A 10 kg dog runs across the ground and jumps onto an ice-covered pond at 5 m/s. If the force of friction acting on the dog is 8 N, how far will the dog slide before coming to rest?

15.625m

Explanation:

Using the equation of motion

v² = u²+2as

u and v are the initial and final velocities

a is the acceleration

s is the distance

Get the acceleration

According to Newton's second law;

F  = ma

8 = 10a

a = 8/10

a = 0.8m/s²

We are also given

v = 5m/s

u = 0m/s

Substitute into the formula above

v² = u²+2as

5² = 0²+2(0.8)s

25 = 1.6s

s = 25/1.6

s = 15.625m

Hence the dog will cover a distance of 15.625m before coming to rest

Independent variable: the best method to get rid of them.

Dependent variable: washing with soap and water.

Hypothesis: Organic oils

Control group: water

Answer:

Step-by-step explanation:

D.
Heat each cube to the same temperature, place each cube into different containers with 500 grams of water at the same temperature, and measure the temperature of the water.

Answer:

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02