Which inequality represents the solution for the given inequality? n -7 > -11

-- Triangle 1

-- Triangle 2

-- Triangle 3

-- Triangle 4

Step-by-Step Explanation:

Given

2 sides of a triangle

1. 22 and 15

2. 13.2 and 6.7

3. 34 and 12

4. 23 and 44

Required

Determine the range of the third side in the above triangles

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

-- Triangle 1

-- Triangle 2

-- Triangle 3

-- Triangle 4

Step-by-Step Explanation:

Given

2 sides of a triangle

1. 22 and 15

2. 13.2 and 6.7

3. 34 and 12

4. 23 and 44

Required

Determine the range of the third side in the above triangles

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

Represent the third side with x

We'll make use of the following conditions to calculate  the range of the third side;

Solving

Make x the subject of formula

Solving

Solving

Make x the subject of formula

The next step is to dismiss the inequality with negative digit; So, we're left with

and

Rewrite both inequalities

and

Combine the two inequalities

1: 6

2: 1,2,3

3: 4m-1>5m-4

4: Not enough data

5: n = 11

6: The ceiling is lower than 3m

7: G = 7

8: C = 18

9: p + 18 = 41; p = 23

10: D = 100t

Step-by-step explanation:

Question 1:

5*2+x/2-7

5*2+6/2-7

10+6/2-7

10+3-7

13-7

6

Question 2:

4*2<16

8<16 True

4*1<16

4<16 True

4*3<16

12<16 True

4*4<16

16<16 False

Question 3:

Let's plug in 1 for m

4*1-15*1-4

4-15-4

31

3>1

Question 4:

You did not give an equation, so I cannot answer.

Question 5:

2*11 + 5 =27

22 + 5 = 27

27 = 27

So n = 11

Question 6:

x<3

The ceiling is lower than 3m because x<3

Question 7:

5.1g = 35.7

5.1g/5.1=35.7/5.1

g = 7

Check: 5.1 * 7 = 35.7

Question 8:

36 + c = 54

36 + c -36 = 54 - 36

c = 18

Check: 36 + 18 = 54

Question 9:

p + 18 = 41; p = 23 is correct because the number of paperback books plus the number of hardcover books would equal the total number of books sold. Check: 23 + 18 = 41

Question 10:

d=100t is correct because each time t goes up one it goes up 100. Example: if it is at one hour, than it is 100, if it is at 3 hours, than d = 100*3 = 300, which is the same pattern as the table.

Hope this helps!

1: 6

2: 1,2,3

3: 4m-1>5m-4

4: Not enough data

5: n = 11

6: The ceiling is lower than 3m

7: G = 7

8: C = 18

9: p + 18 = 41; p = 23

10: D = 100t

Step-by-step explanation:

Question 1:

5*2+x/2-7

5*2+6/2-7

10+6/2-7

10+3-7

13-7

6

Question 2:

4*2<16

8<16 True

4*1<16

4<16 True

4*3<16

12<16 True

4*4<16

16<16 False

Question 3:

Let's plug in 1 for m

4*1-15*1-4

4-15-4

31

3>1

Question 4:

You did not give an equation, so I cannot answer.

Question 5:

2*11 + 5 =27

22 + 5 = 27

27 = 27

So n = 11

Question 6:

x<3

The ceiling is lower than 3m because x<3

Question 7:

5.1g = 35.7

5.1g/5.1=35.7/5.1

g = 7

Check: 5.1 * 7 = 35.7

Question 8:

36 + c = 54

36 + c -36 = 54 - 36

c = 18

Check: 36 + 18 = 54

Question 9:

p + 18 = 41; p = 23 is correct because the number of paperback books plus the number of hardcover books would equal the total number of books sold. Check: 23 + 18 = 41

Question 10:

d=100t is correct because each time t goes up one it goes up 100. Example: if it is at one hour, than it is 100, if it is at 3 hours, than d = 100*3 = 300, which is the same pattern as the table.

Hope this helps!

n > -4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

n - 7 > -11

Step 2: Solve for n

Here we see that any value n greater than -4 would work as a solution.

x ≤ a → x ∈ (-∞, a]

x < a → x ∈ (-∞, a)

x ≥ a → x ∈ [a, ∞)

x < a → x ∈ (a, ∞)

Therefore:

x ≥ 7.8 → [7.8, ∞)

x < 7.8 → (-∞, 7.8)

x ≤ 7.8 → (-∞, 7.8]

x > 7.8 → (7.8, ∞)

x≤7.8  ⇒(-∞;7.8]

x<7.8  ⇒ (-∞;7.8)

x>7.8  ⇒ (7.8; ∞)

x≥7.8  ⇒ [7.8; ∞)

Step-by-step explanation:

Hi, to answer this question we have to analyze each expression:

•x≤7.8

The solution is all the numbers less or equal to 7.8, since it can be equal to 7.8, it includes 7.8 , we have to use closed brackets

(-∞;7.8]

•x<7.8

All the numbers less than 7.8 , it excludes the endpoint , it's an open interval (parenthesis)

(-∞;7.8)

•x>7.8

All the numbers higher than 7.8, open interval (parenthesis)

(7.8; ∞)

•x≥7.8

All the numbers higher or equal to 7.8, closed interval (closed brackets for the endpoint)

[7.8; ∞)

x ≤ a → x ∈ (-∞, a]

x < a → x ∈ (-∞, a)

x ≥ a → x ∈ [a, ∞)

x < a → x ∈ (a, ∞)

Therefore:

x ≥ 7.8 → [7.8, ∞)

x < 7.8 → (-∞, 7.8)

x ≤ 7.8 → (-∞, 7.8]

x > 7.8 → (7.8, ∞)

Step-by-step explanation:

The line between -3 and 2 is not shaded so it is not -3 < x < 2. Instead, the lines to the left of -3 and to the right of 2 are shaded.

Therefore the correct answer is x < -3 or x > 2.

Step-by-step explanation:

The line between -3 and 2 is not shaded so it is not -3 < x < 2. Instead, the lines to the left of -3 and to the right of 2 are shaded.

Therefore the correct answer is x < -3 or x > 2.