Mathematics : asked on dinapaul424

20.01.2021

3. Find the area of a trapezoid with bases 20 cm and 14 cm and height 5 cm.

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Step-by-step answer

09.07.2023, solved by verified expert

Chemistry, Q&A Expert, I am a Assistant Professor in Maharaj Singh College Saharanpur, Uttar Pradesh, India

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Given :

Base = 20 cm and 14 cm.Height = 5 cm.

To find :

Area of trapezoid.

Solution :

We know,

Now, Substituting the values :

Therefore,

The area of the trapezoid is 85 cm² .

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Mathematics, English, Physics. Research Scholar at Indian Institute of Technology, Roorkee

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85cm²

Step-by-step explanation:

Here we are given a trapezium with base = 20cm and 14cm and height = 5cm . And we are interested in finding the area of the trapezium .

Figure :-

As we know that the area of trapezium is given by ,

Here 20cm and 14cm are parallel sides .

Substitute the respective values in stated formula,

Solve the parenthesis ,

Simplify by multiplying ,

And we are done !

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Mathematics

3. Find the area of a trapezoid with bases 20 cm and 14 cm and height 5 cm.

Step-by-step answer

P Answered by Specialist

Given :

Base = 20 cm and 14 cm.Height = 5 cm.

To find :

Area of trapezoid.

Solution :

We know,

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (b_{1} + b_{2}) \times h} }}$

Now, Substituting the values :

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{1}{2 } \times (20 + 14) \times 5} }}$

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{2 } \times 34} }}$

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}= \dfrac{5}{ \cancel2 } \times \cancel{34}} }}$

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=5 \times 17} }}$

${\qquad \dashrightarrow{ \bf{Area_{(Trapezoid)}=85} }}$

Therefore,

The area of the trapezoid is 85 cm² .

Geography

On a coordinate plane, a trapezoid is inside of a rectangle to form 3 triangles within the rectangle. The trapezoid has points (4, 4), (4, 14), (12, 20), and (20, 16). The rectangle has points (4, 4), (4, 20), (20, 20), and (20, 4). Triangle 1 has points (4, 14), (4, 20), (12, 20). Triangle 2 has points (12, 20), (20, 20), (20, 16). Triangle 3 has points (4, 4), (20, 16), (20, 4). Complete the steps to find the area of the trapezoid. Area of rectangle = square units Area of triangle 1 = square units Area of triangle 2 = square units Area of triangle

Step-by-step answer

P Answered by Master

46

The correct answers in order are: 256, 24, 16, 96, 120

Explanation:

I completed this assignment

Geography

On a coordinate plane, a trapezoid is inside of a rectangle to form 3 triangles within the rectangle. The trapezoid has points (4, 4), (4, 14), (12, 20), and (20, 16). The rectangle has points (4, 4), (4, 20), (20, 20), and (20, 4). Triangle 1 has points (4, 14), (4, 20), (12, 20). Triangle 2 has points (12, 20), (20, 20), (20, 16). Triangle 3 has points (4, 4), (20, 16), (20, 4). Complete the steps to find the area of the trapezoid. Area of rectangle = square units Area of triangle 1 = square units Area of triangle 2 = square units Area of triangle

Step-by-step answer

P Answered by Specialist

46

The correct answers in order are: 256, 24, 16, 96, 120

Explanation:

I completed this assignment

Mathematics

The polynomial 3x ^ 3 - 16x ^ 2 + 31x - 20 the area of a trapezoidal desktop . Of the bases of the x ^ 3 - 5x the height of the trapezoid? Hins: Use long division , what is trapezoid represented by the expressions trapezoid

Step-by-step answer

P Answered by Master

Step-by-step explanation:

Given:

Area = 3x^3 - 16x^2 + 31x - 20

Base:

x^3 - 5x

Area of trapezoid, S = 1/2 × (A + B) × h

Using long division,

(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x

= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh

= 2S/Bh - A/B

= (2S/B × 1/h) - A/B

Since, x^3 - 5x = B

Comparing the above,

A = 32x^2 - 92x + 40

2S/B = 6

Therefore, h = 1

Mathematics

Area of a trapezoid = (1/2)(a + b)h, where a and b are the lengths of the two parallel sides and h is the altitude. the area of a trapezoid is 375 m2. if the two parallel sides are 20 m and 30 m, respectively, what is the altitude of the trapezoid? altitude, h = m. a) 3.75 b) 7.5 c) 15

Step-by-step answer

P Answered by PhD

18

Area = (1/2)(a + b)h,

a + b = 20m + 30m = 50m

area = 375 m2.

=> h = 2 * area / (a + b)

h = 2 * (375m^2) / (50m) = 15 m

Altitude, h = 15 m.<> this is the option C.

