Mathematics : asked on allisondelp6

12.03.2020

How do I graph

y=-1/2x-1

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24.06.2023, solved by verified expert

Chemistry, Q&A Expert

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First graph -1 (0, -1) on the graph. Then go 1 unit down and 2 units to the right. Mark the point and draw a line passing the point. Hope this helps, thank you

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Bhaskar Singh Bora

Mathematics, Physics. Q&A Expert

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Step-by-step explanation:

Find the x and y intercept, and determine the slope.

X-intercept:

It crosses the x-axis at x = -2

Y-intercept:

It crosses the y-axis at y = -1

Slope:

y = mx + b

m = slope = -1/2

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Faq

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Specialist

65

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Master

19

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

1.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2); y=-x-2 a.y=-2x b.y=2x c.y=1/2x d.y=-x 2.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1); y=-3/2x-6 a.y=-3/2x+1 b.y=-3/2x-1 c.y=-3/2x+2 d.y=-3/2x+4 3.write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);

Step-by-step answer

P Answered by Specialist

19

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

D.y=-1/2x+5/2

Mathematics

Me ive been crying for hours because im so stressed out write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation. 1. (2, -2) ; y = -x - 2 a) y = -2x b) y = 2x c) y = 1/2 x d) y = - x 2. (2, -1) ; y = - 3/2 x + 6 a) y=-3/2x+6 b) -3/2x+1 c) -3/2x-1x d) -3/2x+4 3. (4, 2) ; x=-3 a) y=2 b) y=2x+4 c) y=4x d) x=4 write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. 4. (-2, 3)

Step-by-step answer

P Answered by Specialist

4

1. y=-x

2. y=-3/2x-2

3. x=4

4. y=-2x-1

Step-by-step explanation:

slope intercept form is y=mx+b with mx being the slope and b being the y intercept

if its parallel it has to have the same slope.

perpendicular lines have the opposite slope and sign. so if its a whole number you put it over 1 and if its a fraction you switch the values in the numerator and denominator in addition to changing the sign. You keep the y intercept the same.

Mathematics

Me ive been crying for hours because im so stressed out write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation. 1. (2, -2) ; y = -x - 2 a) y = -2x b) y = 2x c) y = 1/2 x d) y = - x 2. (2, -1) ; y = - 3/2 x + 6 a) y=-3/2x+6 b) -3/2x+1 c) -3/2x-1x d) -3/2x+4 3. (4, 2) ; x=-3 a) y=2 b) y=2x+4 c) y=4x d) x=4 write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. 4. (-2, 3)

Step-by-step answer

P Answered by Specialist

4

1. y=-x

2. y=-3/2x-2

3. x=4

4. y=-2x-1

Step-by-step explanation:

slope intercept form is y=mx+b with mx being the slope and b being the y intercept

if its parallel it has to have the same slope.

perpendicular lines have the opposite slope and sign. so if its a whole number you put it over 1 and if its a fraction you switch the values in the numerator and denominator in addition to changing the sign. You keep the y intercept the same.

Mathematics

Which equation represents the relationship shown in the table? x y -4 -3 -2 -2 0 -1 2 0 4 1 a.) y= -1/2x-1 b.) y= x+1 c.) y=1/2x-1 d.) y= 1/2x+1

Step-by-step answer

P Answered by PhD

4

(2,0)(4,1)
slope = (1 - 0) / (4 - 2) = 1/2

y = mx + b
slope(m) = 1/2
use any of ur points(4,1)...x = 4 and y = 1
now sub and find b, the y int
1 = 1/2(4) + b
1 = 2 + b
1 - 2 = b
-1 = b

so ur equation is : y = 1/2x - 1 <==

Mathematics

Which equation represents the relationship shown in the table? x y -4 -3 -2 -2 0 -1 2 0 4 1 a.) y= -1/2x-1 b.) y= x+1 c.) y=1/2x-1 d.) y= 1/2x+1

Step-by-step answer

P Answered by PhD

4

(2,0)(4,1)
slope = (1 - 0) / (4 - 2) = 1/2

y = mx + b
slope(m) = 1/2
use any of ur points(4,1)...x = 4 and y = 1
now sub and find b, the y int
1 = 1/2(4) + b
1 = 2 + b
1 - 2 = b
-1 = b

so ur equation is : y = 1/2x - 1 <==

Mathematics

Will mark brainiest what is the equation of the line that goes through the point (-4,1) and is perpendicular to the line represented by the equation below? 2x-y=17 a.y= -1/2x+1 b.y= - 1/2x+3 c. y= -1/2x-1 d. y= -1/2x-3

Step-by-step answer

P Answered by Master

1

So, the first thing we need to do is find the slope, so we'll put the equation into slope intercept form

$y+17=2x\\y=2x-17$

So, our slope in the original is 2, so to make it perpendicular we need to take the negative multiplicative inverse. So, we flip the fraction, and multiply it by negative 1. So, we get -1/2 for our new slope. Now, we just put the numbers into point-slope form and solve

$Y-1=-\frac{1}{2} (x+4)\\Y-1=-\frac{1}{2}x+2\\ Y=-\frac{1}{2}x + 3$

C is the correct answer

Mathematics

Will mark brainiest what is the equation of the line that goes through the point (-4,1) and is perpendicular to the line represented by the equation below? 2x-y=17 a.y= -1/2x+1 b.y= - 1/2x+3 c. y= -1/2x-1 d. y= -1/2x-3

Step-by-step answer

P Answered by Specialist

1

So, the first thing we need to do is find the slope, so we'll put the equation into slope intercept form

$y+17=2x\\y=2x-17$

So, our slope in the original is 2, so to make it perpendicular we need to take the negative multiplicative inverse. So, we flip the fraction, and multiply it by negative 1. So, we get -1/2 for our new slope. Now, we just put the numbers into point-slope form and solve

$Y-1=-\frac{1}{2} (x+4)\\Y-1=-\frac{1}{2}x+2\\ Y=-\frac{1}{2}x + 3$

C is the correct answer

Mathematics

Write the point-slope for the seven following equations1) through: (-3,-3), parallel to y=7/3x+32) through: (-4,0), parallel to y=3/4×-13) through: (-1,4), parallel to y=-5x+24) through: (2,0), parallel to y=1/3x+35) through: (4,-4), parallel to y=-x-46) through: (-2,4), parallel to y=-5/2x+57) through: (-4,-1), parallel to y=-1/2x-1

Step-by-step answer

P Answered by Master

5

K I will try my best

1) y+3=7/3(x+3)

2) y-0=3/4(x+4)

3) y-4=-5(x+1)

4) y-0=1/3(x-2)

5) y+4=-1(x-4)

6) y-4=-5/2(x+2)

7) y+1=-1/2(x+4)

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