Whats 1+1+1+1 divided by 3x2 + 5?, №18010735, 09.02.2021 00:10

Mathematics

Step-by-step answer

P Answered by Specialist

$\frac{26}{3}$

1 + 1 + 1 + $\frac{1}{3}$ x 2 + 5 (Write the division as a fraction)
1 + 1 + 1 + $\frac{2}{3}$ + 5 (Calculate)
8 + $\frac{2}{3}$ (Caculate Positive Numbers)
$\frac{26}{3}$
8 $\frac{2}{3}$ , 8.6 (Alternate Form)

Mathematics

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two. a) x 0 b) all real numbers c) x ≥ -3, x ≠ 2 d) x ≠ -8, x ≠ -3, x ≠ 2 2. identify intervals on which the function is increasing, decreasing, or constant. g(x) = 2 - (x - 7)2 (1 point) a) increasing: x 2; decreasing: x 2 b) increasing: x -7; decreasing: x -7 c) increasing: x 7; decreasing: x 7 d)increasing: x 2; decreasing: x 2 3. perform the requested operation or operations. f(x) = 4x + 7,

Step-by-step answer

P Answered by PhD

44

1) Find the domain of the given function. f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two.
using a graphical tool see the attachment
the answer is C) x ≥ -3, x ≠ 2
2. Identify intervals on which the function is increasing, decreasing, or constant.
g(x) = 2 - (x - 7)2
using a graphical tool
see the attachment
the answer is C) Increasing: x < 7; decreasing: x > 7
3. Perform the requested operation or operations.
f(x) = 4x + 7, g(x) = 3x2
Find (f + g)(x).
(f + g)(x) = f(x) + g(x)
(f + g)(x) = 4x + 7 + 3x^2
(f + g)(x) = 3x^2 + 4x + 7
The answer is C) 4x + 7 + 3x2
4. Perform the requested operation or operations.
f(x) = x minus five divided by eight. ; g(x) = 8x + 5, find g(f(x)).
f(x)=(x-5)/8 g(x)=8x+5
g(f(x))=8((x-5)/8)+5=x-5+5=x
the answer is B) g(f(x)) = x
5. Find f(x) and g(x) so that the function can be described as y = f(g(x)).y = nine divided by square root of quantity five x plus five.
y=f(g(x))=9/((5x+5) ^1/2)
let do
g(x)=5x+5...........so
f(x)= 9/( x^1/2)
the answer is A) f(x) = nine divided by square root of x. , g(x) = 5x + 5

6. A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle. As the camera zooms out, the length l and width w of the rectangle increase at a rate of 3 km/sec. How long does it take for the area A to be at least 4 times its original size?
Original size- >4km*4km=16 km2
4 times its original size---------------4*(16km2)-----64 Km2----------- > 8 km by 8 Km
Therefore
3km----------------------------- 1 sec
(8km-4km)---------------------x
X=4/3=1.33 sec
The answer is D) 1.33 sec

7. Find the inverse of the function.
f(x) = the cube root of quantity x divided by seven. - 9
to solve, replace f(x) with y , switch x and y, solve for y and replace y with f⁻¹(x)

f(x)=((x/7)-9) ^(1/3)
replace f(x) with y
y=((x/7)-9) ^(1/3)
switch x and y
x=((y/7)-9) ^(1/3)
solve for y
x^3=((y/7)-9)
x^3+9=y/7
y=7(x^3+9)
the answer is C) f-1(x) = 7(x3 + 9)

8. Describe how the graph of y= x2 can be transformed to the graph of the given equation.y = (x - 14)2 – 9

using a graphical tool see the attachment the answer is C) Shift the graph of y = x2 right 14 units and then down 9 units

9. Describe how to transform the graph of f into the graph of g. f(x) = alt='square root of quantity x minus nine.' and g(x) = alt='square root of quantity x plus five. '

f(x)=(x-9) ^1/2 g(x)=(x+5) ^1/2
using a graphical tool see the attachment

the answer is C) Shift the graph of f left 14 units

10. If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact.
f(x) = -16x5 - 7x4 – 6
The answer is B) Degree: 5; leading coefficient: -16

