Point M( -3, -2) is rotated 270° counterclockwise and then reflected over the x-axis. What are the coordinates of M'?

Rotation involves moving a point around a center

The coordinates of M" are (-2,-3)

The pre-image M is given as:

M =(-3,-2)

The rule of 270 degrees counterclockwise rotation is:

So, we have:

M' = (-2,3)

The rule of reflection over the x-axis is:

So, we have:

M" = (-2,-3)

Hence, the coordinates of M" are (-2,-3)

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The first question is c i believe, I dont have time to answer the others

The first question is c i believe, I dont have time to answer the others

The answer is in the image 

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

The total nom of  code that can be used is equal to 5+3 = 8

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Approximately it is aqual to 1300kg

The answer is in the image 

The solution is given in the image below