Given:
The vertices of a parallelogram are A (-2,3), B (3,3), C (4,6), and D(-1,6).
It is first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D.
To find:
The distance between C' and D'.
Solution:
If a figure rotated 90 degrees clockwise, then
If figure translated 4 units left and 2 units down, then
Distance formula:
Distance between C'(2,-6) and D'(2,-1) is
Therefore, the distance between C'D' is 5 units.