Answer : The required ratio is (14m-6):(8m+23) .
Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .
That is.
As , we know that the sum of n terms of an AP is given by ,
Assume that ,
First term of 1st AP = a First term of 2nd AP = a'Common difference of 1st AP = dCommon difference of 2nd AP = d'Using this we have ,
Now also we know that the nth term of an AP is given by ,
Therefore,
From equation (i) and (iii) ,
Substitute this value in equation (i) ,
Simplify,
From equation (ii) ,