Mathematics : asked on rrnr
 17.07.2022

What is 950% as a fraction

. 0

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Mathematics
Step-by-step answer
P Answered by Master

9 1/2

Step-by-step explanation:

\frac{950}{100}=9\frac{50}{100} = 9 \frac{1}{2}

Mathematics
Step-by-step answer
P Answered by Master
1. The 4 is in the thousands place
2. 50
3. 2,168 + 305 = 2473
4. estimate 156 + 235
    160 + 240 = 400
5. 8,631 - 5,950 = 2,681
6. 724 * 17 = 12,308
7. 14÷6,230 = 2.25×10^{-3}
8. 962÷ 39 
    960÷ 40 = 24
9. .7
10. 36.90
      +7.35
     -----------
      44.25

11.   9.610
      -0.268
      ----------
       9.342

12.  419.2
      x  2.54
    -------------
       16768
     209600
     838400
   --------------
   1064.768

13. 4\sqrt{128.600}   (pretend sqrt sign is division sign
        -0
       --------
         12
        -12
       --------
           08
          - 8
       --------
             06
             -4
      ----------
               20
              -20
           --------
                0
      32.150
14. least to greatest: 0.031, 0.124, 0.31, 0.5, 1.24
15. 29.95
      x   36
   -----------
    17970
 -  89850
   -----------
  107820
Mathematics
Step-by-step answer
P Answered by Specialist
1. The 4 is in the thousands place
2. 50
3. 2,168 + 305 = 2473
4. estimate 156 + 235
    160 + 240 = 400
5. 8,631 - 5,950 = 2,681
6. 724 * 17 = 12,308
7. 14÷6,230 = 2.25×10^{-3}
8. 962÷ 39 
    960÷ 40 = 24
9. .7
10. 36.90
      +7.35
     -----------
      44.25

11.   9.610
      -0.268
      ----------
       9.342

12.  419.2
      x  2.54
    -------------
       16768
     209600
     838400
   --------------
   1064.768

13. 4\sqrt{128.600}   (pretend sqrt sign is division sign
        -0
       --------
         12
        -12
       --------
           08
          - 8
       --------
             06
             -4
      ----------
               20
              -20
           --------
                0
      32.150
14. least to greatest: 0.031, 0.124, 0.31, 0.5, 1.24
15. 29.95
      x   36
   -----------
    17970
 -  89850
   -----------
  107820
Physics
Step-by-step answer
P Answered by PhD

F'=708.53 N

Explanation:

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,

F=kAv^2

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

Chemistry
Step-by-step answer
P Answered by PhD

Answer:

A) Considering the solution of molality, molarity and density, the molality of the glycerol solution is 0.029 Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s.

Molality is a measure of concentration that indicates the ratio of the number of moles of any dissolved solute to kilograms of solvent.

The Molality of a solution is determined by the expression:

Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s

Molality is expressed in units Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s.

B) In this case, you know a 2.950×10⁻² M solution of glycerol (C₃H₈O₃) in water is at 20.0∘C. The sample was created by dissolving a sample of C₃H₈O₃ in water and then bringing the volume up to 1 L.

So, being the molarity the number of moles of solute that are dissolved in a certain volume and determined by the following expression:

Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s

the number of moles of solute can be calculated as:

number of moles of solute= molarity× volume

Then, in this case, the number of moles of solute is calculated as:

number of moles of solute= 2.950×10⁻² M× 1 L

Solving:

number of moles of solute= 2.950×10⁻² moles

On the other side, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s

C) Then, the mass can be calculated as:

mass= density×volume

In this case, you know that the volume of water needed was 998.7 mL  and the density of water at 20.0∘C is 0.9982 g/mL. So the mass of water can be calculated as:

mass of water= mass of solvent= 0.9982 g/mL× 998.7 mL= 996.9 g= 0.9969 kg

D) Finally, the molality is calculated as:

Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s

Solving:

Molality= 0.029 Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s

In summary, the molality of the glycerol solution is 0.029 Answer:A) Considering the solution of molality, molarity and density, the molality of the glycerol s.

Physics
Step-by-step answer
P Answered by PhD

F'=708.53 N

Explanation:

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,

F=kAv^2

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

Chemistry
Step-by-step answer
P Answered by Master

a. 2.959x10⁻²m

b. 5.327x10⁻⁴

c. 0.272%

d. 2718 PPM

Explanation:

A solution of 2.950x10⁻²M contains 2.950x10⁻² moles of Glycerol per Liter of solution. As the volume of the solution made was 1.000L, moles of glycerol are 2.950x10⁻².

a. molality: Molality is defined as the ratio between moles of solute (2.950x10⁻²) in kg of solvent. As there are 998.7mL of solvent and density is 0.9982g/mL, kg are:

998.7mL ₓ (0.9982g/mL) ₓ (1kg / 1000g) = 0.9969kg of solvent.

Molality: 2.950x10⁻² moles / 0.9969kg of solvent = 2.959x10⁻²m

b. Mole fraction is the ratio between moles of solute and total moles. Moles of water are:

998.7mL ₓ (0.9982g/mL) ₓ (1mol / 18.01g) = 55.35 moles of water.

Mole fraction glycerol:

2.950x10⁻² moles / (2.950x10⁻²moles + 55.35) = 5.327x10⁻⁴

c. Percent by mass Is the ratio by mass of solute and solution multiplied 100 times.

Mass of glycerol (Molar mass:  92.09g/mol):

2.950x10⁻² moles × (92.09g / mol) = 2.717g of glycerol

Mass of water:

998.7mL ₓ (0.9982g/mL) = 996.9g of water.

Percent by mass:

2.717g of glycerol / (996.9g of water + 2.717g) × 100 = 0.272%

d. Parts per million are defined as the ratio between mg of solute and kg of solution.

mg of 2.717g of glycerol are 2717mg

kg of solution are (996.9g + 2.717g) / 1000 = 0.9996kg

Parts per million:

2717mg / 0.9996kg = 2718 PPM

Mathematics
Step-by-step answer
P Answered by Specialist

b) True , this is right. But this is not for 1000 alone for any sample size of large number randomly drawn we can expect 95%

Step-by-step explanation:

Given that in 2013, the Pew Research Foundation reported that "45% of U.S. adults report that they live with one or more chronic conditions", and the standard error for this estimate is 1.2%

Let us check one by one answers given

a) False.  Because we can say 95% or 90% confident only that the true percent of US adults cannot be true.

b) True , this is right. But this is not for 1000 alone for any sample size of large number randomly drawn we can expect 95%

c) False this does not give whether less than 50% or not unless we know the confidence interval range.

d) False, std error is a measure of variation of all the items from the mean.

Chemistry
Step-by-step answer
P Answered by PhD

- Mole fraction of SO₃ : 0.135

- Partial pressure SO₃ = 0.128 atm

Explanation:

Let's find out the mole fraction to know, what we were asked.

Mole fraction = Moles of a gas / Total moles

Mole fraction can also corresponds to Pressures, like this:

Mole fraction = = Partial pressure of a gas  / Total pressure

And this values are the same

The total moles of gases are:

Moles of SO + Moles of O₂ + Moles of SO₃ =

26 + 83 + 17 = 126 moles

Mole Fraction SO₃ = Moles of SO₃ / Total moles

17 / 126 = 0.135

This can be used to find out the partial pressure

Mole fraction = Partial pressure SO₃ / Total pressure

0.135 = Partial pressure  SO₃ / 0.950 atm

0.135 atm . 0.950atm = Partial pressure  SO₃

Partial pressure SO₃ = 0.128 atm

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