What is the intercept of y=-1/2x-1 and y=1/4x-4, №17887557, 12.03.2020 03:20

Mathematics

What is the intercept of y=-1/2x-1 and y=1/4x-4

Step-by-step answer

P Answered by PhD

1

x-intercept: y=0

1) -2, 0

2) 16,0

Step-by-step explanation:

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Master

19

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Specialist

19

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Specialist

65

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

Me ive been crying for hours because im so stressed out write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation. 1. (2, -2) ; y = -x - 2 a) y = -2x b) y = 2x c) y = 1/2 x d) y = - x 2. (2, -1) ; y = - 3/2 x + 6 a) y=-3/2x+6 b) -3/2x+1 c) -3/2x-1x d) -3/2x+4 3. (4, 2) ; x=-3 a) y=2 b) y=2x+4 c) y=4x d) x=4 write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. 4. (-2, 3)

Step-by-step answer

P Answered by Specialist

4

1. y=-x

2. y=-3/2x-2

3. x=4

4. y=-2x-1

Step-by-step explanation:

slope intercept form is y=mx+b with mx being the slope and b being the y intercept

if its parallel it has to have the same slope.

perpendicular lines have the opposite slope and sign. so if its a whole number you put it over 1 and if its a fraction you switch the values in the numerator and denominator in addition to changing the sign. You keep the y intercept the same.

Mathematics

Me ive been crying for hours because im so stressed out write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation. 1. (2, -2) ; y = -x - 2 a) y = -2x b) y = 2x c) y = 1/2 x d) y = - x 2. (2, -1) ; y = - 3/2 x + 6 a) y=-3/2x+6 b) -3/2x+1 c) -3/2x-1x d) -3/2x+4 3. (4, 2) ; x=-3 a) y=2 b) y=2x+4 c) y=4x d) x=4 write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. 4. (-2, 3)

Step-by-step answer

P Answered by Specialist

4

1. y=-x

2. y=-3/2x-2

3. x=4

4. y=-2x-1

Step-by-step explanation:

slope intercept form is y=mx+b with mx being the slope and b being the y intercept

if its parallel it has to have the same slope.

perpendicular lines have the opposite slope and sign. so if its a whole number you put it over 1 and if its a fraction you switch the values in the numerator and denominator in addition to changing the sign. You keep the y intercept the same.

Mathematics

1. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a)y=-2x b)y=2x c)y=1/2x d)y=-x 2. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x+6 a)y=-3/2x+1 b)y=-3/2x-1 c)y=-3/2x+2 d)y=-3/2x+4 3. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

Step-by-step answer

P Answered by PhD

6

1. The correct option is D.

2. The correct option is C.

3. The correct option is D.

4. The correct option is B.

5. The correct option is D.

Step-by-step explanation:

The slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

The slope of parallel lines are same.

(1)

The required line is parallel to the line y=-x-2 and passes through (2,-2). Slope of the line is -1.

The equation of required line is

y-y_1=m(x-x_1)

y-(-2)=-1(x-2)

y+2=-x+2

y=-x

Therefore the correct option is D.

(2)

The required line is parallel to the line y=-3/2x+6 and passes through (2,-1). Slope of the line is -3/2.

The equation of required line is

y-y_1=m(x-x_1)

$y-(-1)=-\frac{3}{2}(x-2)$

$y+1=-\frac{3}{2}x+3$

$y=-\frac{3}{2}x+2$

Therefore the correct option is C.

(3)

The required line is parallel to the line x=-3 and passes through (4,2). Slope of the line is infinite.

The equation of required line is

y-y_1=m(x-x_1)

$y-2=\frac{1}{0}(x-4)$

0=x-4

x=4

Therefore the correct option is D.

(4)

Product of slopes of perpendicular lines is -1.

The required line is perpendicular to the line y=1/2x-1 and passes through (-2,3). Slope of the required line is -2.

The equation of required line is

y-y_1=m(x-x_1)

y-3=-2(x-(-2))

y-3=-2x-4

x=-2x-1

Therefore the correct option is B.

