13.01.2022

# 9/11 x 7/10 - 9/11 x 3/10

1

09.07.2023, solved by verified expert

Step-by-step explanation:

Given the following question:

Multiply the fractions, by multiplying the numerators by the numerators, doing the same with the denominators.

Now subtract:

Simplify:

Hope this helps.

18/55

Step-by-step explanation:

### Faq

Mathematics

Step-by-step explanation:

Given the following question:

Multiply the fractions, by multiplying the numerators by the numerators, doing the same with the denominators.

Now subtract:

Simplify:

Hope this helps.

Chemistry

Complete question:

Assume that five weak acids, identified only by numbers (1, 2, 3, 4, and 5) have the following ionization constants: A1 - Ka = 1.0 x 10-3 A2 - Ka = 3.0 x 10-5 A3 - Ka = 2.6 x 10-7 A4 - Ka = 4.0 x 10-9 A5 - Ka = 7.3 x 10-11

The anion of which acid is the strongest base? a) A2 b) A5 c) A3 d) A1 e) A4

(B) The anion with the strongest base is A5

Explanation:

Acidity of a solution depends on the concentration of H⁺

Assuming a constant solution molarity (HA), then

pH = -Log{H⁺]

For A1: ,             pH = 1.5

For A2: ,          pH = 2

For A3:       pH = 3

For A4:        pH = 4

For A5:  pH = 5

From the calculation above, the strongest acid is A1 and the weakest Acid is A5.

Therefore, the anion with the strongest base is A5

Chemistry

Complete question:

Assume that five weak acids, identified only by numbers (1, 2, 3, 4, and 5) have the following ionization constants: A1 - Ka = 1.0 x 10-3 A2 - Ka = 3.0 x 10-5 A3 - Ka = 2.6 x 10-7 A4 - Ka = 4.0 x 10-9 A5 - Ka = 7.3 x 10-11

The anion of which acid is the strongest base? a) A2 b) A5 c) A3 d) A1 e) A4

(B) The anion with the strongest base is A5

Explanation:

Acidity of a solution depends on the concentration of H⁺

Assuming a constant solution molarity (HA), then

pH = -Log{H⁺]

For A1: ,             pH = 1.5

For A2: ,          pH = 2

For A3:       pH = 3

For A4:        pH = 4

For A5:  pH = 5

From the calculation above, the strongest acid is A1 and the weakest Acid is A5.

Therefore, the anion with the strongest base is A5

Mathematics

1)b.48 2)d.81 3)a.11 4)b.–81 5)–246 c.5ft a.19 9/25 in² d.11 mi/h a.48 C.a=m–c/–b

Step-by-step explanation:

4²+(4×2³)=16+(4×8)=16+32=48

(–3)⁴=3²×3²=9×9=81

–2n²+5n+9 (n=2)

–2(2²)+5(2)+9=–2×4+5×2+9=–8+10+9=11

3x³ (x=–3)

3(–3)³=3×–27=–81

4r²–2s³ (r=1 s=5)

4×1–2×125=4–250=–246

A=½bh. ½b=A/h. b=2A/h

then b=(2×30)÷12=5ft

area of a square=s×s=

d=rt then r=d/t

then r=15.4÷1.4=11 mi/h

(–h–3j)²/h (h=3, j=–5)

(–3–3×–5)²÷3=(12)²÷3=144÷3=48

m=c–ab m–c=–ab m–c/–b=a

Mathematics

1)b.48 2)d.81 3)a.11 4)b.–81 5)–246 c.5ft a.19 9/25 in² d.11 mi/h a.48 C.a=m–c/–b

Step-by-step explanation:

4²+(4×2³)=16+(4×8)=16+32=48

(–3)⁴=3²×3²=9×9=81

–2n²+5n+9 (n=2)

–2(2²)+5(2)+9=–2×4+5×2+9=–8+10+9=11

3x³ (x=–3)

3(–3)³=3×–27=–81

4r²–2s³ (r=1 s=5)

4×1–2×125=4–250=–246

A=½bh. ½b=A/h. b=2A/h

then b=(2×30)÷12=5ft

area of a square=s×s=

d=rt then r=d/t

then r=15.4÷1.4=11 mi/h

(–h–3j)²/h (h=3, j=–5)

(–3–3×–5)²÷3=(12)²÷3=144÷3=48

m=c–ab m–c=–ab m–c/–b=a

Engineering

See explaination

Explanation:

This function reverses the position

of the consonants keeping the

position of vowel constant.

