Chemistry : asked on faithtaylor365

19.09.2020

How many grams of KBr are dissolved in 92.7 mL of a 0.955 M solution? Show your work.

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09.07.2023, solved by verified expert

Chemistry, Q&A Expert, I am a Assistant Professor in Maharaj Singh College Saharanpur, Uttar Pradesh, India

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10.5g of KBr

Explanation:

molarity = moles of solute / litres of solution

we are given the volume of the solution in milliliters but the formula uses litres so we have to convert

to convert to liters we divide the number of milliliters by 1000 ( because 1 liter has 1000 milliliters. )

so liters of solution = 92.7/1000 = 0.0927 L

we can now plug in what we are given and solve for moles of solute

recall molarity = moles of solute / litres of solution

molarity = 0.955M and liters of solution = 0.0927L

so

multiply both sides by 0.0927

we're left with moles of solute = 0.0885285 moles

Finally we must convert moles to grams

Molar mass of KBr = 39.0983 + 79.904 = g/mol

Using dimensional analysis we get

the mol KBr cancel out on both sides and we get which is equal to 10.5g (rounded)

So we can conclude that 10.5g of KBr is dissolved in 92.7mL of a 0.955M solution.

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Chemistry

How many grams of KBr are dissolved in 92.7 mL of a 0.955 M solution? Show your work.

Step-by-step answer

P Answered by Master

10.5g of KBr

Explanation:

molarity = moles of solute / litres of solution

we are given the volume of the solution in milliliters but the formula uses litres so we have to convert

to convert to liters we divide the number of milliliters by 1000 ( because 1 liter has 1000 milliliters. )

so liters of solution = 92.7/1000 = 0.0927 L

we can now plug in what we are given and solve for moles of solute

recall molarity = moles of solute / litres of solution

molarity = 0.955M and liters of solution = 0.0927L

so $0.955M=\frac{moles.of.solute}{0.0927L}$

multiply both sides by 0.0927

we're left with moles of solute = 0.0885285 moles

Finally we must convert moles to grams

Molar mass of KBr = 39.0983 + 79.904 = g/mol

Using dimensional analysis we get $\frac{0.0885285molKBr}{} *\frac{119.002g}{1molKBr}$

the mol KBr cancel out on both sides and we get 0.0885285 *119.002g which is equal to 10.5g (rounded)

So we can conclude that 10.5g of KBr is dissolved in 92.7mL of a 0.955M solution.

Chemistry

Fiona claims that the diagram below shows simple machines, but Chad claims that it shows a compound machine. A man pushes a shopping cart up a ramp. Which statement best explains who is correct? Fiona is correct because less than three machines are shown in the diagram. Fiona is correct because the diagram shows two individual simple machines. Chad is correct because more than one machine is shown in the diagram. Chad is correct because the diagram shows two simple machines doing a job.

Step-by-step answer

P Answered by Specialist

Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation:
A mechanical device using which we can change the direction or magnitude of force applied is known as simple machine.
For example, in the given diagram there are two individual simple machines.
The machine helps in changing the direction or magnitude of force applied by the man. As a result, it becomes easy for him to carry different things easily from one place to another.
Thus, we can conclude that the statement Fiona is correct because the diagram shows two individual simple machines, is correct.
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation

Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation

Chemistry

Based on the equation, how many grams of Br2 are required to react completely with 29.2 grams of AlCl3 (5 points)? 2AlCl3 + 3Br2 → 2AlBr3 + 3Cl2

Step-by-step answer

P Answered by PhD

1

Answer:

52.6 gram

Step-by-step explanation:

It is clear by the equation 2(27+3×35.5)= 267 gm of AlCl3 reacts with 6× 80 = 480 gm of Br2 . So 29.2 gm reacts = 480× 29.2/267= 52.6 gm

Chemistry

The reaction of 15 moles carbon with 30 moles O2. Will result in a theoretical yield of_ moles CO2.

Step-by-step answer

P Answered by PhD

15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.

Chemistry

carbon 14 has a half life of 5730 years how much carbon 14 will remain in a 100 g sample after 11460 years

Step-by-step answer

P Answered by PhD

Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g

Chemistry

The half life of radium 226 is 1602 years. If you have 500 grams of radium today how many grams would have been present 9612 years ago?

Step-by-step answer

P Answered by PhD

Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g

Chemistry

A magnesium chloride solution reacts with potassium phosphate solution to form a white precipitate.knowing that virtually all potassium compounds are soluble they dissolve in water,write the balanced equation for this reaction.include all subscripts

Step-by-step answer

P Answered by PhD

Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows (look at the picture)

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.
Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined a

Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined a

Chemistry

Chemistry, 29.01.2021 19:10 Lovely7290 Which chemical name and formula are correct A. Diarsenic pentoxide, A5O5 B. carbon tetrachloride, CCI4 C. Sodium dichromate, Na2Cr2 D. magnesium phosphide, MgP please help

Step-by-step answer

P Answered by PhD

Answer: B. carbon tetrachloride, CCI4
Explanation: The other options are incorrect. Let's write the correct formulas:
A. Diarsenic pentoxide - As2O5
C. Sodium dichromate - Na2Cr2O7
D. magnesium phosphide - Mg3P2

Chemistry

Classify each solution as acidic, basic, or neutral. a. [H+] = 6.0 x 10-10M b. [OH-] = 30 × 10-2M C. IH+1 = 20× 10-7M d. [OH-] = 1.0 x 10-7M

Step-by-step answer

P Answered by PhD

Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified in terms of hydrogen ions or hydroxide ions, or in terms of electron pairs. (look at the picture)
Let us note that from the pH scale, a pH of;
0 - 6.9 is acidic
7 is neutral
8 - 14 is basic

But pH= - log [H^+]
pOH = -log [OH^-]
Then;
pH + pOH = 14
Hence;
pH = 14 - pOH

a. [H+] = 6.0 x 10-10M
pH= 9.22 is basic
b. [OH-] = 30 × 10-2M
pH = 13.5 is basic
C. IH+1 = 20× 10-7M
pH = 0.56 is acidic
d. [OH-] = 1.0 x 10-7M
pH = 7 is neutral
Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified

Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified

Chemistry

A hot air balloon contains 270.0 L of helium at 24 degrees C and 845 mm Hg. What will be the volume of the balloon at -50.0 degrees C and a pressure of 0.735 atm?

Step-by-step answer

P Answered by PhD

1

Answer: 306 L
Explanation: Using the ideal gas law,
PV = nRT
where R = 0.08206 L•atm/(mol•°K), solving for n gives
n = PV/(RT)
n = (845 mmHg) (270 L) / ((0.08206 L•atm/(mol•°K)) (24 °C))

Convert the given temperature to °K and the given pressure to atm:
24 °C = (273.15 + 24) °K ≈ 297.2 °K
(845 mmHg) × (1/760 atm/mmHg) ≈ 1.11 atm

Then the balloon contains
n = (1.11 atm) (270 L) / ((0.08206 L•atm/(mol•°K)) (297.2 °K))
n ≈ 12.3 mol
of He.

Solve the same equation for V :
V = nRT/P

Convert the target temperature to °K:
-50 °C = (273.15 - 50) °K = 223.15 °K

Then the volume under the new set of conditions is
V = (12.3 mol) (0.08206 L•atm/(mol•°K)) (223.15 °K) / (0.735 atm)
V ≈ 306 L

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