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02.06.2020

An object with a mass of 4.0 kg has a force of 12.0 newtons applied to it. What is the resultant acceleration of the object? Help me?? :(

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24.06.2023, solved by verified expert

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3m/s²

Explanation:

Force applied to an object can be calculated thus;

F = ma

Where;

F = force applied (Newtons)

m = mass of substance (kg)

a = acceleration (m/s²)

According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?

Derived from F = m.a

We have; a = F/m

a = 12/4

a = 3

The resultant acceleration of the object is 3m/s².

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Chemistry

An object with a mass of 4.0 kg has a force of 12.0 newtons applied to it. What is the resultant acceleration of the object? Help me?? :(

Step-by-step answer

P Answered by PhD

3m/s²

Explanation:

Force applied to an object can be calculated thus;

F = ma

Where;

F = force applied (Newtons)

m = mass of substance (kg)

a = acceleration (m/s²)

According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?

Derived from F = m.a

We have; a = F/m

a = 12/4

a = 3

The resultant acceleration of the object is 3m/s².

Physics

Activity 3. Let s Do The Mathi Direction: Use Newton s second law equation to solve for force, mass, and acceleration Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration? Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface with a force of 50N? Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the resulting acceleration of the object? Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is applied

Step-by-step answer

P Answered by PhD

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3. $\overline 3$ m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object, = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3. $\overline 3$ m/s²

The acceleration = 3. $\overline 3$ m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object, = 0.5 kg.

Physics

Step-by-step answer

P Answered by PhD

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3. $\overline 3$ m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object, = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3. $\overline 3$ m/s²

The acceleration = 3. $\overline 3$ m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object, = 0.5 kg.

Chemistry

Fiona claims that the diagram below shows simple machines, but Chad claims that it shows a compound machine. A man pushes a shopping cart up a ramp. Which statement best explains who is correct? Fiona is correct because less than three machines are shown in the diagram. Fiona is correct because the diagram shows two individual simple machines. Chad is correct because more than one machine is shown in the diagram. Chad is correct because the diagram shows two simple machines doing a job.

Step-by-step answer

P Answered by Specialist

Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation:
A mechanical device using which we can change the direction or magnitude of force applied is known as simple machine.
For example, in the given diagram there are two individual simple machines.
The machine helps in changing the direction or magnitude of force applied by the man. As a result, it becomes easy for him to carry different things easily from one place to another.
Thus, we can conclude that the statement Fiona is correct because the diagram shows two individual simple machines, is correct.
Answer: b. Fiona is correct because the diagram shows two individual simple machines.

Explanation

Chemistry

Which of the following will have a lower ionization energy than scandium

Step-by-step answer

P Answered by Master

Calcium (Ca)(On the periodic table, ionization energy increases as you go up and to the right of the periodic table)

Chemistry

Give an example of a protein structure that would give positive test with Molisch’s Reagent

Step-by-step answer

P Answered by PhD

glycoproteins

Explanation:

A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).

Chemistry

what is the volume of a container that contains 24.0 grams of N2 gas st 328K and .884 atm?

Step-by-step answer

P Answered by PhD

Answer:

Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

Explanation:

In this case, you know:

P= 0.884 atm

V= ?

n= Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N 0.857 moles (where 28 g/mole is the molar mass of N₂, that is, the amount of mass that the substance contains in one mole.)

R=0.082 Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

T= 328 K

Replacing in the ideal gas law:

0.884 atm×V= 0.857 moles× 0.082 Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N ×328 K

Solving:

Answer:Taking into accoun the ideal gas law, The volume of a container that contains 24.0 grams of N

V= 26.07 L

The volume of a container that contains 24.0 grams of N2 gas at 328K and 0.884 atm is 26.07 L.

Chemistry

The reaction of 15 moles carbon with 30 moles O2. Will result in a theoretical yield of_ moles CO2.

Step-by-step answer

P Answered by PhD

15 moles.Explanation:Hello,In this case, the undergoing chemical reaction is:Clearly, since carbon and oxygen are in a 1:1 molar ratio, 15 moles of carbon will completely react with 15 moles of oxygen, therefore 15 moles of oxygen remain as leftovers. In such a way, since carbon and carbon dioxide are also in a 1:1 molar ratio, the theoretical yield of carbon dioxide is 15 moles based on the stoichiometry:Best regards.

Chemistry

The half life of radium 226 is 1602 years. If you have 500 grams of radium today how many grams would have been present 9612 years ago?

Step-by-step answer

P Answered by PhD

Answer: 7.8125 g
Explanation: Given:
Original amount (N₀) = 500 g
Number of half-lives (n) = 9612/1602 = 6
Amount remaining (N) = ?
N = 1/2ⁿ × N₀
N = 1/2^6 × 500
N = 0.015625 × 500
N = 7.8125 g

Chemistry

A magnesium chloride solution reacts with potassium phosphate solution to form a white precipitate.knowing that virtually all potassium compounds are soluble they dissolve in water,write the balanced equation for this reaction.include all subscripts

Step-by-step answer

P Answered by PhD

Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined as the chemical reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

The chemical equation for the reaction of potassium phosphate and magnesium chloride follows (look at the picture)

2 moles of aqueous solution of potassium phosphate reacts with 3 moles of aqueous solution of magnesium chloride to produce 1 mole of solid magnesium phosphate and 6 moles of aqueous solution of potassium chloride.
Answer: The product formed is potassium chloride.
Explanation:
Precipitation reaction is defined a