15.625m
Explanation:
Using the equation of motion
v² = u²+2as
u and v are the initial and final velocities
a is the acceleration
s is the distance
Get the acceleration
According to Newton's second law;
F = ma
8 = 10a
a = 8/10
a = 0.8m/s²
We are also given
v = 5m/s
u = 0m/s
Substitute into the formula above
v² = u²+2as
5² = 0²+2(0.8)s
25 = 1.6s
s = 25/1.6
s = 15.625m
Hence the dog will cover a distance of 15.625m before coming to rest