(5)

The required line is perpendicular to the line y+1=2(x-3) and passes through (5,0). Slope of the required line is -1/2.

The equation of required line is

y-y_1=m(x-x_1)

$y-0=-\frac{1}{2}(x-5)$

$y=-\frac{1}{2}(x)+\frac{5}{2}$

Therefore the correct option is D.

Mathematics

1. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a)y=-2x b)y=2x c)y=1/2x d)y=-x 2. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x+6 a)y=-3/2x+1 b)y=-3/2x-1 c)y=-3/2x+2 d)y=-3/2x+4 3. write and equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

Step-by-step answer

P Answered by PhD

6

1. The correct option is D.

2. The correct option is C.

3. The correct option is D.

4. The correct option is B.

5. The correct option is D.

Step-by-step explanation:

The slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

The slope of parallel lines are same.

(1)

The required line is parallel to the line y=-x-2 and passes through (2,-2). Slope of the line is -1.

The equation of required line is

y-y_1=m(x-x_1)

y-(-2)=-1(x-2)

y+2=-x+2

y=-x

Therefore the correct option is D.

(2)

The required line is parallel to the line y=-3/2x+6 and passes through (2,-1). Slope of the line is -3/2.

The equation of required line is

y-y_1=m(x-x_1)

$y-(-1)=-\frac{3}{2}(x-2)$

$y+1=-\frac{3}{2}x+3$

$y=-\frac{3}{2}x+2$

Therefore the correct option is C.

(3)

The required line is parallel to the line x=-3 and passes through (4,2). Slope of the line is infinite.

The equation of required line is

y-y_1=m(x-x_1)

$y-2=\frac{1}{0}(x-4)$

0=x-4

x=4

Therefore the correct option is D.

(4)

Product of slopes of perpendicular lines is -1.

The required line is perpendicular to the line y=1/2x-1 and passes through (-2,3). Slope of the required line is -2.

The equation of required line is

y-y_1=m(x-x_1)

y-3=-2(x-(-2))

y-3=-2x-4

x=-2x-1

Therefore the correct option is B.

(5)

The required line is perpendicular to the line y+1=2(x-3) and passes through (5,0). Slope of the required line is -1/2.

The equation of required line is

y-y_1=m(x-x_1)

$y-0=-\frac{1}{2}(x-5)$

$y=-\frac{1}{2}(x)+\frac{5}{2}$

Therefore the correct option is D.

Mathematics

1). write an equation of a line with the given slope and y-intercept. m= -2, b=4 a) y= -2x-4 b) y= -2x+4 c) y= -1/2x+4 d) y= 4x-2 2). find the slope and y-inercept of the line y= 1/5x-8 a). 5; 8 b). 8; 1/5 c). 1/5; -8 d). -8; 1/5 3). are the graphs of the lines in he pair parallel? explain y=6x+9 27x-3y=-81 a). yes, since the slopes are the same and the y-intercepts are the same. b). yes, since the slopes are the same and the y-intercepts are different. c). no, since the y-intercepts are different. 4). write y=3/5x+4 in a standard form using integers.

Step-by-step answer

P Answered by PhD

3

Answers:

1) The Equation of a Line is:

y=mx+b (1)

Where:

is the slope

is the y-intercept

For this problem we have a given m=-2 and a given b=4

So, we only have to substitute this values in the equation (1):

y=-2x+4

This is option B

2) Here we have to find the slope and the y-intercept of this equation:

$y=\frac{1}{5}x-8$

According to the explanation in the first answer related to the equation (1), the slope of this line is:

$m=\frac{1}{5}$

And its y-intercept is:

b=-8

This is option C

3) We have to Equations of the Line, and we are asked if these are parallel:

y=6x+9 (a)

27x-3y=-81 (b)

Equation (b) has to be written in the same form of (a), in the form y=mx+b in order to be able to compare both:

-3y=-81-27x

$y=-\frac{1}{3}(-81-27x)$

$y=\frac{81}{3}+\frac{27}{3}x$

y=9x+27 (c)

There is a rule that establishes that Two lines are parallel if they have the same slope. In this case, if we compare equations (a) and (c) we find they don’t have the same slope, then they are not parallel.

