19.10.2021

Using the cross multiplication method, which of the following is the solution to 1/(x+1) = 17/(x+2)?

. 1

Step-by-step answer

09.07.2023, solved by verified expert
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x = -15/16

Step-by-step explanation:

see image.

Cross-multiply and combine like terms. Finally divide to get x all by itself.

see image.


Using the cross multiplication method, which, №18010286, 19.10.2021 13:15
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Mathematics
Step-by-step answer
P Answered by Specialist

x=3 y=4

Step-by-step explanation:


STD 10th

with full methodsolve the following pair of equations by thecross multiplication method0.
Mathematics
Step-by-step answer
P Answered by Master

x=3 y=4

Step-by-step explanation:


STD 10th

with full methodsolve the following pair of equations by thecross multiplication method0.
Mathematics
Step-by-step answer
P Answered by PhD

x=a²+ab+b²/a+b , y=-ab/a+b

Step-by-step explanation:

The system of the given equation may b written as:

ax+by-a²=0

bx+ay-b²=0

Here,

a1=a,b1=b,c1= -a²

a2=b,b2=a and c2= -b²

By cross multiplication we get

x/b*(-b²)-(-a²)*a = -y/a*(-b²)-(-a²)*b = 1/a*a-b*b

x/-b³+a³ = -y/-ab²+a²b  = 1/a²-b²

Now

x/-b³+a³ = 1/a²-b²

x=a³-b³/a²-b²

x=(a-b)(a²+ab+b²)/(a-b)(a+b)

x=a²+ab+b²/a+b

And,

-y/-ab²+a²b = 1/a²-b²

-y=a²b -ab²/a²-b²

y=ab²-a²b/a²-b²

y=ab(b-a)/(a-b)(a+b)

y= -ab(a-b)/(a-b)(a+b)

y= -ab/a+b

Hence x=a²+ab+b²/a+b , y=-ab/a+b

Mathematics
Step-by-step answer
P Answered by Specialist

Hello, Please refer the photo attachment for your question's answer. The final answer is :-

x= -2, y= 5

Hope it helps you...

Answered by Benjemin


3x+2y=4 8x+5y=9Please solve using Cross multiplication method.​
Mathematics
Step-by-step answer
P Answered by PhD

x = 3

y = -2

Step-by-step explanation:

x + 2y + 1 = 0

2x - 3y - 12 = 0

Multiply first equation by -2.

-2x + -4y + -2 = 0

2x - 3y - 12 = 0

Add equations.

0x + -7y - 14 = 0

Solve for y.

-7y = 14

y =-2

Put y as -2 in the first equation and solve for x.

x+2(-2)+1=0

x + -4 + 1 = 0

x = 0 + 4 - 1

x = 3

Mathematics
Step-by-step answer
P Answered by PhD

2x + 3y = 46

3x + 5y = 74

Multiply 1st equation by 3 and 2nd equation by 2:

6x + 9y = 138

6x + 10y = 148

Subtract 2nd equation to 1st equation:

=> y = 148 - 138 = 10

=> 2x + 3*10 = 46

=> 2x = 16

=> x = 8

Hope this helps!

:)

Mathematics
Step-by-step answer
P Answered by Specialist

x = -15/16

Step-by-step explanation:

see image.

Cross-multiply and combine like terms. Finally divide to get x all by itself.

see image.


Using the cross multiplication method, which of the following is the solution to 1/(x+1) = 17/(x+2)?
Mathematics
Step-by-step answer
P Answered by PhD

x = 3

y = -2

Step-by-step explanation:

x + 2y + 1 = 0

2x - 3y - 12 = 0

Multiply first equation by -2.

-2x + -4y + -2 = 0

2x - 3y - 12 = 0

Add equations.

0x + -7y - 14 = 0

Solve for y.

-7y = 14

y =-2

Put y as -2 in the first equation and solve for x.

x+2(-2)+1=0

x + -4 + 1 = 0

x = 0 + 4 - 1

x = 3

Mathematics
Step-by-step answer
P Answered by PhD

2x + 3y = 46

3x + 5y = 74

Multiply 1st equation by 3 and 2nd equation by 2:

6x + 9y = 138

6x + 10y = 148

Subtract 2nd equation to 1st equation:

=> y = 148 - 138 = 10

=> 2x + 3*10 = 46

=> 2x = 16

=> x = 8

Hope this helps!

:)

Mathematics
Step-by-step answer
P Answered by PhD

x=a²+ab+b²/a+b , y=-ab/a+b

Step-by-step explanation:

The system of the given equation may b written as:

ax+by-a²=0

bx+ay-b²=0

Here,

a1=a,b1=b,c1= -a²

a2=b,b2=a and c2= -b²

By cross multiplication we get

x/b*(-b²)-(-a²)*a = -y/a*(-b²)-(-a²)*b = 1/a*a-b*b

x/-b³+a³ = -y/-ab²+a²b  = 1/a²-b²

Now

x/-b³+a³ = 1/a²-b²

x=a³-b³/a²-b²

x=(a-b)(a²+ab+b²)/(a-b)(a+b)

x=a²+ab+b²/a+b

And,

-y/-ab²+a²b = 1/a²-b²

-y=a²b -ab²/a²-b²

y=ab²-a²b/a²-b²

y=ab(b-a)/(a-b)(a+b)

y= -ab(a-b)/(a-b)(a+b)

y= -ab/a+b

Hence x=a²+ab+b²/a+b , y=-ab/a+b

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