11. Write the quadratic function in vertex form.y = x2 + 4x + 7

Complete the square on the right side of the equation
Use the form ax2+bx+cax2+bx+c, to find the values of a, b, and c.
a=1,b=4,c=7
Consider the vertex form of a parabola.
a(x+d)2+e
Find the value of dd using the formula d=b/2a
d=4/(2*1)=2
Find the value of e using the formula e=c−b2/4a
e=7−4=3
Substitute the values of a, d, and e into the vertex form a(x+d)2+e
(x+2)2+3
The answer is A) y = (x + 2)2+ 3

12. Find the zeros of the function.
f(x) = 3x3 - 12x2 - 15x
using a graphical tool (see the attachment)x1=-1
x2=0
x3=5
The answer is C) 0, -1, and 5

13. Find a cubic function with the given zeros.7, -3, 2
X1=7
X2=-3
X3=2
f(x)=(x-7)(x+3)(x-2)=(x2-4x-21)(x-2)=x3-6x2-13x+42
the answer is C) f(x) = x3 - 6x2 - 13x + 42

14. Find the remainder when f(x) is divided by (x - k).f(x) = 7x4 + 12x3 + 6x2 - 5x + 16; k = 3
f(x)=7(3)4+12(3)3+6(3)2-5(3)+16=946
The answer is the B) 946

15. Use the Rational Zeros Theorem to write a list of all potential rational zerosf(x) = x3 - 10x2 + 4x - 24

The constant term of () is -24

The leading coefficient is 1.

We have to only consider the factors of the constant (leading coefficient = 1)

The factors are 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 24, -24

The answer is A) ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divi

Mathematics

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two. a) x 0 b) all real numbers c) x ≥ -3, x ≠ 2 d) x ≠ -8, x ≠ -3, x ≠ 2 2. identify intervals on which the function is increasing, decreasing, or constant. g(x) = 2 - (x - 7)2 (1 point) a) increasing: x 2; decreasing: x 2 b) increasing: x -7; decreasing: x -7 c) increasing: x 7; decreasing: x 7 d)increasing: x 2; decreasing: x 2 3. perform the requested operation or operations. f(x) = 4x + 7,

Step-by-step answer

P Answered by Master

ANSWER TO QUESTION 1

We have the function

$f(x)=\frac{\sqrt{x+3}} {(x+8)(x-2)}$ .

The domain of this function refers to all -values for which f(x) is defined.

This is a rational function that is undefined whenever the denominator is equal to zero. As a result of this we need to exclude the x-values that will make the function undefined.

We can find these values by equating the the denominator to zero.

$(x+8)(x-2)\ne 0$

$(x+8)\ne 0\:or\:(x-2)\ne 0$

$(x\ne -8\:or\:x\ne 2 0$

Also this rational function is undefined whenever the expression under the radical sign in the numerator is less than zero.

We must therefore restrict the expression under the square root sign in the numerator to be greater or equal to zero. Thus

$x+3\ge0$

$x\ge-3$

Because of this last restriction, $x\ne -8$ is eliminated from the restrictions.

Therefore the domain of $f(x)=\frac{\sqrt{x+3}} {(x+8)(x-2)}$ is

$x\ge-3$ , $x\ne 2$

The correct answer is C

ANSWER TO QUESTION 2

We have the function

g(x)=2-(x-7)^2

which is a maximum function written in the vertex form.

It is a maximum function because when we compare to the general vertex form,

g(x)=a(x-h)^2+k

a=-1

The vertex of the graph is V(7,2) .

The x-value of the vertex is

For , the graph is increasing and for $x\:7$ the graph will be decreasing.

The correct answer is C

ANSWER TO QUESTION 3

f(x)=4x+7

and

g(x)=3x^2

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x+7+3x^2

The correct answer is C

ANSWER TO QUESTION 4

We have

$f(x)=\frac{x-5}{8}$

g(x)=8x+5

The composition of the two functions

g(f(x))

is given by;

$g(f(x))=g(\frac{x-5}{8})$

This implies that;

$g(f(x))=8\times (\frac{x-5}{8})+5$

g(f(x))=x-5+5

g(f(x))=x

The correct answer is B.

ANSWER TO QUESTION 5.

Given

$f(g(x))=\frac{9}{\sqrt{5x+5}}$ .

Then

$f(x)=\frac{9}{\sqrt{x} }$ and g(x)=5x+5

So that;

f(g(x))=f(5x+5)

Which will give;

$f(g(x))=\frac{9}{\sqrt{5x+5}}$ .

