24.10.2020

Please someone work out x - 2/7 = 5

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09.07.2023, solved by verified expert
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Given equation: Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:211. Add 2/7 both sides.Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:212. Make the denominators equivalent.=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:213. Simplify the equation and find the value of x.=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21=> Please someone work out x - 2/7 = 5, №18010619, 24.10.2020 02:21
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Mathematics
Step-by-step answer
P Answered by Master
Solution:

We know that:

Given equation: x - \frac{2}{7}  = 51. Add 2/7 both sides.x - \frac{2}{7}  = 5=> x - \frac{2}{7}  + \frac{2}{7} = 5 + \frac{2}{7}=> x = 5 + \frac{2}{7}2. Make the denominators equivalent.=> x = 5 + \frac{2}{7}=> x = \frac{5 \times 7}{7} + \frac{2}{7}=> x = \frac{35}{7}  + \frac{2}{7}3. Simplify the equation and find the value of x.=> x = \frac{35}{7} + \frac{2}{7}=> \bold{x = \frac{37}{7}  = \frac{35}{7} + \frac{2}{7}  = 5 + \frac{2}{7}  = 5\frac{2}{7} }
Mathematics
Step-by-step answer
P Answered by PhD

x=37/5 ; x=51/5

Step-by-step explanation:

x -  2/5= 7

here,

x-2/5

LCM of denominators(1 &5)=5

5 (LCM of denominators) divided by the denominator of x(which is 1)= 5/1 =5

then,

5 multiply with numerator of x (which is x) = 5x

again,

5 (LCM of denominators) divided by the denominator of 2/5(which is 5) = 5/5=1

then,

1 multiply with numerator of 2/5 (which is 2)= 1 x 2 =2

so,

the fraction is,

(5x-2)/7

which is = 7

so,

(5x-2)=35           [multiplied by 5 on both site ]

5x=35+2             [add 2 on both site]

5x=37

x=37/5              [divided by 5 on both site]

similarly,

x + 4/5 = 11

=>(5x+4)/5=11

=>5x+4=55          [multiplied by 5 on both site ]  

=>5x=55-4           [subtraction by 4 on both site]

=>5x=51

=>x=51/5                [divided by 5 on both site]

Mathematics
Step-by-step answer
P Answered by PhD

x=37/5 ; x=51/5

Step-by-step explanation:

x -  2/5= 7

here,

x-2/5

LCM of denominators(1 &5)=5

5 (LCM of denominators) divided by the denominator of x(which is 1)= 5/1 =5

then,

5 multiply with numerator of x (which is x) = 5x

again,

5 (LCM of denominators) divided by the denominator of 2/5(which is 5) = 5/5=1

then,

1 multiply with numerator of 2/5 (which is 2)= 1 x 2 =2

so,

the fraction is,

(5x-2)/7

which is = 7

so,

(5x-2)=35           [multiplied by 5 on both site ]

5x=35+2             [add 2 on both site]

5x=37

x=37/5              [divided by 5 on both site]

similarly,

x + 4/5 = 11

=>(5x+4)/5=11

=>5x+4=55          [multiplied by 5 on both site ]  

=>5x=55-4           [subtraction by 4 on both site]

=>5x=51

=>x=51/5                [divided by 5 on both site]

Mathematics
Step-by-step answer
P Answered by Specialist
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6 quadratic trinomial 

Explanation:
Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: 3.1x^2 +6.0x + 0.3
Endler's guppies:   4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

-i
Mathematics
Step-by-step answer
P Answered by Specialist
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6 quadratic trinomial 

Explanation:
Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: 3.1x^2 +6.0x + 0.3
Endler's guppies:   4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

-i
Mathematics
Step-by-step answer
P Answered by PhD
1. 8 = 8 => refrexive

2. If x = y, then y = x => symmetric

3. If x = y and y = 7, then x = 7 => transitive

4. 6 + 2 = 2 + 6 => commutative - addition

5. 5 ∙ 2 = 2 ∙ 5 => commutative - multiplication

6. 10 + (3 + 2) = (10 + 3) + 2 => associative - addition

7. 6(3 ∙ 5) = (6 ∙ 3)5 => associative - multiplication

8. 4(8 + 1) = 4 ∙ 8 + 4 ∙ 1 => distributive

9. 6 + 0 = 6 => identity - addition

10. 8 ∙ 1 = 8 => identity - multiplication

11. 1/2 ∙ 2 = 1 => multiplicative inverse

12. 5 ∙ 0 = 0 => property of zero
Mathematics
Step-by-step answer
P Answered by PhD
1. 8 = 8 => refrexive

2. If x = y, then y = x => symmetric

3. If x = y and y = 7, then x = 7 => transitive

4. 6 + 2 = 2 + 6 => commutative - addition

5. 5 ∙ 2 = 2 ∙ 5 => commutative - multiplication

6. 10 + (3 + 2) = (10 + 3) + 2 => associative - addition

7. 6(3 ∙ 5) = (6 ∙ 3)5 => associative - multiplication

8. 4(8 + 1) = 4 ∙ 8 + 4 ∙ 1 => distributive

9. 6 + 0 = 6 => identity - addition

10. 8 ∙ 1 = 8 => identity - multiplication

11. 1/2 ∙ 2 = 1 => multiplicative inverse

12. 5 ∙ 0 = 0 => property of zero

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