05.08.2022

If the hypotenuse of a 30°-60°-90° Triangle is 10√2, find the length of the other two sides.

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09.07.2023, solved by verified expert
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Let us consider a 30°-60°-90°△ABC right angled at B in which ∠C = 30⁰ and ∠A = 60⁰ with hypotenuse AC = 10√2 units.

Solution:-

In △ABC,

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38sin ∠C = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38sin ∠C = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38sin 30⁰ = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

In △ABC,

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38cos ∠C = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38cos ∠C = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38cos 30⁰ = If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38

Thus , the length of other two sides of triangles are 5√2 and 5√6 units.


If the hypotenuse of a 30°-60°-90° Triangle is, №18010901, 05.08.2022 06:38
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Faq

Mathematics
Step-by-step answer
P Answered by Specialist

Let us consider a 30°-60°-90°△ABC right angled at B in which ∠C = 30⁰ and ∠A = 60⁰ with hypotenuse AC = 10√2 units.

Solution:-

In △ABC,

\longrightarrowsin ∠C = \sf \dfrac{Perpendicular}{Hypotenuse}

\longrightarrowsin ∠C = \sf \dfrac{AB}{AC}

\longrightarrowsin 30⁰ = \sf \dfrac{AB}{10\sqrt{2}}

\longrightarrow\sf \dfrac{1}{2}= \dfrac{AB}{10\sqrt{2}}

\longrightarrow\sf AB = \dfrac{10\sqrt{2}}{2}

\longrightarrow\sf AB = 5\sqrt{2}\:units

\\

In △ABC,

\longrightarrowcos ∠C = \sf \dfrac{Base}{Hypotenuse}

\longrightarrowcos ∠C = \sf \dfrac{BC}{AC}

\longrightarrowcos 30⁰ = \sf \dfrac{BC}{10\sqrt{2}}

\longrightarrow\sf \dfrac{\sqrt{3}}{2}= \dfrac{BC}{10\sqrt{2}}

\longrightarrow\sf  BC = \dfrac{10\sqrt{2}\times \sqrt{3}}{2}

\longrightarrow\sf  BC = \dfrac{10\sqrt{2\times 3}}{2}

\longrightarrow\sf  BC = \dfrac{10\sqrt{6}}{2}

\longrightarrow\sf  BC = 5\sqrt{6}\: units

Thus , the length of other two sides of triangles are 5√2 and 5√6 units.


If the hypotenuse of a 30°-60°-90° Triangle is 10√2, find the length of the other two sides.
Mathematics
Step-by-step answer
P Answered by PhD

A)The angles are 30-60-90. The longest leg (hypotenuse) of the triangle is twice the shortest leg. The middle leg is the shortest leg times the square root of 3.

Step-by-step explanation:

The answer choice speaks for itself.

The legs of a 45-45-90 triangle have the ratios 1 : 1 : √2.

The legs of a 30-60-90 triangle have the ratios 1 : √3 : 2.

Clearly, the given leg lengths match the second set of ratios more closely:

10 : 17.32 : 20 ≈ 1 : √3 : 2.

Mathematics
Step-by-step answer
P Answered by PhD

A)The angles are 30-60-90. The longest leg (hypotenuse) of the triangle is twice the shortest leg. The middle leg is the shortest leg times the square root of 3.

Step-by-step explanation:

The answer choice speaks for itself.

The legs of a 45-45-90 triangle have the ratios 1 : 1 : √2.

The legs of a 30-60-90 triangle have the ratios 1 : √3 : 2.

Clearly, the given leg lengths match the second set of ratios more closely:

10 : 17.32 : 20 ≈ 1 : √3 : 2.

Mathematics
Step-by-step answer
P Answered by Specialist

Option A is right

Step-by-step explanation:

Given is a triangle (right angled) with other degrees as 30 and 60.

The length of hypotenuse = 30

We have to find the length of shorter leg.

We know that in a 30-60-90 triangle, the length of shorter side is always half the length of the hyptenuse.

In 30-60-90 triangle, opposite side of smaller angle/hypotenuse =1/2

Using the above we get

the shorter side = 1/2 (hypotenuse) = 1/2(30) = 15

Hence answer is 15

Mathematics
Step-by-step answer
P Answered by Specialist

Step-by-step explanation:

Indicates leg lengths of 1 and√3 and hypotenuse 2, the desired ratio is √3/2

Mathematics
Step-by-step answer
P Answered by Master

Option A is right

Step-by-step explanation:

Given is a triangle (right angled) with other degrees as 30 and 60.

The length of hypotenuse = 30

We have to find the length of shorter leg.

We know that in a 30-60-90 triangle, the length of shorter side is always half the length of the hyptenuse.

In 30-60-90 triangle, opposite side of smaller angle/hypotenuse =1/2

Using the above we get

the shorter side = 1/2 (hypotenuse) = 1/2(30) = 15

Hence answer is 15

Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Question 6)

sin Y= m

sin Y = m/1

So, hypotenuse is 1

Since sine is opposite over hypotenuse

So XZ= m and YZ = 1

Similarly, cos Y = k

cos Y = k/1

So adjacent side of angle Y is k

So XY = k

cos z - sin z = \frac{XZ }{YZ } - \frac{XY}{YZ}

cos z - sin z = \frac{m }{1 } - \frac{k}{1}

cos z - sin z = m - k

Question 7)

the relationship between sine, cosine, and tangent.

tan(x) = sin(x)/cos(x) = (11/61)/(60/61)

tan(x) = 11/60

Question 8)

Start with where the shorter leg is. It must be opposite the smallest angle.

In a 30 - 60 - 90 degree triangle you have the hypotenuse to be twice as long as the shortest side. You have to read that a couple of times to make sure you understand it. 

That being said, if the shortest side is x, the hypotenuse will be 2x.

Since in this case the shortest side is 11, the hypotenuse will be 2*11 = 22

The answer is 22

Mathematics
Step-by-step answer
P Answered by Master

Step-by-step explanation:

Question 6)

sin Y= m

sin Y = m/1

So, hypotenuse is 1

Since sine is opposite over hypotenuse

So XZ= m and YZ = 1

Similarly, cos Y = k

cos Y = k/1

So adjacent side of angle Y is k

So XY = k

cos z - sin z = \frac{XZ }{YZ } - \frac{XY}{YZ}

cos z - sin z = \frac{m }{1 } - \frac{k}{1}

cos z - sin z = m - k

Question 7)

the relationship between sine, cosine, and tangent.

tan(x) = sin(x)/cos(x) = (11/61)/(60/61)

tan(x) = 11/60

Question 8)

Start with where the shorter leg is. It must be opposite the smallest angle.

In a 30 - 60 - 90 degree triangle you have the hypotenuse to be twice as long as the shortest side. You have to read that a couple of times to make sure you understand it. 

That being said, if the shortest side is x, the hypotenuse will be 2x.

Since in this case the shortest side is 11, the hypotenuse will be 2*11 = 22

The answer is 22

Mathematics
Step-by-step answer
P Answered by PhD

For 1 flavor there are 9 topping

Therefore, for 5 different flavors there will be 5*9 choices

No of choices= 5*9

=45 

Mathematics
Step-by-step answer
P Answered by PhD

y=2x+15

where y=Value of coin

x=Age in years

Value of coin after 19 years=2*19+15

=$53

Therefore, Value after 19 years=$53

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