The correct answer is A

ANSWER TO QUESTION 6

The dimension of the smallest region are

l=4 km

and

w=4km

If the length and width are increasing at the rate of 3km\sec, then after seconds, the dimensions will be,

l=4+3x km

and

w=4+3x km

This means the area after seconds is given by;

(4+3x)(4+3x) .

If the area is at least 4 times its original size, then we can write the inequality;

$(4+3x)(4+3x)\ge 4(4\times 4)$ .

$(4+3x)(4+3x)\ge 64$

We expand to obtain;

9x^2+24x+16ge 64

We simplify to obtain,

9x^2+24x-48ge 0

We split factor to get;

(x+4)(3x-4)ge 0

This implies that;

$x\le -4$

or

$x\ge \frac{4}{3}$

Since we are dealing with time, we discard the negative value. Hence it will take

$x= \frac{4}{3} \approx 1.33sec$

The correct answer is D.

ANSWER TO QUESTION 8

The correct answer is C.

This is how the following transformations affect the graph of

y=x^2

y=a(x+b)^2+c

If , the graph opens down.

If $a\:0$ , the graph opens up.

If , the graph graph shifts to the right b units.

If $b\:0$ , the graph graph shifts to the left b units.

If , the graph graph shifts down c units.

If $c\:0$ ,the graph graph shifts up c units.

Therefore for y=(x-14)^2-9 , the graph of y=x^2 moves to the right 14 units and moves down 9 units.

ANSWER TO QUESTION 9

The graph of

$f(x)=\sqrt{x-9}$ has y-intercept which is

and

$f(x)=\sqrt{x+5}$ has x-intercept which is

In order to transform the graph of in to , we need to shift the x-intercept of the graph of f 14 units to the left.

The correct answer is C

ANSWER TO QUESTION 10

The function;

f(x)=-16x^5-7x^4-6 .

This is a polynomial with a degree of 5 and the leading coefficient is .

The correct answer is C

ANSWER TO QUESTION 11

We have

y=x^2+4x+7

We add and subtract half the coefficient of .

y=x^2+4x+(2)^2 -(2)^2+7

The first three term is a perfect square.

y=(x+2)^2 -4+7

y=(x+2)^2 +3

The correct answer is A.

ANSWER TO QUESTION 12

We want to solve;

f(x)=3x^3-12x^2-15x

To find the zeros of this function, we equate it to zero.

3x^3-12x^2-15x=0

We factor to obtain;

3x(x^2-4x-5)=0

We now split the middle term of the quadratic factor to get,

3x(x^2-5x+x-5)=0

3x(x(x-5)+1(x-5)=0

3x(x-5)(x+1)=0

3x=0,(x-5)=0,(x+1)=0

x=0,x=5,x=-1

The correct answer is C.

See Attachment for the rest of the solutions

Mathematics

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two. a) x 0 b) all real numbers c) x ≥ -3, x ≠ 2 d) x ≠ -8, x ≠ -3, x ≠ 2 2. identify intervals on which the function is increasing, decreasing, or constant. g(x) = 2 - (x - 7)2 (1 point) a) increasing: x 2; decreasing: x 2 b) increasing: x -7; decreasing: x -7 c) increasing: x 7; decreasing: x 7 d)increasing: x 2; decreasing: x 2 3. perform the requested operation or operations. f(x) = 4x + 7,

Step-by-step answer

P Answered by PhD

45

1) Find the domain of the given function.
f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two.

using a graphical tool see the attachment

the answer is C) x ≥ -3, x ≠ 2

2. Identify intervals on which the function is increasing, decreasing, or constant.

g(x) = 2 - (x - 7)2

using a graphical tool

see the attachment

the answer is C) Increasing: x < 7; decreasing: x > 7

3. Perform the requested operation or operations.

f(x) = 4x + 7, g(x) = 3x2

Find (f + g)(x).