4) Here we are asked to write $y=\frac{3}{5}x+4$ in a standard form with integers:

$-\frac{3}{5}x+y=4$

Multiply each side by 5:

$5(-\frac{3}{5}x+y)=5(4)$

$5(-\frac{3}{5}x)+5y=20$

-3x+5y=20

In this case none of the options apply, please check if the question was written correctly.

5) In this question we are asked to write an equation parallel to:

y=2x+7 (2)

That passes through the given point (3,11). (Notice that in the Cartesian plane the points have an x-component and a y-component)

First, remember that two Equations of the line are parallel when they have the same slope. Now that this is clear, we are going to use the equation of the slope with the given point to find the parallel equation:

Equation of the slope:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ (3)

From (2) we know the slope is 2, then we only have to substitute this value and the points in (3):

$2=\frac{y-11}{x-3}$

2(x-3)=y-11

2x-6=y-11

Finally:

y=2x+5

This is option B

Mathematics

1). write an equation of a line with the given slope and y-intercept. m= -2, b=4 a) y= -2x-4 b) y= -2x+4 c) y= -1/2x+4 d) y= 4x-2 2). find the slope and y-inercept of the line y= 1/5x-8 a). 5; 8 b). 8; 1/5 c). 1/5; -8 d). -8; 1/5 3). are the graphs of the lines in he pair parallel? explain y=6x+9 27x-3y=-81 a). yes, since the slopes are the same and the y-intercepts are the same. b). yes, since the slopes are the same and the y-intercepts are different. c). no, since the y-intercepts are different. 4). write y=3/5x+4 in a standard form using integers.

Step-by-step answer

P Answered by PhD

3

Answers:

1) The Equation of a Line is:

y=mx+b (1)

Where:

is the slope

is the y-intercept

For this problem we have a given m=-2 and a given b=4

So, we only have to substitute this values in the equation (1):

y=-2x+4

This is option B

2) Here we have to find the slope and the y-intercept of this equation:

$y=\frac{1}{5}x-8$

According to the explanation in the first answer related to the equation (1), the slope of this line is:

$m=\frac{1}{5}$

And its y-intercept is:

b=-8

This is option C

3) We have to Equations of the Line, and we are asked if these are parallel:

y=6x+9 (a)

27x-3y=-81 (b)

Equation (b) has to be written in the same form of (a), in the form y=mx+b in order to be able to compare both:

-3y=-81-27x

$y=-\frac{1}{3}(-81-27x)$

$y=\frac{81}{3}+\frac{27}{3}x$

y=9x+27 (c)

There is a rule that establishes that Two lines are parallel if they have the same slope. In this case, if we compare equations (a) and (c) we find they don’t have the same slope, then they are not parallel.

4) Here we are asked to write $y=\frac{3}{5}x+4$ in a standard form with integers:

$-\frac{3}{5}x+y=4$

Multiply each side by 5:

$5(-\frac{3}{5}x+y)=5(4)$

$5(-\frac{3}{5}x)+5y=20$

-3x+5y=20

In this case none of the options apply, please check if the question was written correctly.

5) In this question we are asked to write an equation parallel to:

y=2x+7 (2)

That passes through the given point (3,11). (Notice that in the Cartesian plane the points have an x-component and a y-component)

First, remember that two Equations of the line are parallel when they have the same slope. Now that this is clear, we are going to use the equation of the slope with the given point to find the parallel equation:

Equation of the slope:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ (3)

From (2) we know the slope is 2, then we only have to substitute this value and the points in (3):

$2=\frac{y-11}{x-3}$

2(x-3)=y-11

2x-6=y-11

Finally:

y=2x+5

This is option B

What is the intercept of

y=-1/2x-1 and y=1/4x-4

Step-by-step answer

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