Mathematics
: asked on jasonoliva13

02.06.2020

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24.06.2023, solved by verified expert

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American Roulette

1. The probability of losing a ’1st 12’ bet on a single spin is:

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

= 0.23

Step-by-step explanation:

Possible outcomes in an American Roulette wheel = 38

Make-up of the outcomes = 18 black, 18 red and 2 green

Green outcomes are numbered 0 and 00

Number of wins for this person = 12

Probability of winning = 0.33 (12/36)

Number of possible losses for this person = 24

Probability of losing = 0.67 (24/36)

1. The probability of losing a '1st 12' bet on a single spin is:

= (36 - 12)/36

= 0.67

2. The probability of winning 7 out of the 10 total bets is:

Probability of winning = 12/36 * 7/10

= 0.23

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