(f + g)(x) = f(x) + g(x)

(f + g)(x) = 4x + 7 + 3x^2

(f + g)(x) = 3x^2 + 4x + 7

The answer is C) 4x + 7 + 3x2

4. Perform the requested operation or operations.

f(x) = x minus five divided by eight. ; g(x) = 8x + 5, find g(f(x)).

f(x)=(x-5)/8 g(x)=8x+5

g(f(x))=8((x-5)/8)+5=x-5+5=x

the answer is B) g(f(x)) = x

5. Find f(x) and g(x) so that the function can be described as y = f(g(x)).
y = nine divided by square root of quantity five x plus five.

y=f(g(x))=9/((5x+5) ^1/2)

let do

g(x)=5x+5...........so

f(x)= 9/( x^1/2)

the answer is A) f(x) = nine divided by square root of x. , g(x) = 5x + 5

6. A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle. As the camera zooms out, the length l and width w of the rectangle increase at a rate of 3 km/sec. How long does it take for the area A to be at least 4 times its original size?

Original size- >4km*4km=16 km2

4 times its original size---------------4*(16km2)-----64 Km2----------- > 8 km by 8 Km

Therefore

3km----------------------------- 1 sec

(8km-4km)---------------------x

X=4/3=1.33 sec

The answer is D) 1.33 sec

7. Find the inverse of the function.

f(x) = the cube root of quantity x divided by seven. - 9

to solve
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

f(x)=((x/7)-9) ^(1/3)

replace f(x) with y

y=((x/7)-9) ^(1/3)

switch x and y

x=((y/7)-9) ^(1/3)

solve for y

x^3=((y/7)-9)

x^3+9=y/7

y=7(x^3+9)

the answer is C) f-1(x) = 7(x3 + 9)

8. Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x - 14)2 – 9

using a graphical tool see the attachment the answer is C) Shift the graph of y = x2 right 14 units and then down 9 units

9. Describe how to transform the graph of f into the graph of g.
f(x) = alt='square root of quantity x minus nine.' and g(x) = alt='square root of quantity x plus five. '

f(x)=(x-9) ^1/2 g(x)=(x+5) ^1/2

using a graphical tool see the attachment
the answer is C) Shift the graph of f left 14 units

10. If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact.

f(x) = -16x5 - 7x4 – 6

The answer is B) Degree: 5; leading coefficient: -16

11. Write the quadratic function in vertex form.
y = x2 + 4x + 7

Complete the square on the right side of the equation

Use the form ax2+bx+cax2+bx+c, to find the values of a, b, and c.

a=1,b=4,c=7

Consider the vertex form of a parabola.

a(x+d)2+e

Find the value of dd using the formula d=b/2a

d=4/(2*1)=2

Find the value of e using the formula e=c−b2/4a

e=7−4=3

Substitute the values of a, d, and e into the vertex form a(x+d)2+e

(x+2)2+3

The answer is A) y = (x + 2)2+ 3

12. Find the zeros of the function.

f(x) = 3x3 - 12x2 - 15x

using a graphical tool (see the attachment)

x1=-1

x2=0

x3=5

The answer is C) 0, -1, and 5

13. Find a cubic function with the given zeros.
7, -3, 2

X1=7

X2=-3

X3=2

f(x)=(x-7)(x+3)(x-2)=(x2-4x-21)(x-2)=x3-6x2-13x+42

the answer is C) f(x) = x3 - 6x2 - 13x + 42

14. Find the remainder when f(x) is divided by (x - k).
f(x) = 7x4 + 12x3 + 6x2 - 5x + 16; k = 3

f(x)=7(3)4+12(3)3+6(3)2-5(3)+16=946

The answer is the B) 946

15. Use the Rational Zeros Theorem to write a list of all potential rational zeros.
f(x) = x3 - 10x2 + 4x - 24

The constant term of

Mathematics

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two. a) x 0 b) all real numbers c) x ≥ -3, x ≠ 2 d) x ≠ -8, x ≠ -3, x ≠ 2 2. identify intervals on which the function is increasing, decreasing, or constant. g(x) = 2 - (x - 7)2 (1 point) a) increasing: x 2; decreasing: x 2 b) increasing: x -7; decreasing: x -7 c) increasing: x 7; decreasing: x 7 d)increasing: x 2; decreasing: x 2 3. perform the requested operation or operations. f(x) = 4x + 7,

