20.01.2021

3. Find the area of a trapezoid with bases 20 cm and 14 cm and height 5 cm.

. 1

Step-by-step answer

09.07.2023, solved by verified expert
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Given :

Base = 20 cm and 14 cm.Height = 5 cm.

To find :

Area of trapezoid.

Solution :

We know,

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

Now, Substituting the values :

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

Therefore,

The area of the trapezoid is 85 cm² .
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85cm²

Step-by-step explanation:

Here we are given a trapezium with base = 20cm and 14cm and height = 5cm . And we are interested in finding the area of the trapezium .

Figure :-

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

As we know that the area of trapezium is given by ,

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

Here 20cm and 14cm are parallel sides .

Substitute the respective values in stated formula,

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

Solve the parenthesis ,

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

Simplify by multiplying ,

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

And we are done !

3. Find the area of a trapezoid with bases 20, №18010226, 20.01.2021 02:18

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Faq

Mathematics
Step-by-step answer
P Answered by Specialist

Given :

Base = 20 cm and 14 cm.Height = 5 cm.

To find :

Area of trapezoid.

Solution :

We know,

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 }  \times (b_{1} + b_{2}) \times h} }}

Now, Substituting the values :

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 }  \times (20 + 14) \times 5} }}

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{2 }  \times 34} }}

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{ \cancel2 }  \times  \cancel{34}} }}

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=5 \times 17} }}

{\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=85} }}

Therefore,

The area of the trapezoid is 85 cm² .
Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Given:

Area = 3x^3 - 16x^2 + 31x - 20

Base:

x^3 - 5x

Area of trapezoid, S = 1/2 × (A + B) × h

Using long division,

(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x

= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh

= 2S/Bh - A/B

= (2S/B × 1/h) - A/B

Since, x^3 - 5x = B

Comparing the above,

A = 32x^2 - 92x + 40

2S/B = 6

Therefore, h = 1

Mathematics
Step-by-step answer
P Answered by PhD
Area = (1/2)(a + b)h,

a + b = 20m + 30m = 50m

area = 375 m2.

=> h = 2 * area / (a + b)

h = 2 * (375m^2) / (50m) = 15 m

Altitude, h = 15 m.<> this is the option C.
Mathematics
Step-by-step answer
P Answered by Master

12

Step-by-step explanation:

he coordinates of the vertices of the trapezoid ABCD are:

A=(-5,-2)=(xa,ya)→xa=-5, ya=-2

B=(-1,2)=(xb,yb)→xb=-1, yb=2

C=(0,-1)=(xc,yc)→xc=0, yc=-1

D=(-2,-3)=(xd,yd)→xd=-2, yd=-3

yi x(i+1)        xi     yi     xi y(i+1)

                 -5    -2

(-2)(-1)=2     -1      2     (-5)(2)=-10

(2)(0)=0       0     -1     (-1)(-1)=1

(-1)(-2)=2    -2    -3     (0)(-3)=0

(-3)(-5)=15   -5    -2     (-2)(-2)=4

S1=-10+1+0+4→S1=-5

S2=2+0+2+15→S2=19

Area: A=(1/2) Absolute value (S1-S2)

A=(1/2) Absolute value (-5-19)

A=(1/2) Absolute value (-24)

A=(1/2) (24)

A=24/2

A=12

The area of the trapezoid is 12 square units

Mathematics
Step-by-step answer
P Answered by PhD
Area = (1/2)(a + b)h,

a + b = 20m + 30m = 50m

area = 375 m2.

=> h = 2 * area / (a + b)

h = 2 * (375m^2) / (50m) = 15 m

Altitude, h = 15 m.<> this is the option C.
Mathematics
Step-by-step answer
P Answered by Master

12

Step-by-step explanation:

he coordinates of the vertices of the trapezoid ABCD are:

A=(-5,-2)=(xa,ya)→xa=-5, ya=-2

B=(-1,2)=(xb,yb)→xb=-1, yb=2

C=(0,-1)=(xc,yc)→xc=0, yc=-1

D=(-2,-3)=(xd,yd)→xd=-2, yd=-3

yi x(i+1)        xi     yi     xi y(i+1)

                 -5    -2

(-2)(-1)=2     -1      2     (-5)(2)=-10

(2)(0)=0       0     -1     (-1)(-1)=1

(-1)(-2)=2    -2    -3     (0)(-3)=0

(-3)(-5)=15   -5    -2     (-2)(-2)=4

S1=-10+1+0+4→S1=-5

S2=2+0+2+15→S2=19

Area: A=(1/2) Absolute value (S1-S2)

A=(1/2) Absolute value (-5-19)

A=(1/2) Absolute value (-24)

A=(1/2) (24)

A=24/2

A=12

The area of the trapezoid is 12 square units

Mathematics
Step-by-step answer
P Answered by PhD

1. -6 (2y + 7)

2. 1/3 (2p - 45)

3. \frac{12x-32}{4}

4. sorry i'm not entirely sure how to do this one...

Step-by-step explanation:

1. factoring a number out of something is basically just dividing the given set (in this case -12y - 42) by the number you are trying to take out

so divide each part of the equation by -6

-12 ÷ -6 and -42 ÷ -6

now put the -6 out side a parenthesis to get -6 (2y + 7)

2. same thing here

divide both parts by 1/3 so 2/3p ÷ 1/3 and -15 ÷ 1/3

remember when dividing by fractions to flip the fraction and turn the sign to a multiplication sign

so here its the same thing as multiplying the numbers by 3

you should get 1/3 (2p - 45)

3.  this one is kinda simple, just take the given equation and divide it by 4

this is because a square has 4 equal sides

so dividing by 4 means that you would get the length og one side

you should get \frac{12x-32}{4}

4. sorry again idk how to help with this :(

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