23.11.2022

Prove that 1/sin^2A -1/tan^2A= 1

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Step-by-step answer

09.07.2023, solved by verified expert

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Mathematics
Step-by-step answer
P Answered by Specialist

Step-by-step explanation:

LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS

Hint: 1 - Cos² A = Sin² A

Mathematics
Step-by-step answer
P Answered by PhD

To prove that:

$\frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}=1

LHS = \frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}

Using basic trigonometric identity, \tan (x)=\frac{\sin (x)}{\cos (x)}

       $=\frac{1}{\sin ^{2}A}-\frac{1}{\left(\frac{\sin A}{\cos A}\right)^{2}}

      $=\frac{1}{\sin ^{2}A}-\frac{1}{\frac{\sin^2A}{\cos^2 A}}

      $=\frac{1}{\sin ^{2}A}-\frac{\cos^2 A}{\sin^2A}

      $=\frac{1-{\cos^2 A}}{\sin ^{2}A}

Using trigonometric identity: 1-\cos ^{2}(x)=\sin ^{2}(x)

      $=\frac{\sin ^{2}A}{\sin ^{2}A}

      = 1

      = RHS

LHS = RHS

$\frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}=1

Hence proved.

Mathematics
Step-by-step answer
P Answered by PhD

To prove that:

$\frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}=1

LHS = \frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}

Using basic trigonometric identity, \tan (x)=\frac{\sin (x)}{\cos (x)}

       $=\frac{1}{\sin ^{2}A}-\frac{1}{\left(\frac{\sin A}{\cos A}\right)^{2}}

      $=\frac{1}{\sin ^{2}A}-\frac{1}{\frac{\sin^2A}{\cos^2 A}}

      $=\frac{1}{\sin ^{2}A}-\frac{\cos^2 A}{\sin^2A}

      $=\frac{1-{\cos^2 A}}{\sin ^{2}A}

Using trigonometric identity: 1-\cos ^{2}(x)=\sin ^{2}(x)

      $=\frac{\sin ^{2}A}{\sin ^{2}A}

      = 1

      = RHS

LHS = RHS

$\frac{1}{\sin ^{2}A}-\frac{1}{\tan ^{2}A}=1

Hence proved.

Business
Step-by-step answer
P Answered by Specialist

1.

The annual net cost savings promised by the automated welding machine

Annual Costs savings in replacing 6 welders $108,000

Reduced Material costs $6,500

Total annual Costs savings = $114,500

Note there is a $3,000 annual maintenance cost that will then be taken off this savings amount to make up the Annual Net cash inflow of $111,500

2

A. The Net Present value is $72,227. Kindly refer to the attached document for the clear presentation

B. The project should be accepted because it delivers a positive NPV. Meaning the net benefit outweighs the cost of owning the new Assets.

3.

The Discounted net Cash flow for the 6 years (aside the initial outlay) is $402,227.

Annually this comes to $67,038.

The benefit the business gets in the switch to the automatic welders is approximately $67,038 annually.


I’m not sure we should lay out $250,000 for that automated welding machine, said Jim Alder, presid
Mathematics
Step-by-step answer
P Answered by PhD

SI=(P*R*T)/100

P=2000

R=1.5

T=6

SI=(2000*1.5*6)/100

=(2000*9)/100

=180

Neil will earn interest of 180

Mathematics
Step-by-step answer
P Answered by PhD

Cost of 7 gallons=$24.50

Cost of 1 gallon=24.50/7=3.5

Cost of 15 gallons=15*3.5=52.5

Cost of 15 gallons will be $52.5

Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

Mathematics
Step-by-step answer
P Answered by PhD

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

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