Parameters:

data : type(str)

The string on which operation

needs to be performed

start : type(int)

Starting index of the string

end : type(int)

Ending index of the string

"""

def consonantReverse(data, start = 0, end = None):

# By default user will psas the data only.

# End will be none which will be set to length of string - 1

if(end == None):

return consonantReverse(data, 0, len(data)-1)

# return as this is invalid

if(start >= end):

return data

# split the data into list

if type(data)== str:

data = list(data)

# initialize index1 and index2

index1 = len(data)

index2 = -1

# find out the first index from beggining

# where consonant is present

for i in range(start, end+1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index1 = i

break

# find out the index from the end

# where consonant is present

for i in range(end, start-1, -1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index2 = i

break

# return as this is not valid case

if(index1 >= index2):

return ''.join(data)

# swap the data in the two index

data[index1], data[index2] = data[index2], data[index1]

# call the function recursively

data = consonantReverse(data, index1+1, index2-1)

# if it is a list, join the list into string

if(type(data) == list):

return ''.join(data)

# otherwise return the data

else:

return data

Engineering

See explaination

Explanation:

This function reverses the position

of the consonants keeping the

position of vowel constant.

Parameters:

data : type(str)

The string on which operation

needs to be performed

start : type(int)

Starting index of the string

end : type(int)

Ending index of the string

"""

def consonantReverse(data, start = 0, end = None):

# By default user will psas the data only.

# End will be none which will be set to length of string - 1

if(end == None):

return consonantReverse(data, 0, len(data)-1)

# return as this is invalid

if(start >= end):

return data

# split the data into list

if type(data)== str:

data = list(data)

# initialize index1 and index2

index1 = len(data)

index2 = -1

# find out the first index from beggining

# where consonant is present

for i in range(start, end+1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index1 = i

break

# find out the index from the end

# where consonant is present

for i in range(end, start-1, -1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index2 = i

break

# return as this is not valid case

if(index1 >= index2):

return ''.join(data)

# swap the data in the two index

data[index1], data[index2] = data[index2], data[index1]

# call the function recursively

data = consonantReverse(data, index1+1, index2-1)

# if it is a list, join the list into string

if(type(data) == list):

return ''.join(data)

# otherwise return the data

else:

return data

Chemistry

Answer 1) Option a) have an atomic number greater than 83

Explanation : Nuclear decay by alpha particle emission is more common in atoms of elements that have an atomic number greater than 83. Nuclear reactions occurs with the elements which have mass number more than 200.

Explanation : In the given nuclear reaction of helium;

Two helium isotopes combines to give another helium isotope with emission of a proton (P).

Answer 3) Option D) The products are more radioactive than the reactants.

Explanation : The major drawback of a nuclear fission reaction to be used as an reliable energy source is that it usually produces the products which are found to be more radioactive than the reactants.

Answer 4) Option D) All of the above concerns.

Explanation : Nuclear reactions are usually very harmful in nature. It raises many concerns about the waste disposal that is generated from the reaction. It also requires safe operation for the working nuclear plants. It can also be misused for nuclear weapon proliferation. Hence, the answer is all of the above.

Explanation : The energy output of the Sun and other stars is a result of fusion reactions among hydrogen nuclei. In fusion reactions usually additions takes place.

Answer 6) Option B) The "missing" mass has been converted to energy

Explanation : The total mass of a helium nucleus not equal to the mass of its individual parts because the missing mass has to be converted into energy.

Answer 7) Option A) less than the mass-energy of the products

Explanation : In a nuclear reaction, the mass-energy of the reactants is generally less than that of the mass-energy of the products because some energy has to be generated while the reaction is progressing.

