19.09.2020

How many grams of KBr are dissolved in 92.7 mL of a 0.955 M solution? Show your work.

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09.07.2023, solved by verified expert
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10.5g of KBr

Explanation:

molarity = moles of solute / litres of solution

we are given the volume of the solution in milliliters but the formula uses litres so we have to convert

to convert to liters we divide the number of milliliters by 1000 ( because 1 liter has 1000 milliliters. )

so liters of solution = 92.7/1000 = 0.0927 L

we can now plug in what we are given and solve for moles of solute

recall molarity = moles of solute / litres of solution

molarity = 0.955M and liters of solution = 0.0927L

so How many grams of KBr are dissolved in 92.7 mL, №18011175, 19.09.2020 17:13

multiply both sides by 0.0927

we're left with moles of solute = 0.0885285 moles

Finally we must convert moles to grams

Molar mass of KBr = 39.0983 + 79.904 =  g/mol

Using dimensional analysis we get How many grams of KBr are dissolved in 92.7 mL, №18011175, 19.09.2020 17:13

the mol KBr cancel out on both sides and we get How many grams of KBr are dissolved in 92.7 mL, №18011175, 19.09.2020 17:13 which is equal to 10.5g (rounded)

So we can conclude that 10.5g of KBr is dissolved in 92.7mL of a 0.955M solution.

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Chemistry
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P Answered by Master

10.5g of KBr

Explanation:

molarity = moles of solute / litres of solution

we are given the volume of the solution in milliliters but the formula uses litres so we have to convert

to convert to liters we divide the number of milliliters by 1000 ( because 1 liter has 1000 milliliters. )

so liters of solution = 92.7/1000 = 0.0927 L

we can now plug in what we are given and solve for moles of solute

recall molarity = moles of solute / litres of solution

molarity = 0.955M and liters of solution = 0.0927L

so 0.955M=\frac{moles.of.solute}{0.0927L}

multiply both sides by 0.0927

we're left with moles of solute = 0.0885285 moles

Finally we must convert moles to grams

Molar mass of KBr = 39.0983 + 79.904 =  g/mol

Using dimensional analysis we get \frac{0.0885285molKBr}{} *\frac{119.002g}{1molKBr}

the mol KBr cancel out on both sides and we get 0.0885285 *119.002g which is equal to 10.5g (rounded)

So we can conclude that 10.5g of KBr is dissolved in 92.7mL of a 0.955M solution.

Chemistry
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P Answered by PhD
Answer: chalcogens.
Explanation: Strontium is an alkaline earth metal, it always exhibits a degree of oxidation in its compounds +2.
Chalcogens are a group of 6 chemical elements (oxygen O, sulfur S, selenium se, tellurium te, polonium Po) that have an oxidation state of -2 => Chalcogens will combine with strontium in a ratio of 1:1.
Chemistry
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P Answered by Master

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the
Chemistry
Step-by-step answer
P Answered by PhD

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry
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P Answered by PhD

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N ×328 K

Solving:

Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry
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P Answered by PhD
15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.
Chemistry
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P Answered by PhD
Answer: 25 g
Explanation: Given:
Original amount (N₀) = 100 g
Number of half-lives (n) = 11460/5730 = 2
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^2 × 100
N = 0.25 × 100
N = 25 g
Chemistry
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P Answered by PhD
Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g
Chemistry
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P Answered by PhD
Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified in terms of hydrogen ions or hydroxide ions, or in terms of electron pairs. (look at the picture)
Let us note that from the pH scale, a pH of;
0 - 6.9 is acidic
7 is neutral
8 - 14 is basic

But pH= - log [H^+]
pOH = -log [OH^-]
Then;
pH + pOH = 14
Hence;
pH = 14 - pOH

a. [H+] = 6.0 x 10-10M
pH= 9.22 is basic
b. [OH-] = 30 × 10-2M
pH = 13.5 is basic
C. IH+1 = 20× 10-7M
pH = 0.56 is acidic
d. [OH-] = 1.0 x 10-7M
pH = 7 is neutral
Answer: a. basic
b. basic
c. acidic
d. neutral

Explanation: Acids and bases can be classified
Chemistry
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P Answered by PhD
Answer: 306 L
Explanation: Using the ideal gas law,
PV = nRT
where R = 0.08206 L•atm/(mol•°K), solving for n gives
n = PV/(RT)
n = (845 mmHg) (270 L) / ((0.08206 L•atm/(mol•°K)) (24 °C))

Convert the given temperature to °K and the given pressure to atm:
24 °C = (273.15 + 24) °K ≈ 297.2 °K
(845 mmHg) × (1/760 atm/mmHg) ≈ 1.11 atm

Then the balloon contains
n = (1.11 atm) (270 L) / ((0.08206 L•atm/(mol•°K)) (297.2 °K))
n ≈ 12.3 mol
of He.

Solve the same equation for V :
V = nRT/P

Convert the target temperature to °K:
-50 °C = (273.15 - 50) °K = 223.15 °K

Then the volume under the new set of conditions is
V = (12.3 mol) (0.08206 L•atm/(mol•°K)) (223.15 °K) / (0.735 atm)
V ≈ 306 L

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