 - 0.856 = 0.00

Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.

However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.

Error:

Jeweler A's error :

0.864 - 0.856 = 0.008

% error =( error / true value) × 100

% error = (0.008/0.856) × 100% = 0.934%

Jeweler B's error :

0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)

% error = 0%

Chemistry

14. Two jewelers were asked to measure the mass of a gold nugget. The true mass of the nugget is 0.856 grams (g). Each jeweler took three measurements. The average of the three measurements was reported as the official” measurement with the following results: Jeweler A: 0.863 g, 0.869 g, 0.859 g Jeweler B: 0.875 g, 0.834 g, 0.858 g Which jeweler s official measurement was more accurate? Which jeweler s measure- ments were more precise? In each case, what was the error and percent error in the official measurement?

Step-by-step answer

P Answered by PhD

2

Jeweler B = more accurate

Jeweler A = more precise

Error:

0.008, 0

% error :

0.934% ; 0

Explanation:

Given that:

True mass of nugget = 0.856

Jeweler A: 0.863 g, 0.869 g, 0.859 g

Jeweler B: 0.875 g, 0.834 g, 0.858 g

Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864

Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556

Accuracy = closeness of a measurement to the true value

Accuracy = true value - official measurement

Jeweler A's accuracy :

0.856 - 0.864 = - 0.008

Jeweler B's accuracy :

0.856 - 0.856 = 0.00

Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.

However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.

Error:

Jeweler A's error :

0.864 - 0.856 = 0.008

% error =( error / true value) × 100

% error = (0.008/0.856) × 100% = 0.934%

Jeweler B's error :

0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)

% error = 0%

What is the measure of N

Step-by-step answer

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