Physics : asked on sahrsalim70
 20.01.2021


I am supposed to fill out the below chart

Please check if with me.

. 1

Faq

Mathematics
Step-by-step answer
P Answered by Master
Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40 

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104

Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 po
Mathematics
Step-by-step answer
P Answered by Specialist

Part 1

Given equation:

C(t) = -0.30 (t – 12)² + 40  

For t = 0

C(t) = -0.30 (0 - 12)² + 40 C(t) = -0.30 (-12)² + 40 C(t) = -3.2

For t = 12 (noon)

C(t) = -0.30 (12 - 12)² + 40 C(t) = -0.30 (0)² + 40 C(t) = 40

For t = 24 (midnight)

C(t) = -0.30 (24 - 12)² + 40 C(t) = -0.30 (12)² + 40 C(t) = -0.30 × 144 + 40 C(t) = - 43.2 + 40 C(t) = -3.2

Part 2

attached below

Part 3

C(t) = –0.30(t – 12)² + 40 F(t)=9/5C(t)+32

Substituting the values:

F(t)=9/5{–0.30 (t – 12)² + 40}+32 F(t) = -0.54 (t – 12)² + 72 + 32 F(t) = -0.54 (t – 12)² + 104

5, 6 and 7, should be simplish

good luck, i hope this helps :)


Plz help will give wut i got (as in points)

Temperature in the desert can be modeled by the functi
Mathematics
Step-by-step answer
P Answered by Specialist
Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40 

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104

Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 po
Mathematics
Step-by-step answer
P Answered by Specialist
Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40 

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104

Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 po
Mathematics
Step-by-step answer
P Answered by Specialist
Part.1
Given equation:
C(t) = -0.30 (t – 12)² + 40 

For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2

For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40

For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2

Part.2
Graph of the equation is given in the attachment.

Part.3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32

Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104

Fill out the following chart to find the temperatures for t = 12 (noon) and t = 24 (midnight). (2 po
Physics
Step-by-step answer
P Answered by PhD

Answer:

9.6 meters

Step-by-step explanation:

Time taken by the tomatoes to each the ground

using h = 1/2 g t^2 

t^2 = 2h/g = 2 x 50/ 9.8 = 10.2

t = 3.2 sec 

horizontal ditance = speed x time = 3 x 3.2 = 9.6 meters

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