Mathematics

Trapezoid ABCD is graphed in a coordinate plane. What is the area of the trapezoid? 5 4 3 В © 10 shyare units 12 square units 20 square units 24 square units -5 -3 -2 -1 2 3 4 5 no 3 D Save and Exit Nes Submit

Step-by-step answer

P Answered by Master

9

12

Step-by-step explanation:

he coordinates of the vertices of the trapezoid ABCD are:

A=(-5,-2)=(xa,ya)→xa=-5, ya=-2

B=(-1,2)=(xb,yb)→xb=-1, yb=2

C=(0,-1)=(xc,yc)→xc=0, yc=-1

D=(-2,-3)=(xd,yd)→xd=-2, yd=-3

yi x(i+1) xi yi xi y(i+1)

-5 -2

(-2)(-1)=2 -1 2 (-5)(2)=-10

(2)(0)=0 0 -1 (-1)(-1)=1

(-1)(-2)=2 -2 -3 (0)(-3)=0

(-3)(-5)=15 -5 -2 (-2)(-2)=4

S1=-10+1+0+4→S1=-5

S2=2+0+2+15→S2=19

Area: A=(1/2) Absolute value (S1-S2)

A=(1/2) Absolute value (-5-19)

A=(1/2) Absolute value (-24)

A=(1/2) (24)

A=24/2

A=12

The area of the trapezoid is 12 square units

Mathematics

Area of a trapezoid = (1/2)(a + b)h, where a and b are the lengths of the two parallel sides and h is the altitude. the area of a trapezoid is 375 m2. if the two parallel sides are 20 m and 30 m, respectively, what is the altitude of the trapezoid? altitude, h = m. a) 3.75 b) 7.5 c) 15

Step-by-step answer

P Answered by PhD

18

Area = (1/2)(a + b)h,

a + b = 20m + 30m = 50m

area = 375 m2.

=> h = 2 * area / (a + b)

h = 2 * (375m^2) / (50m) = 15 m

Altitude, h = 15 m.<> this is the option C.

Mathematics

Trapezoid ABCD is graphed in a coordinate plane. What is the area of the trapezoid? 5 4 3 В © 10 shyare units 12 square units 20 square units 24 square units -5 -3 -2 -1 2 3 4 5 no 3 D Save and Exit Nes Submit

Step-by-step answer

P Answered by Master

9

12

Step-by-step explanation:

he coordinates of the vertices of the trapezoid ABCD are:

A=(-5,-2)=(xa,ya)→xa=-5, ya=-2

B=(-1,2)=(xb,yb)→xb=-1, yb=2

C=(0,-1)=(xc,yc)→xc=0, yc=-1

D=(-2,-3)=(xd,yd)→xd=-2, yd=-3

yi x(i+1) xi yi xi y(i+1)

-5 -2

(-2)(-1)=2 -1 2 (-5)(2)=-10

(2)(0)=0 0 -1 (-1)(-1)=1

(-1)(-2)=2 -2 -3 (0)(-3)=0

(-3)(-5)=15 -5 -2 (-2)(-2)=4

S1=-10+1+0+4→S1=-5

S2=2+0+2+15→S2=19

Area: A=(1/2) Absolute value (S1-S2)

A=(1/2) Absolute value (-5-19)

A=(1/2) Absolute value (-24)

A=(1/2) (24)

A=24/2

A=12

The area of the trapezoid is 12 square units

Mathematics

HELLO I REALLY NEED HELP WITH THIS QUESTION: Felix calculated the area of a triangle with a base of 3 inches and a height of 1.5 inches. Edith calculated the area of a trapezoid with a height of 2 inches and parallel bases of 4 inches and 6 inches. Their work is shown below. Felix s work: A = 1/2bh A = 3(1.5) A = 45 inches2 Edith s work: A = 1/2(b1 + b2)h A = (4 + 6)2 A = 20 inches2 What error did they both make in their work? They didn’t multiply by the base. They didn’t multiply by the height. They didn’t multiply by one half. They didn’t use

Step-by-step answer

P Answered by Master

60

It is the 3rd choice, They didn't multiply by one half

Mathematics

Please help me I m struggling and will give 20 points if someone can explain some of these to me. Answer as many as possible and I ll be so grateful. I m just not understanding and I have a test tomorrow. 1) Factor -6 out of -12y - 42 2) Factor 1/3 out of 2/3p - 15 3) A square wrestling mat has a perimeter of (12x-32) feet. Write an expression that represents the side length of the mat in feet 4) The area of the trapezoids is (3/4x - 1/4) square centimeters. Write two different pairs of expressions that represent possible lengths of the bases.

Step-by-step answer

P Answered by PhD

1

1. -6 (2y + 7)

2. 1/3 (2p - 45)

3. $\frac{12x-32}{4}$

4. sorry i'm not entirely sure how to do this one...

Step-by-step explanation:

1. factoring a number out of something is basically just dividing the given set (in this case -12y - 42) by the number you are trying to take out

so divide each part of the equation by -6

-12 ÷ -6 and -42 ÷ -6

now put the -6 out side a parenthesis to get -6 (2y + 7)

2. same thing here

divide both parts by 1/3 so 2/3p ÷ 1/3 and -15 ÷ 1/3

remember when dividing by fractions to flip the fraction and turn the sign to a multiplication sign

so here its the same thing as multiplying the numbers by 3

you should get 1/3 (2p - 45)

3. this one is kinda simple, just take the given equation and divide it by 4

this is because a square has 4 equal sides

so dividing by 4 means that you would get the length og one side

you should get $\frac{12x-32}{4}$

4. sorry again idk how to help with this :(

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