Jen invested $3500 into a continuously compounded account with an interest rate of 3.1%. After 9 years, how much money is in the account? Round your answer to the nearest whole number

≈$4607

Step-by-step explanation:

I will assume it's compounded yearly.

Apply the compound interest formula.

A = Total

P = Initial Principle

r = Interest Rate

n = number of interest in every t period

t = number of periods

In the case,

P = 3500

r = 3.1% = 0.031

n = 1

t = 9

Hence,

A ≈ 4607 (nearest whole number)

The total nom of  code that can be used is equal to 5+3 = 8

The solution is in the following image

The answer is in the image 

F=ma

where F=force

m=mass

a=acceleration

Here,

F=4300

a=3.3m/s2

m=F/a

    =4300/3.3

    =1303.03kg

Salesperson will make 6% of 1800

=(6/100)*1800

=108

Salesperson will make $108 in $1800 sales

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

The wood before starting =12 feet

Left wood=6 feet

Wood used till now=12-6=6 feet

Picture frame built till now= 6/(3/4)

=8 pieces

Therefore, till now 8 pieces have been made.

The answer is in the image