Physics : asked on bigworm60
 23.07.2020

The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of the cart are 13.2 ft/s at point A and 17.4 ft/s at point C. The cart takes 3.00 s to go from point A to point C, and the cart takes 1.20 s to go from point B to point C. What is the cart's speed at point B

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24.06.2023, solved by verified expert
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the cart's speed at point B is 15.72 ft/s

Explanation:

 Given the data in the question;

The car travels from point A to C in 3.00 s, its average acceleration The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 will be;

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  = [The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  - The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49] / Δt

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 is 17.4 ft/s,   The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 is 13.2 ft/s and Δt is 3.00 s

so we substitute

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  = [17.4 - 13.2] / 3

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  = 4.2 / 3

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  =  1.4 ft/s²

so average acceleration of the cart between the points  A and B is 1.4 ft/s²

The instantaneous value of the velocity of the cart at point B will be;

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  = Δv / Δt

now substitute [The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  - The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49] for Δv and t' for Δt

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  = [The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  - The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49] / t'

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 = The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 - The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49( t' )

so we substitute 17.4 ft/s for The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49, 1.20 s for t' and  The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49  =  1.4 ft/s²

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 = 17.4 - (1.4 × 1.20)

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 = 17.4 - 1.68

The cart travels the track again and now experiences, №17886785, 23.07.2020 03:49 = 15.72 ft/s

Therefore, the cart's speed at point B is 15.72 ft/s

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Physics
Step-by-step answer
P Answered by PhD

the cart's speed at point B is 15.72 ft/s

Explanation:

 Given the data in the question;

The car travels from point A to C in 3.00 s, its average acceleration a_{avg} will be;

a_{avg}  = [V_{c}  - V_{A}] / Δt

V_{c} is 17.4 ft/s,   V_{A} is 13.2 ft/s and Δt is 3.00 s

so we substitute

a_{avg}  = [17.4 - 13.2] / 3

a_{avg}  = 4.2 / 3

a_{avg}  =  1.4 ft/s²

so average acceleration of the cart between the points  A and B is 1.4 ft/s²

The instantaneous value of the velocity of the cart at point B will be;

a_{avg}  = Δv / Δt

now substitute [V_{c}  - V_{B}] for Δv and t' for Δt

a_{avg}  = [V_{c}  - V_{B}] / t'

V_{B} = V_{c} - a_{avg}( t' )

so we substitute 17.4 ft/s for V_{c}, 1.20 s for t' and  a_{avg}  =  1.4 ft/s²

V_{B} = 17.4 - (1.4 × 1.20)

V_{B} = 17.4 - 1.68

V_{B} = 15.72 ft/s

Therefore, the cart's speed at point B is 15.72 ft/s

Physics
Step-by-step answer
P Answered by Specialist
Options:
a. a lower frequency and a shorter wavelength.
b. a higher frequency and a longer wavelength.
c. a lower frequency and a longer wavelength.
d. a higher frequency and a shorter wavelength

Answer:
d. a higher frequency and a shorter wavelength

Explanation:
The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths.
For example, Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies. Radio waves, on the other hand, have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation.
Options:
a. a lower frequency and a shorter wavelength.
b. a higher frequency and a longer wavelen
Physics
Step-by-step answer
P Answered by Specialist
Answer: Option B and C are True.

Explanation:
The weight of the two blocks acts downwards.
Let the weight of the two blocks be W. Solving for T₁ and T₂:
w = T₁/cos 60° -----(1);
w = T₂/cos 30° ----(2);
equating (1) and (2)
T₁/cos 60° = T₂/cos 30°;
T₁ cos 30° = T₂ cos 60°;
T₂/T₁ = cos 30°/cos 60°;
T₂/T₁ =1.73.
Therefore, option a is false since T₂ > T₁.
Option B is true since T₁ cos 30° = T₂ cos 60°.
Option C is true because the T₃ is due to the weight of the two blocks while T₄ is only due to one block.
Option D is wrong because T₁ + T₂ > T₃ by simple summation of the two forces, except by vector addition.
Answer: Option B and C are True.

Explanation:  
The weight of the two blocks acts downwards.
Le
Physics
Step-by-step answer
P Answered by PhD

The question specifies the diameter of the screw, therefore the IMA of this screw is 0.812? / 0.318 = 8.02

Physics
Step-by-step answer
P Answered by PhD
Answer:
7.25 secs.

Explanation:
First find the distance it takes to stop
s = [v^2-u^2]/2a = 0^2 - 8.7^2/2[-2.4] = 8.7^2/4.8
Next find the time it takes to go that distance , s = ut +[1/2] at^2
8.7^2/4.8 = 8.7t +[1/2] [ -2.4]t^2 , rearrange and
t^2 -[8.7/1.2]+ 8.7^2/[(1.2)(4.8)]=0 complete the square
[t - (8.7/2.4)]^2=0
t = 8.7/2.4 = 3.625 secs
At this stage the deceleration will push the object back in the direction it came from for another 3.625 secs when it will be 8.7 m/s again
Total time , T =2t = 7.25 secs.

Note:
The term differential is used in calculus to refer to an infinitesimal (infinitely small) change in some varying quantity. For example, if x is a variable, then a change in the value of x is often denoted Δx (pronounced delta x). The differential dx represents an infinitely small change in the variable x.
Physics
Step-by-step answer
P Answered by PhD
First sum applied the Newton's second law motion: F = ma
Force = mass* acceleration
This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time,
force=(mass*velocity)/time
such that, (mass*velocity)/time=momentum/time
Therefore we get mass*velocity=momentum
Momentum=mass*velocity
Elephant mass=6300 kg; velocity=0.11 m/s
Momentum=6300*0.11
P=693 kg (m/s)
Dolphin mass=50 kg; velocity=10.4 m/s
Momentum=50*10.4
P=520 kg (m/s)
The elephant has more momentum(P) because it is large.
Physics
Step-by-step answer
P Answered by PhD
The change in temperature is 9.52°CExplanation:Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.Thus, from the law of conservation of energy can be stated as:Heat Supplied by Electric Kettle = Heat Absorbed by WaterHeat Supplied by Electric Kettle = m C ΔTwhere,Heat Supplied by Electric Kettle = 20,000 JMass of water = m = 0.5 kgSpecific Heat Capacity of Water = C = 4200 J/kg.°CChange in Temperature of Water = ΔTTherefore,20,000 J = (0.5 kg)(4200 J/kg.°C) ΔTΔT = 20,000 J/(2100 J/°C)ΔT = 9.52°C

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