x = -15/16
Step-by-step explanation:
see image.
Cross-multiply and combine like terms. Finally divide to get x all by itself.
x=3 y=4
x=a²+ab+b²/a+b , y=-ab/a+b
The system of the given equation may b written as:
ax+by-a²=0
bx+ay-b²=0
Here,
a1=a,b1=b,c1= -a²
a2=b,b2=a and c2= -b²
By cross multiplication we get
x/b*(-b²)-(-a²)*a = -y/a*(-b²)-(-a²)*b = 1/a*a-b*b
x/-b³+a³ = -y/-ab²+a²b = 1/a²-b²
Now
x/-b³+a³ = 1/a²-b²
x=a³-b³/a²-b²
x=(a-b)(a²+ab+b²)/(a-b)(a+b)
x=a²+ab+b²/a+b
And,
-y/-ab²+a²b = 1/a²-b²
-y=a²b -ab²/a²-b²
y=ab²-a²b/a²-b²
y=ab(b-a)/(a-b)(a+b)
y= -ab(a-b)/(a-b)(a+b)
y= -ab/a+b
Hence x=a²+ab+b²/a+b , y=-ab/a+b
Hello, Please refer the photo attachment for your question's answer. The final answer is :-
x= -2, y= 5
Hope it helps you...
Answered by Benjemin
x = 3
y = -2
x + 2y + 1 = 0
2x - 3y - 12 = 0
Multiply first equation by -2.
-2x + -4y + -2 = 0
Add equations.
0x + -7y - 14 = 0
Solve for y.
-7y = 14
y =-2
Put y as -2 in the first equation and solve for x.
x+2(-2)+1=0
x + -4 + 1 = 0
x = 0 + 4 - 1
2x + 3y = 46
3x + 5y = 74
Multiply 1st equation by 3 and 2nd equation by 2:
6x + 9y = 138
6x + 10y = 148
Subtract 2nd equation to 1st equation:
=> y = 148 - 138 = 10
=> 2x + 3*10 = 46
=> 2x = 16
=> x = 8
Hope this helps!
:)
It will provide an instant answer!