Step-by-step answer

P Answered by PhD

44

1) Find the domain of the given function. f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two.
using a graphical tool see the attachment
the answer is C) x ≥ -3, x ≠ 2
2. Identify intervals on which the function is increasing, decreasing, or constant.
g(x) = 2 - (x - 7)2
using a graphical tool
see the attachment
the answer is C) Increasing: x < 7; decreasing: x > 7
3. Perform the requested operation or operations.
f(x) = 4x + 7, g(x) = 3x2
Find (f + g)(x).
(f + g)(x) = f(x) + g(x)
(f + g)(x) = 4x + 7 + 3x^2
(f + g)(x) = 3x^2 + 4x + 7
The answer is C) 4x + 7 + 3x2
4. Perform the requested operation or operations.
f(x) = x minus five divided by eight. ; g(x) = 8x + 5, find g(f(x)).
f(x)=(x-5)/8 g(x)=8x+5
g(f(x))=8((x-5)/8)+5=x-5+5=x
the answer is B) g(f(x)) = x
5. Find f(x) and g(x) so that the function can be described as y = f(g(x)).y = nine divided by square root of quantity five x plus five.
y=f(g(x))=9/((5x+5) ^1/2)
let do
g(x)=5x+5...........so
f(x)= 9/( x^1/2)
the answer is A) f(x) = nine divided by square root of x. , g(x) = 5x + 5

6. A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle. As the camera zooms out, the length l and width w of the rectangle increase at a rate of 3 km/sec. How long does it take for the area A to be at least 4 times its original size?
Original size- >4km*4km=16 km2
4 times its original size---------------4*(16km2)-----64 Km2----------- > 8 km by 8 Km
Therefore
3km----------------------------- 1 sec
(8km-4km)---------------------x
X=4/3=1.33 sec
The answer is D) 1.33 sec

7. Find the inverse of the function.
f(x) = the cube root of quantity x divided by seven. - 9
to solve, replace f(x) with y , switch x and y, solve for y and replace y with f⁻¹(x)

f(x)=((x/7)-9) ^(1/3)
replace f(x) with y
y=((x/7)-9) ^(1/3)
switch x and y
x=((y/7)-9) ^(1/3)
solve for y
x^3=((y/7)-9)
x^3+9=y/7
y=7(x^3+9)
the answer is C) f-1(x) = 7(x3 + 9)

8. Describe how the graph of y= x2 can be transformed to the graph of the given equation.y = (x - 14)2 – 9

using a graphical tool see the attachment the answer is C) Shift the graph of y = x2 right 14 units and then down 9 units

9. Describe how to transform the graph of f into the graph of g. f(x) = alt='square root of quantity x minus nine.' and g(x) = alt='square root of quantity x plus five. '

f(x)=(x-9) ^1/2 g(x)=(x+5) ^1/2
using a graphical tool see the attachment

the answer is C) Shift the graph of f left 14 units

10. If the following is a polynomial function, then state its degree and leading coefficient. If it is not, then state this fact.
f(x) = -16x5 - 7x4 – 6
The answer is B) Degree: 5; leading coefficient: -16

11. Write the quadratic function in vertex form.y = x2 + 4x + 7

Complete the square on the right side of the equation
Use the form ax2+bx+cax2+bx+c, to find the values of a, b, and c.
a=1,b=4,c=7
Consider the vertex form of a parabola.
a(x+d)2+e
Find the value of dd using the formula d=b/2a
d=4/(2*1)=2
Find the value of e using the formula e=c−b2/4a
e=7−4=3
Substitute the values of a, d, and e into the vertex form a(x+d)2+e
(x+2)2+3
The answer is A) y = (x + 2)2+ 3

12. Find the zeros of the function.
f(x) = 3x3 - 12x2 - 15x
using a graphical tool (see the attachment)x1=-1
x2=0
x3=5
The answer is C) 0, -1, and 5

13. Find a cubic function with the given zeros.7, -3, 2
X1=7
X2=-3
X3=2
f(x)=(x-7)(x+3)(x-2)=(x2-4x-21)(x-2)=x3-6x2-13x+42
the answer is C) f(x) = x3 - 6x2 - 13x + 42

14. Find the remainder when f(x) is divided by (x - k).f(x) = 7x4 + 12x3 + 6x2 - 5x + 16; k = 3
f(x)=7(3)4+12(3)3+6(3)2-5(3)+16=946
The answer is the B) 946

15. Use the Rational Zeros Theorem to write a list of all potential rational zerosf(x) = x3 - 10x2 + 4x - 24

The constant term of () is -24

The leading coefficient is 1.