Explanation : The calculation of the mass of 10.0 kilograms is completely converted into energy.

formula can be used.

here m = 10 Kg and C =

E = 10 X = .

Explanation : For calculation of energy for mass of 4 Kg

we can use the Einstein's formula,

where m = 4 Kg and C = C =

E = 4 X = .

Einstein's formula for the conversion of mass and energy, to find the energy, multiply the mass by the speed of light squared.

Chemistry

Answer 1) Option a) have an atomic number greater than 83

Explanation : Nuclear decay by alpha particle emission is more common in atoms of elements that have an atomic number greater than 83. Nuclear reactions occurs with the elements which have mass number more than 200.

Explanation : In the given nuclear reaction of helium;

Two helium isotopes combines to give another helium isotope with emission of a proton (P).

Answer 3) Option D) The products are more radioactive than the reactants.

Explanation : The major drawback of a nuclear fission reaction to be used as an reliable energy source is that it usually produces the products which are found to be more radioactive than the reactants.

Answer 4) Option D) All of the above concerns.

Explanation : Nuclear reactions are usually very harmful in nature. It raises many concerns about the waste disposal that is generated from the reaction. It also requires safe operation for the working nuclear plants. It can also be misused for nuclear weapon proliferation. Hence, the answer is all of the above.

Explanation : The energy output of the Sun and other stars is a result of fusion reactions among hydrogen nuclei. In fusion reactions usually additions takes place.

Answer 6) Option B) The "missing" mass has been converted to energy

Explanation : The total mass of a helium nucleus not equal to the mass of its individual parts because the missing mass has to be converted into energy.

Answer 7) Option A) less than the mass-energy of the products

Explanation : In a nuclear reaction, the mass-energy of the reactants is generally less than that of the mass-energy of the products because some energy has to be generated while the reaction is progressing.

Explanation : The calculation of the mass of 10.0 kilograms is completely converted into energy.

formula can be used.

here m = 10 Kg and C =

E = 10 X = .

Explanation : For calculation of energy for mass of 4 Kg

we can use the Einstein's formula,

where m = 4 Kg and C = C =

E = 4 X = .

Einstein's formula for the conversion of mass and energy, to find the energy, multiply the mass by the speed of light squared.

StudenGPT
To rearrange each equation in standard form with a positive lead coefficient, we need to follow these steps: 7. $$y = -\frac{3}{4}x + 2$$ To convert this equation into the standard form $$Ax + By = C$$, we'll start by eliminating the fraction. Multiply the entire equation by 4 to get rid of the denominator: $$4y = -3x + 8$$ Next, let's move all the terms to one side of the equation: $$3x + 4y = 8$$ Since we want the lead coefficient to be positive, we can multiply the entire equation by -1: $$-3x - 4y = -8$$ So the rearranged equation in standard form is $$-3x - 4y = -8$$. Let's apply the same steps to the other equations: 10. $$y = \frac{3}{4}x + \frac{1}{2}$$ Multiply the entire equation by 4: $$4y = 3x + 2$$ Move all the terms to one side: $$-3x + 4y = 2$$ Multiply by -1: $$3x - 4y = -2$$ The rearranged equation in standard form is $$3x - 4y = -2$$. 8. $$y = -x - 5$$ Move all the terms to one side: $$x + y = -5$$ Multiply by -1: $$-x - y = 5$$ The rearranged equation in standard form is $$-x - y = 5$$. 11. $$y = 3x + 6$$ Move all the terms to one side: $$-3x + y = 6$$ The rearranged equation in standard form is $$-3x + y = 6$$. 9. $$y = \frac{1}{2}x - 2$$ Multiply by 2: $$2y = x - 4$$ Move all the terms to one side: $$-x + 2y = -4$$ Multiply by -1: $$x - 2y = 4$$ The rearranged equation in standard form is $$x - 2y = 4$$. 12. $$y = -\frac{1}{4}x + 8$$ Multiply by 4: $$4y = -x + 32$$ Move all the terms to one side: $$x + 4y = 32$$ The rearranged equation in standard form is $$x + 4y = 32$$. Please double-check each step to ensure accuracy in the rearranged equations.