When Quinn got home, he turned the air conditioner on.
TTT represents the temperature in Quinn's home (in degrees Celsius) after ttt minutes.
T=42-0.7tT=42−0.7tT, equals, 42, minus, 0, point, 7, t
How fast did the temperature drop?

The answer is in the image 

Answer is 0.7 degrees celcius per minute

Explanation:

given that T(t) = 42-0.7t

We have to find the rate of drop of temperature.

For that we find drop of T in 1 minute

Consider T(t) for t minutes and t+1 minutes

T(t+1) = 42-0.7(t+1)

T(t) = 42-0.7t

Difference i.e. drop in temperature in one minute

= T(t+1)-T(t)

= 42-0.7(t+1)-(42-0.7t)   =-0.7

Hence drop per minute = 0.7 degree celcius.

We are given

where

T models the temperature in Quinn's home (in degrees Celsius) after t minutes

t is time in minutes

Since, we have to find rate of change of temperature

so, we will find derivative

So, the temperature drops at a rate 0.7 degrees Celsius per minutes.........Answer

We are given

where

T models the temperature in Quinn's home (in degrees Celsius) after t minutes

t is time in minutes

Since, we have to find rate of change of temperature

so, we will find derivative

So, the temperature drops at a rate 0.7 degrees Celsius per minutes.........Answer

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