We have to only consider the factors of the constant (leading coefficient = 1)

The factors are 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 12, -12, 24, -24

The answer is A) ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24

1. find the domain of the given function. (1 point) f(x) = square root of quantity x plus three divi

Mathematics

Question 13(multiple choice worth 5 points)use the rational zeros theorem to write a list of all potential rational zeros. f(x) = x3 - 7x2 + 9x - 24 ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 ±1, ±2, ±3, ±4, ±24 ±1, ±one divided by two, ±2, ±3, ±4, ±6, ±8, ±12, ±24 ±1, ±2, ±3, ±4, ±6, ±12, ±24question 14(multiple choice worth 5 points)perform the requested operation or operations. f(x) = 7x + 6, g(x) = 4x2 find (f + g)(x). 7x + 6 + 4x2 28x3 + 24x 7x + 6 - 4x2 seven x plus six divided by four x squared.question 15(multiple choice worth 5 points)find a cubic

Step-by-step answer

P Answered by Master

1

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24

Q14 - A. $7x+6+4x^{2}$

Q15 - D. $f(x)=x^{3}-3x^{2}-28x+60$

Q16 - D. 20.9 ft

Q17 - A. x ≥ -9, x ≠ -3, x ≠ 7

Q18 - B. 2π

Step-by-step explanation:

Question 13:

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if $\frac{p}{q}$ is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, $\frac{p}{q}$ is a zero of x^3-7x^2+9x-24=0 . Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of $\frac{p}{q}$ are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = $4x^{2}$

Then, (f+g)(x) = f(x) + g(x) = 7x + 6 + $4x^{2}$

So, (f+g)(x) = $7x+6+4x^{2}$

Question 15:

Zeros of the function are given by 6, -5, 2.

Thus, the factored form will be (x-6)(x+5)(x-2)=0

i.e. $(x^{2}+5x-6x-30)(x-2)=0$

i.e. $(x^{2}-x-30)(x-2)=0$

i.e. $(x^{3}-2x^{2}-x^{2}+2x-30x+60=0$

i.e. $x^{3}-3x^{2}-28x+60=0$

So, the cubic function is $f(x)=x^{3}-3x^{2}-28x+60$ .

Question 16:

Let, the length of the ramp = x feet.

The horizontal length of the ramp = 20 feet

The vertical length of the ramp = 6 feet.

Using Pythagoras Theorem, we have,

$x^{2}=20^{2}+6^{2}$

i.e. $x^{2}=400+36$

i.e. $x^{2}=436$

i.e. $x=\pm 20.9$

Since, the length of the ramp cannot be negative.

Hence, the length of the ramp is 20.9 feet.

Question 17:

We have the function, $f(x)=\frac{\sqrt{x+9}}{(x+3)(x-7)}$

As the quantities in square roots are always positive, then x+9≥0 i.e. x≥-9.

Also, the function is not defined at x = -3 and x = 7.

Thus, the domain is x ≥ -9 and x ≠ -3, x ≠ 7.

Question 18:

We have the function y = -3 cosx

As, there will be no affect on the period by the quantity -3 and the period of the cosine function is 2π.

Thus, period of y = -3 cosx is 2π.

Mathematics

Question 13(multiple choice worth 5 points)use the rational zeros theorem to write a list of all potential rational zeros. f(x) = x3 - 7x2 + 9x - 24 ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 ±1, ±2, ±3, ±4, ±24 ±1, ±one divided by two, ±2, ±3, ±4, ±6, ±8, ±12, ±24 ±1, ±2, ±3, ±4, ±6, ±12, ±24question 14(multiple choice worth 5 points)perform the requested operation or operations. f(x) = 7x + 6, g(x) = 4x2 find (f + g)(x). 7x + 6 + 4x2 28x3 + 24x 7x + 6 - 4x2 seven x plus six divided by four x squared.question 15(multiple choice worth 5 points)find a cubic

Step-by-step answer

P Answered by Master

1

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24

Q14 - A. $7x+6+4x^{2}$

Q15 - D. $f(x)=x^{3}-3x^{2}-28x+60$

Q16 - D. 20.9 ft

Q17 - A. x ≥ -9, x ≠ -3, x ≠ 7

Q18 - B. 2π

Step-by-step explanation:

Question 13:

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if $\frac{p}{q}$ is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, $\frac{p}{q}$ is a zero of x^3-7x^2+9x-24=0 . Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of $\frac{p}{q}$ are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = $4x^{2}$

Then, (f+g)(x) = f(x) + g(x) = 7x + 6 + $4x^{2}$

So, (f+g)(x) = $7x+6+4x^{2}$

Question 15:

Zeros of the function are given by 6, -5, 2.

Thus, the factored form will be (x-6)(x+5)(x-2)=0

i.e. $(x^{2}+5x-6x-30)(x-2)=0$

i.e. $(x^{2}-x-30)(x-2)=0$

i.e. $(x^{3}-2x^{2}-x^{2}+2x-30x+60=0$

i.e. $x^{3}-3x^{2}-28x+60=0$

So, the cubic function is $f(x)=x^{3}-3x^{2}-28x+60$ .

Question 16:

Let, the length of the ramp = x feet.

The horizontal length of the ramp = 20 feet

The vertical length of the ramp = 6 feet.

Using Pythagoras Theorem, we have,

$x^{2}=20^{2}+6^{2}$

i.e. $x^{2}=400+36$

i.e. $x^{2}=436$

i.e. $x=\pm 20.9$

Since, the length of the ramp cannot be negative.

Hence, the length of the ramp is 20.9 feet.

Question 17:

We have the function, $f(x)=\frac{\sqrt{x+9}}{(x+3)(x-7)}$

As the quantities in square roots are always positive, then x+9≥0 i.e. x≥-9.

Also, the function is not defined at x = -3 and x = 7.

Thus, the domain is x ≥ -9 and x ≠ -3, x ≠ 7.

Question 18:

We have the function y = -3 cosx

As, there will be no affect on the period by the quantity -3 and the period of the cosine function is 2π.

Thus, period of y = -3 cosx is 2π.

Mathematics

8.08, part 1 1. find the vertex, focus, directrix, and focal width of the parabola. negative 1 divided by 16 times x squared = y a) vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 16 b) vertex: (0, 0); focus: (-8, 0); directrix: x = 4; focal width: 64 c) vertex: (0, 0); focus: (0, 4); directrix: y = -4; focal width: 4 d) vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 64 2. find the standard form of the equation of the parabola with a focus at (0, -8) and a directrix at y = 8. a) y = negative 1 divided by 32 x2 b)

Step-by-step answer

P Answered by Master

Hello,
Please, see the detailed solutions in the attached files.
Thanks.

8.08, part 1 1. find the vertex, focus, directrix, and focal width of the parabola. negative 1 divi

Mathematics

8.08, part 1 1. find the vertex, focus, directrix, and focal width of the parabola. negative 1 divided by 16 times x squared = y a) vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 16 b) vertex: (0, 0); focus: (-8, 0); directrix: x = 4; focal width: 64 c) vertex: (0, 0); focus: (0, 4); directrix: y = -4; focal width: 4 d) vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 64 2. find the standard form of the equation of the parabola with a focus at (0, -8) and a directrix at y = 8. a) y = negative 1 divided by 32 x2 b)

Step-by-step answer

P Answered by Specialist

Hello,
Please, see the detailed solutions in the attached files.
Thanks.

Mathematics

5. divide 1) x4-3x2+4x+5 by x2+1-x 2) x3-3x2+5x-3 by x2-2

Step-by-step answer

P Answered by PhD

1) Quotient = x^2+x-3 .

Reminder= 8.

2) Quotient = x-3.

Reminder = 7x-9.

Step-by-step explanation:

The Polynomial division is same as the regular division using long division method.

The quotient and reminder can be either polynomial or number.

1) For $\frac{x^4-3x^2+4x+5}{x^2-x+1}$ , the quotient is x^2+x-3 and the reminder is 8.

2) For $\frac{x^3-3x^2+5x-3}{x^2-2}$ , the quotient is x-3 and the reminder is 7x-9.

( The steps are uploaded in the image).

5. divide1) x4-3x2+4x+5 by x2+1-x 2) x3-3x2+5x-3 by x2-2

Whats 1+1+1+1 divided by 3x2 + 5?

Step-by-step answer

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